Kirat[ad_1] The ValidationException has an errors() function that will list the validation errors. dd($e->errors()); should dump them out for viewing. 7 [ad_2] solved The given data was invalid. – how to know what was wrong?
[ad_1] some small confusing parts in your example. You can use the keyname “buy user_film” but i will not recommended. Because you may have some problems with it later. (e.g. dynamic key names.) key: buy user_film{[“”The Silence of the Lambs””,””fats and furiuos””]} You can have objects inside an array but not vice versa 3. film=JSON.parse(JSON.stringify(localStorage.getItem(“buy … Read more
[ad_1] From what I understand, you want to compare two arrays that might not be the same size, and if they are not, then only compare up to the shortest size? You can do something like this: boolean equals = true; for(int i = 0; i < test1.length && i < test2.length; i++) { if(!test1[i].equals(test2[i])) … Read more
[ad_1] import re naslov = “Tajkun (2020) onlajn sa prevodom” re.sub(“\([0-9]{4}\) onlajn sa prevodom”, “”, naslov) More about the re module. [ad_2] solved how can i delete certain words and numbers from a variable in python
[ad_1] This solution has very bad design… You do not know order of eveluating those flags. The issue I am assuming you are using cobra. So when you read documentation you will not find any part of how your flags are evaluated. So sometimes it is called undefined behavior and it may work but if … Read more
[ad_1] string = “casortdhgeujcode” key = “code” frequency = {} for c in key: frequency[c] = string.count(c) print(min(frequency.values())) 13 [ad_2] solved Find how many instances of a word can be made from the chars in a string [closed]
[ad_1] Can any one explain me the actual concept of Creating and Initialising an object in java?why a default constructor is used in initialising an object [closed] [ad_2] solved Can any one explain me the actual concept of Creating and Initialising an object in java?why a default constructor is used in initialising an object [closed]
[ad_1] You have an end on line 354 that I don’t think should be there, change this: break if guess>=7 i=i+1 end end to this: break if guess>=7 i=i+1 end 2 [ad_2] solved “Line 357: syntax error, unexpected kEND, expecting $end” [closed]
[ad_1] Print following commands in browser console and you can see diference: 1) Date.parse(“2013/05/29”) //return number of milliseconds between January 1, 1970 https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Date/parse 2) new Date(“2013/05/25”) //return DateTime object [ad_2] solved Difference between Date parse and differencing the date [duplicate]
[ad_1] First of all, sqrt(x) should be faster and more accurate than pow(x,0.5), why do you think it’s in the library? Second, you’re probably getting a wrong answer because your loop termination condition is testing a floating-point number. A tiny round-off somewhere in one of those 2 million loops is probably enough to throw off … Read more
[ad_1] You need to set the associations between models After that, it could look like this: @students = @user.students.all where @user = current_user I guess. Edit: To make it failsafe: @students = @user.students.all if @user To avoid later problems set user only when its not set by the controller e.g in a user view: @user … Read more
[ad_1] I’ll bite. This should work: var re = /(^\d{2}\.\d{4}$)/; (^ – begin \d{2} – match two digits \. – the period between digit sets \d{4} – match four digits $) – end And if you need the parantheses: var re = /(^\(\d{2}\.\d{4}\)$)/; jsFiddle 0 [ad_2] solved Regular Expression javascript for cip code [closed]
[ad_1] You can use \[.*?\]\{.*?\} on your example which I tested out here. This breaks into two smaller regex: \[.*?\], which is the square brackets with any chars inside. \{.*?\}, which is the curly brackets with any chars inside. Both of these are using a non-greedy .* inside the brackets. This way if there is … Read more
[ad_1] I have made an example for dynamically changing the selected value of a drop down menu here. <script type=”text/javascript”> window.onload = function() { BindEvent(); } function BindEvent() { var elemToBind = document.getElementById ( “cmb1” ); elemToBind.onchange = function () { SetSel ( this ); } } function SetSel(elem) { var secondCombo = document.getElementById ( … Read more
[ad_1] You should use preg_replace function. Example: $str=”var=104&anothervar=10&page=14&name=stack”; $str = preg_replace(‘/&?page=\d+&?/’, ”, $str); echo $str; &page=\d+? [&]? means 0 or 1 occurence of & character. (in case it was first parametr ampersand with no ampresand in the begining) \d+? means at least 1 or more number after = Output: var=104&anothervar=104&name=stack 9 [ad_2] solved Regular expression … Read more