Kirat[ad_1] Use backtracking. void print_all(char []ch,int maxLen){ for(int i=1;i<=maxLen;i++) backTrack(ch,i,0,new char[i]); } void backTrack(char[] ch,int len,int k,char[] ans){ if(k==len){ System.out.print(new String(ans,0,len)+”,”); return; } for(int i=0;i<ch.length;i++){ ans[k]=ch[i]; backTrack(ch,len,k+1,ans); } } 1 [ad_2] solved How to print out possible string with alphabet set and length? [closed]
[ad_1] This works for me. public class PersonService { protected int lastItemInPersonArray = 0; private Person[] persons = new Person[100]; public void addPersonToPersonArray(Person personToAdd) { persons[lastItemInPersonArray++] = personToAdd; } public static void main(String[] args) { PersonService ps = new PersonService(); ps.addPersonToPersonArray(new Person(“P 1”)); ps.addPersonToPersonArray(new Person(“P 2”)); ps.addPersonToPersonArray(new Person(“P 3”)); System.out.println(ps.persons[0].nome); System.out.println(ps.persons[1].nome); System.out.println(ps.persons[2].nome); } } class … Read more
[ad_1] Function takes input as country name and sends output as a comma separated values of firstLetter of all the states in that particular country [ad_2] solved Function takes input as country name and sends output as a comma separated values of firstLetter of all the states in that particular country
[ad_1] While this question is poorly worded, I think I understand what you are asking for. Here’s what you should do. I am not all that fluent in php so please make sure that you look over the code snippets that I write instead of copy/pasting them. Find the maximum X and Y values. Instantiate … Read more
[ad_1] First of all I must say your question was not very clear, it took me a while to figure out what you actually want to achieve. I hope I understand correctly. Without simply typing out the actual code you need, this is how I would approach it: I would create an array with dictionaries … Read more
[ad_1] Try: $(document).ready(function () { var $scrollingDiv = $(“#navbar”); $(window).scroll(function () { $scrollingDiv.stop() .animate({ “marginTop”: ($(window).scrollTop() + 0) + “px” }, “slow”); $scrollingDiv.css(“background-color”, (($(window).scrollTop() / $(document).height()) > 0.15) ? “orange” : “”); }); }); Demo 1 [ad_2] solved change div color after scrolling 15% down with jquery [closed]
[ad_1] The most obvious problem is your word count only has a single loop, but you need to scan every character in every movie – that suggests two nested loops. Then the idea of returning two types of information in a single array is ill-advised – a structure would be more appropriate. Then in C … Read more
[ad_1] It’s really unclear what the goal is here. Maybe this will help, consider the following code. $(function() { function cereal(id, name, like) { this.id = id; this.name = name; this.like = like; } const cereals = [ new cereal(1, ‘Captain Crunch’, ‘Yes’), new cereal(2, ‘Frosted Wheats ‘, ‘Yes’), new cereal(3, ‘Shredded Wheat’, ‘No’), new … Read more
[ad_1] function yymmddToString(yymmdd) { var months = [‘January’, ‘February’, ‘March’, ‘April’ …..]; var x = yymmdd.split(‘-‘); return months[parseInt(x[1], 10)] + ‘ ‘ + x[0]; } var result = data1.reduce(function(result, datum) { var x = result[datum.name] = result[datum.name] || {}; x[yymmddToString(datum.time)] = datum.value; return result; }, {}); 6 [ad_2] solved Converting an array object to another … Read more
[ad_1] After grepping some data into a variable i want to print only the variable is having some data otherwise i dont wabt to print [ad_2] solved After grepping some data into a variable i want to print only the variable is having some data otherwise i dont wabt to print
[ad_1] I have create JSON data through coding so don’t consider it just check the following answer /// Create dictionary from following code /// it just for input as like your code NSMutableDictionary * dict = [[NSMutableDictionary alloc] init]; NSMutableDictionary * innr = [[NSMutableDictionary alloc] init]; [innr setObject:@”red” forKey:@”Color”]; [innr setObject:@”01″ forKey:@”color_id”]; NSMutableDictionary * outer … Read more
[ad_1] Just get your a() method declaration out of the main : public class asdf { public static void main(String[] args) { a(); } static void a() { System.out.println(“asdfff”); } } 0 [ad_2] solved I get bugs in whatever i write on my editor using inteliJ in Java.(maybe an IDE problem?) [duplicate]
[ad_1] You should not use whitespaces in your column names. change public static String COLUMN_PRODUS = “Nume Produse”; into public static String COLUMN_PRODUS = “NumeProduse”; [ad_2] solved SQLiteLog: (1) near “Produse”: syntax error
[ad_1] I’m guessing the problem is that in your compiler char is signed (the standard allows it to be either signed or unsigned, it’s implementation-defined/specific). As such, whenever you convert chars that have bit 7 set to 1 (0x80 through 0xFF) into any larger integer type, it’s treated as a negative value and it gets … Read more
[ad_1] First of all instead of setting string = s simply loop through s as it is. Also, instead of looping through both s and vowels just loop s and check if the letter is in vowels, if so add a white space to string if not add the letter to string. Here is the … Read more