Kirat[ad_1] Maybe this is what you are looking for: SELECT * FROM products WHERE (product_type = “abc” AND (product_price >= 100 AND product_price <= 1000)) OR (product_type = “def” AND (product_price >= 2500 AND product_price <= 5000)) OR product_type NOT IN (“abc”, “def”) [ad_2] solved Is it possible to write this type of query with … Read more
[ad_1] You could splice the values and get only the first two elements as number. var array = [{ time: “18:00:00” }, { time: “10:00:00″ }, { time:”16:30:00” }], result = array.map(o => o.time.split(‘:’).slice(0, 2).map(Number)); console.log(result); .as-console-wrapper { max-height: 100% !important; top: 0; } If you have JSON sting, then you need to parse it … Read more
[ad_1] You are missing one + sign in the alert parameter: alert(“The string ” + fullName + ” is ” + fullNameLength + ” characters long.”); // ^ here You should write your code in some proper editor or IDE (webstorm, vs code, …). That way the editor will highlight those simple syntax errors for … Read more
[ad_1] A solution with a formula only: We assume that A1=1-3. Fill the following formula into A2 and copy it down. =IF(A1<>””,IF(ISNUMBER(A1),IF(A1+1<=VALUE(RIGHT(A$1,LEN(A$1)-FIND(“-“,A$1))),A1+1,””),VALUE(LEFT(A$1,FIND(“-“,A$1)-1))),””) The result will be 1 2 3 This works for any numbers devided by -. 1 [ad_2] solved Excel Number Separation [closed]
[ad_1] You can use this tool: https://www.smtpjs.com/ It allows you to encrypt your SMTP credentials when you call it so you don’t expose them to the client side. Include this script: <script src=”https://smtpjs.com/v2/smtp.js”></script> And then you can call the service like this: Email.send(“[email protected]”, “[email protected]”, “This is a subject”, “this is the body”, “smtp.yourisp.com”, “username”, “password” … Read more
[ad_1] There are quite a few npm packages out there to accomplish this, but one that is very popular is lodash.merge. Take a look at the lodash merge function: https://lodash.com/docs/4.17.4#merge This method is like _.assign except that it recursively merges own and inherited enumerable string keyed properties of source objects into the destination object. Source … Read more
[ad_1] Create a singleton named NavigationHandler and add the below functions to it: Function to open MainFragment: public void openMainFragment(FragmentManager fragmentManager, MainFragment fragment){ String backStackName = fragment.getClass().getSimpleName(); fragmentManager.beginTransaction() .replace(R.id.fl_main_container, fragment) .addToBackStack(backStackName) .commit(); } Function to open SubFragment: public void openSubFragment(FragmentManager fragmentManager, SubFragment fragment){ String backStackName = fragment.getClass().getSimpleName(); fragmentManager.popBackStackImmediate(backStackName, POP_BACK_STACK_INCLUSIVE); fragmentManager.beginTransaction() .replace(R.id.fl_main_container, fragment) .addToBackStack(backStackName) .commit(); } … Read more
[ad_1] why create object without “new” , i think it true that Typeface typeface = new Typeface();?[1]: https://i.stack.imgur.com/h9HqN.png [ad_2] solved why create object without “new” , i think it true that Typeface typeface = new Typeface();?[1]: https://i.stack.imgur.com/h9HqN.png
[ad_1] if (bigList[0][0] == ” “) This is true because the value of bigList[0][0] is also ” “, and the strings are compared by their value. Since they have the same value, the comparison is true. if (bigList[0] == smallList) This is true because bigList[0] points to the same object in memory as smallList does. … Read more
[ad_1] TL;DR Just use json.Unmarshal. You can wrap it lightly, using your transport, and call json.Unmarshal (or with a json.Decoder instance, use d.Decode) on your prebuilt JSON bytes and the v interface{} argument from your caller. Somewhat longer, with an example Consider how json.Unmarshal does its own magic. Its first argument is the JSON (data … Read more
[ad_1] In R, a vector (a in your question) can be subset with a logical index vector (b in your question). If the corresponding members are TRUE in the logical vector, the elements (of a) are retained. a = c (3, 4, 7, 8) b = c(TRUE, TRUE, FALSE, FALSE) a[b] #[1] 3 4 a[b] … Read more
[ad_1] it’s very simple if you use pseudo elements check the snippet .social { overflow: hidden; background: #333; padding: 10px 5px; text-align: center; } .icons { position: relative; display: inline-block; vertical-align: top; padding: 0 10px; /* you can use this padding for the space between icons and border */ } .icons:before { content: ”; position: … Read more
[ad_1] I would do something like this: private void startNewTimer(List<CountDownTimer> listOfTimers) { CountDownTimer countDownTimer = new CountDownTimer(1000,1000) { @Override public void onTick(long millisUntilFinished) { } @Override public void onFinish() { } }.start(); listOfTimers.add(countDownTimer); } private boolean cancelTimers(List<CountDownTimer> listOfTimers) { if(listOfTimers != null && !listOfTimers.isEmpty()) { for(CountDownTimer cdt : listOfTimers) { cdt.cancel(); } listOfTimers = null; … Read more
[ad_1] Use mobile hotspot from your phone just long enough for it to connect to at least one peer then switch back to your college wifi. If your college wifi is like mine then they are using a blocker that blocks bittorrent clients however I’ve found it only stops them from starting it won’t stop … Read more
[ad_1] You can use a number of CSS browser selector “hacks” by checking Browser CSS Hacks by Paul Irish. I’ve posted the available selectors below: Selector Hacks /* IE6 and below */ * html #id { color: red } /* IE7 */ *:first-child+html #id { color: red } /* IE7, FF, Saf, Opera */ html>body … Read more