Kirat[ad_1] This should match any of the specified characters and no others. /^[$0-9a-z+\-\/*]+$/ Note: the ‘-‘ character needs to be escaped in selection groups like this since it generally signifies a range of possible characters (i.e. a-z or 0-9). 3 [ad_2] solved Want regex for accepting $,0-9,a-z,+,-,/,*? [closed]
[ad_1] This is in no-way pretty, but it should work #include <stdio.h> void main(){ int size = 3,i; //you can’t just pass a value into main like that so I’ve initialised size here while (size){ //loop controlling line output i = 0; while (i++<size){//loop controlling * output within line putchar(‘*’);//output a * } putchar(‘\n’); //output … Read more
[ad_1] Yes you can. Unfortunately Java is not well suited for this task (for various reasons). I would suggest you buy an arduino set and learn what it can do regarding controlling devices and receiving input from sensors, so you know more about what is possible. 2 [ad_2] solved Java Programming real objects [closed]
[ad_1] String studId = “”; String firstName =””; String lastName =””; int number =0; int index = 0; StudentServiceImpl studServImpl = new StudentServiceImpl(); Scanner scan = new Scanner(System.in); do{ System.out.println(“1.Add Student:”); System.out.println(“2.Delete Student:”); System.out.println(“3.Display Students:”); System.out.println(“4.Exit”); System.out.println(); System.out.print(“Select number: “); System.out.println(); number=scan.nextInt(); if(number==1){ Student student = new Student(); System.out.println(“Enter Student No.”); studId = scan.next(); student.setStudId(studId); … Read more
[ad_1] A different argument: Your algorithm recurses until it “bottoms out” at fib(1) which returns 1. So you are getting the fibonacci number by doing (fibonacci number) calls and adding the 1s. So fib(n) is O(fib(n)). Binet’s Fibonacci formula can be written as fib(n) == int(0.5 + (phi ** n) / (5 ** 0.5)) where … Read more
[ad_1] Nothing, 1+1=2 will return an assignment error, alert someValue will return an identifier error. 3 [ad_2] solved Code Prediction [closed]
[ad_1] You might feel surprised to have received so many vote-downs. The reason is that you have not provided any information concerning what you have tried to solve the problem. Since you have not provided any specifics either, I’ll assume you want some basically structured data (e.g. JSON) to send/retrieve from server. Following code will … Read more
[ad_1] For Unity, you user either C# or UnityScript (A sort of JavaScript variant) for programming game logic, and Cg (Very similar to HLSL) for shaders. If you want to spend some money, though, you can also get node based programming tools (Sort of like Unreal Engine 4’s Blueprints) from the Unity Asset Store for … Read more
[ad_1] .btn{ border-radius:25%/100%; border:1px solid #000; background:#fff; padding: 8px 15px; font-size:14px; } .btn span{ font-size:10px; padding-left:5px; } <button class=”btn”>sometext <span>X<span> </button> [ad_2] solved HTML stylize a div like a rounded edge label
[ad_1] Assuming you have one thread: use sleep(timeout) – it will always wait timeout seconds before continuing. Assuming you have two threads: Option 1: Thread1 simply should wait and has nothing to do with Thread2 – use sleep(timeout) – it will always wait timeout seconds before continuing. Option 2: Thread1 does have something to do … Read more
[ad_1] For the first time in my years of programming, I’ve had to change an AJAX call to synchronous for it to work the way I wanted it. All that was needed was to add the “async: false” attribute to the AJAX call. This way the AJAX call is treated like any other synchronous function: … Read more
[ad_1] The reason this outputs 4 has to do with the size of each type and struct padding and alignment. On my system, sizeof(unsigned int) is 4, sizeof(long int) is 8, and sizeof(struct test) is 24. So to ensure that the 64-bit field lies on a 64-bit boundary, the structure is physically laid out like … Read more
[ad_1] The right way is this : aFlightList=aFlightList.Where(x=>airlines.Contains(x.AirCoNam1)).ToArray(); [ad_2] solved How to detect that one field of collection exist into another list with linq?
[ad_1] There are a lot of Google results that would show this but it would be something like JSONArray jsonArray = new JSONArray(“[{“Trip”:{“id”:”1″,”trip_start”:”2016-05-22 17:20:06″,”trip_end”:”2016-05-22 17:22:19″}}]”); JSONObject jsonObject = jsonArray.getJSONObject(0); JSONObject tripObject = jsonObject.getJSONObject(“Trip”); Log.d(“JSONResponse”, “ID: ” + tripObject.getString(“id”)); Hope this helps 5 [ad_2] solved Parsing json data.how can i parse this json data?
[ad_1] short answer: Yes you can use wrap() by default the $(‘.gap’) selector it look for .gap class in your HTML, if it found it, it wrap it into li element. demo: $(‘.gap’).wrap(‘<li></li>’) <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <span class=”gap”>…</span> Note dont use append() result will be <span class=”gap”>…<li></li></span> Edit: anyway <span class=”gap”>…<li></li></span> or <li><span class=”gap”>…</span></li> both of … Read more