[Solved] How does vector’s growth function work? [closed]

[ad_1] So how is the 10000th element stored here? The element isn’t stored in the vector. It’s ‘stored’ in a piece of memory that is unrelated to the vector. Isn’t the expected behavior here a “Segmentation fault”? No. The behaviour is undefined, so there is no behaviour to expect. But the above runs successfully. That’s … Read more

[Solved] histogram and pdf in the same graph [duplicate]

[ad_1] h<-hist(data, breaks=”FD”, col=”red”, xlab=”xTitle”, main=”Normal pdf and histogram”) xfit<-seq(min(data),max(data),length=100) x.norm<-rnorm(n=100000, mean=a, sd=b) yfit<-dnorm(xfit,mean=mean(x.norm),sd=sd(x.norm)) yfit <- yfit*diff(h$mids[1:2])*length(loose_All) lines(xfit, yfit, col=”blue”, lwd=2) 1 [ad_2] solved histogram and pdf in the same graph [duplicate]

[Solved] C# custom add in a List

[ad_1] I would use a HashSet<string> in this case: var files = new HashSet<string> { “file0”, “file1”, “file2”, “file3” }; string originalFile = “file0″; string file = originalFile; int counter = 0; while (!files.Add(file)) { file = $”{originalFile}({++counter})”; } If you have to use a list and the result should also be one, you can … Read more

[Solved] How can I resize the UIImage to specific size

[ad_1] Here’s how you can resize the image while preserving its aspect ratio. The code below is from a category for UIImage: + (UIImage*)imageWithImage:(UIImage *)image scaledToSize:(CGSize)newSize { float heightToWidthRatio = image.size.height / image.size.width; float scaleFactor = 1; if(heightToWidthRatio > 0) { scaleFactor = newSize.height / image.size.height; } else { scaleFactor = newSize.width / image.size.width; } … Read more

[Solved] Removing Capitalized Strings from Input File in Python3.4?

[ad_1] From the code it would appear that your file is really a csv file (your are reading the file with csv.reader). Assuming that this is the case, the following should work: def filtercaps(infilename,outfilename): import csv list_of_words=[] list=[] with open(infilename) as inputfile: for row in csv.reader(inputfile): list.append(row) for l in list: if len(l) == 0: … Read more

[Solved] program succeded in no error but this method is not working

[ad_1] prgBar.Show() Is this what you need? Did you forget to show the new form? EDIT: I’m answering to you comment… you need a static property to access the form from somewhere else: public partial class Form1 : Form { // This is you constructor (not shown in your sample code). public Form1() { InitializeComponent(); … Read more

[Solved] language for creating contract template [closed]

[ad_1] This question is probably going to get locked due to it being too broad, but if you are in BI you might want to consider something like Microsoft Lightswitch (http://blogs.msdn.com/b/bethmassi/archive/2011/12/01/beginning-lightswitch-getting-started.aspx). It makes it pretty easy to build form centered interfaces which sounds like what you are trying to do. 1 [ad_2] solved language for … Read more

[Solved] Need preview page before send email [closed]

[ad_1] Further to my comment, what I mean by splitting up the sendMail.php (you will, of course, have to modify your main page javascript to accommodate a confirm response from your sendMail.php): if(isset($_POST[‘data’]) && is_array($_POST[‘data’]) ) { foreach($_POST[‘data’] as $data) { } $datatList = implode(‘, ‘, $_POST[‘data’]); } else $datatList = $_POST[‘data’]; if(!isset($_POST[‘confirm’])) { $name … Read more

[Solved] IEnumerable Merge

[ad_1] I named your first model OldCategory. Query: var categories = new OldCategory[] { new OldCategory {CategoryId = 1, SubCategoryId = 2}, new OldCategory {CategoryId = 1, SubCategoryId = 4} }; var newCategories = categories .GroupBy(_ => new { Id = _.CategoryId, Name = _.CategoryName }) .Select(_ => new Category { CategoryId = _.Key.Id, CategoryName … Read more

[Solved] Difference between pre- and postfix incrementation in C (++a and a++) [duplicate]

[ad_1] Remember, C and C++ are somewhat expressive languages. That means most expressions return a value. If you don’t do anything with that value, it’s lost to the sands of time. The expression (a++) will return a‘s former value. As mentioned before, if its return value is not used right then and there, then it’s … Read more