Kirat[ad_1] For onLongClick() returned value notify if the callback consumed the long click or not. It means that if you return true your callback will be last who serves the “Long click event”, else if you return false framework will looks for the next candidate who can serve the event, it can be some View … Read more
[ad_1] A simple regular expression: let sentence = “This is \”table\”. There is an \”apple\” on the \”table\”” let pattern = “\”[^\”]+\”” //everything between ” and ” let replacement = “____” let newSentence = sentence.replacingOccurrences( of: pattern, with: replacement, options: .regularExpression ) print(newSentence) // This is ____. There is an ____ on the ____ If … Read more
[ad_1] You need some sort of text mining library to do this and more specifically what you want to do it’s called tokenization: Each word in a string is categorized as a lexical token with a syntactical role e.g verb, pronoun etc. See tokenization and text mining for more info. There is a Javascript library … Read more
[ad_1] You need JSONP for cross-browser requests. The link you gave me works fine with getJSON jquery function. for streams: http://jsfiddle.net/82wNq/27/ for games: http://jsfiddle.net/82wNq/25/ $.getJSON(“https://api.twitch.tv/kraken/search/games?q=star&type=suggest&callback=?”, function (data) { $.each(data.games, function (index, item) { $(“<div>”).html(item.name).appendTo(“#content”); $(“<img>”).attr(“src”, item.box.medium).appendTo(“#content”); }); }); 1 [ad_2] solved Cross-Domain AJAX Call [duplicate]
[ad_1] Try this let d = new Date(); const monthNames = [“Jan”, “Feb”, “Mar”, “Apr”, “May”, “June”, ” July”, “Aug”, “Sep”, “Oct”, “Nov”, “Dec” ]; const d = new Date(); console.log(d.getHours() + “, ” + monthNames[d.getMonth()] + ” ” + d.getDate()); You can change monthNames to suit your needs. [ad_2] solved I need a specific … Read more
[ad_1] a -> b is the function type. It describes a function that takes a type a and returns a type b. >>= is the monadic bind function. It is of type Monad m => m a -> (a -> m b) -> m b. If you need to understand this, I recommend reading Learn … Read more
[ad_1] The inner loop will perform all of its iterations for each iteration of the outer loop. This is a case where you can test the behaviour yourself fairly easily, and generally it is faster to try these kinds of things out than to ask the question on here and wait for an answer. For … Read more
[ad_1] It would help to see your code for your implementation of the while loop to see what’s wrong, but the general solution for converting a for loop to a while loop is this: for(i=1;i<=2;i++) { /*your code*/ } becomes i = 1; while(i<=2) { /*your code*/ i++; } Make sure your iterators and decrementors … Read more
[ad_1] This is a data saver Icon that comes with the Android Oreo update: Verizon explanation [ad_2] solved What is this icon called in statusbar? [closed]
[ad_1] This might be slightly off as mysql dialect always throws me. Since B falls after A in an alphabetical sort, if you group on the ID and then select the maximum, it will give you all the B rows where they exist, otherwise you will get the A row. SELECT ID, MAX(alphabet) AS preference … Read more
[ad_1] If you cross join your Week and Student tables to get all combinations, and then use not exists to determine where no TimeSheet record exists. select W.WeekID, S.StudentID from [Week] W cross join Student S where not exists (select 1 from TimeSheet T where T.StudentID = S.StudentID and T.WeekID = W.WeekID); 0 [ad_2] solved … Read more
[ad_1] Several ways to do this, this is one: EDIT: my first solution gave a list for every value, but you only require a list when there is more than one value for a key. my_list = [‘key1=value1’, ‘key2=value2’, ‘key3=value3-1’, ‘value3-2’, ‘value3-3’, ‘key4=value4’, ‘key5=value5’, ‘value5-1’, ‘value5-2’, ‘key6=value6’] my_dict = {} current_key = None for item … Read more
[ad_1] If you look at the XPath in the error message, you will probably see what the issue is. Your text isn’t surrounded by quotes as is required, e.g. td[@area-label=November 2025] should be td[@area-label=”November 2025″] To fix this, you need to adjust your line of code to dp_month = driver.find_element_by_xpath(‘//*/td[@aria-label=”‘+month_label+'”]/div[contains(text(),”‘+ x_month +'”)]’) [ad_2] solved SyntaxError: … Read more
[ad_1] Seeing as this is a course header, I think students are supposed to include it and then use most of the standard library that way. I am surprised Stroustrup teaches it that way (it is, in my opinion, still bad practice), but it does mean that he has one less bit of syntax to … Read more
[ad_1] Based on the conditions you mentioned you can do something like below. Find the word count and then check is home available in the string and then find the index of the house . So then you can check does that index match to last index of the word array (count($wordArray)) – 1) $string1 … Read more