[Solved] Crash : requires android.permission.READ_CALL_LOG or android.permission.WRITE_CALL_LOG On some devices

[ad_1] Issue was that if user already has an app without <uses-permission android:name=”android.permission.READ_CALL_LOG”></uses-permission> <uses-permission android:name=”android.permission.WRITE_CALL_LOG”></uses-permission> in manifest and gives call permission or phone permission , after update if these are added in update call/phone permission is still their but call log permission is not so you need to ask again. Fresh install was working fine … Read more

[Solved] how I can set color of anything in css [closed]

[ad_1] *{ color: #fff; background: #000; } Also you can use the inherit value which will inherit the values from the parent. body{ color: #fff; background: #000; } .inner_element{ color: inherit; background: inherit; } [ad_2] solved how I can set color of anything in css [closed]

[Solved] Change the index for DataGridView

[ad_1] Try this: private void button1_Click(object sender, EventArgs e) { Int32 rowIndex; try { rowIndex = dataGridView1.CurrentRow.Index; rowIndex = rowIndex + 1; } catch (Exception ex) { MessageBox.Show(ex.Message); } MessageBox.Show(rowIndex.ToString()); } Since you was calculating rowIndex = dataGridView1.CurrentRow.Index + 1; but finally printing dataGridView1.CurrentRow.Index. It should rowIndex.ToString() which has required result. [ad_2] solved Change the index for DataGridView

[Solved] What will be faster, >= or >? [duplicate]

[ad_1] Both comparisons will be compiled to machine instructions like BLT (branch on less than) or BLE (branch on less equal), which check some status bits like BLT: N-V + -NV (negative & not overflow or not negative and overflow) or BLE: Z + N-V + -NV (zero or negative & not overflow or not … Read more

[Solved] implementing a c# interface [closed]

[ad_1] you are throwing an NotInprementedException on the setter of the property. if you want automatic properties replace get { throw new NotImplementedException(); } set { throw new NotImplementedException(); } with get; set; 1 [ad_2] solved implementing a c# interface [closed]

[Solved] Convert ArrayString to Array android [closed]

[ad_1] try this String []aaaa = “[1000000062,1000000095,1000000058,1000000400]”.replace(“[“, “”).replace(“]”, “”).split(“,”); int aa[] = new int[aaaa.length]; for(int i=0; i<aa.length; i++){ aa[i] = Integer.parseInt(aaaa[i]); } 1 [ad_2] solved Convert ArrayString to Array android [closed]

[Solved] Dynamic memory allocation without brackets [closed]

[ad_1] struct struct_set { unsigned long long number; struct_set *next; }; Is linked list So there is not any need to write it as contiguous memory. for more Linked list As it is homework, do that by yourself [ad_2] solved Dynamic memory allocation without brackets [closed]

[Solved] Mesh aren’t displayed in their correct positions for a FBX model of multiple meshes

[ad_1] Locked. There are disputes about this answer’s content being resolved at this time. It is not currently accepting new interactions. According to the Transformations example code in Autodesk’s official SDK, a node’s global position in the world space is recursively calculated by the CalculateGlobalTransform(FbxNode* pNode) function as in the sample code below. Very important … Read more

[Solved] Java program to find the largest & smallest number in n numbers without using arrays

[ad_1] public static void main(String[] args) { int smallest = 0; int large = 0; int num; System.out.println(“enter the number”);//how many number you want to enter Scanner input = new Scanner(System.in); int n = input.nextInt(); num = input.nextInt(); smallest = num; //assume first entered number as small one // i starts from 2 because we … Read more

[Solved] check if item in array1 exist in array2 [closed]

[ad_1] If you have unsorted arrays with different lengths, this will work too. Create a function called intersect for example: function intersect(arr1,arr2){ //We need to know which array is the shortest to avoid useless loops if(arr2.length<arr1.length){ var temp = arr1; arr1 = arr2; arr2 = temp; } // Now, we are sure arr1 is the … Read more