Kirat

[Solved] Storing content in a buffer [closed]

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[ad_1] I guess you’re looking for ArrayList. For example : ArrayList<String> listNodeContent= new ArrayList<String>(); //your code listNodeContent.add(current.getChild(“C”).getContent(0)); Then you can retrieve the content using different methods : ArrayList#get(int index), with an iterator (ArrayList#iterator()) or with a foreach loop : for(String tmp : listNodeContent){ System.out.println(tmp); } 6 [ad_2] solved Storing content in a buffer [closed]

[Solved] Save position of element with Jquery, PHP and MySQL [closed]

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[ad_1] I don’t know what do mean by “saving position of an element” and how can that be useful, but you can try jQuery position() and $.ajax() methods: Get the current coordinates of the first element in the set of matched elements, relative to the offset parent. var t = $(‘a.icon’).position().top; var l = $(‘a.icon’).position().left; … Read more

[Solved] Get text between 2 same symbols [closed]

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[ad_1] You are on the right track. Use the overload of IndexOf that takes a start index when you look for the second character: int first = picture.IndexOf(‘_’); int second = picture.IndexOf(‘_’, first + 1); string part = picture.Substring(first + 1, second – first – 1); [ad_2] solved Get text between 2 same symbols [closed]

[Solved] Bit / Byte Confusion on Binary Digits [closed]

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[ad_1] These days, the number of bits per character is not so simple but there are most definitely 8 bits per byte. The number of bits/bytes per character will vary depending on your system and the character set. Original ASCII was 7bits per character. That was extended to 8bits per character and stayed there for … Read more

[Solved] fixed divs inside container

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[ad_1] This is what it seems you want What you want is a sticky menu which requires javascript to find the current position of the page in the viewport and change the CSS or class to make it fixed. This is a bad example because there is no div that is made visible after you … Read more

[Solved] What is the use of multiple classes

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[ad_1] Reason 1 To make the code easier to understand. (Don’t underestimate how important easy to understand code is) Imagine this: class Student { public string First { get; set; } public string Last {get; set;} public int ID { get; set; } public string Street { get; set; } public string City { get; … Read more

[Solved] addition of positive and negative numbers

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[ad_1] The first println is trying to say I’m gonna sum numbers from 1 to 10 but be careful to add the even numbers as negative numbers So as the even numbers are negative, The code is trying to first check if it’s an even number by (j % 2 == 0) If it’s an … Read more

[Solved] Can’t use void() [closed]

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[ad_1] Try :- if (stringInput == “attack ennemy”) { cout << endl << “You dealt 100 attack points to: ENNEMY” << endl; ennemyHealthPoints = ennemyHealthPoints – attackPoints; **displayEnnemyStatus(ennemyAttackPoints, ennemyHealthPoints)**; } Instead of :- if (stringInput = attack ennemy) { cout << endl << “You dealt 100 attack points to: ENNEMY” << endl; ennemyHealthPoints = ennemyHealthPoints … Read more

[Solved] Why aren’t my values transferring over

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[ad_1] In your else block in actionPerformed you exit before reaching validate(). The problem is probably the following: You are adding the numOweLbl to your UI, but you never set the text of it to totalOwed. Before you do container.add(numOweLbl) you need to set its text. numOweLbl.setText(totalOwed) [ad_2] solved Why aren’t my values transferring over

[Solved] Javascript object sorting [closed]

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[ad_1] You can’t sort properties in an object. Copy the data into an array and sort it. Example: var arr = []; $.each(data, function(key, value){ arr.push({ id: key, data: value }); }); arr.sort(function(x,y){ var xn = x.data.userStatuINT; var yn = y.data.userStatuINT; return xn == yn ? 0 : xn < yn ? -1 : 1; … Read more

[Solved] What does “>” mean in jQuery and how to use it?

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[ad_1] $pages will be all immediate child divs of #main. If you have <div id=main> <div id=1> <div id=2></div> </div> <div id=3></div> <div id=4></div> <span id=5> <div id=6></div> </span> </div> Then $(‘#main > div’) will fetch 1, 3, and 4. If you did $(‘#main div’) then you’re finding all matching descendants, not just immediate ones, … Read more