Kirat[ad_1] In this case you are doing Wrong-: <TextView android:id=”@+id/scoreLabel” android:layout_width=”match_parent” android:layout_height=”50dp” android:gravity=”center_vertical” android:paddingLeft=”50dp” android:text=”Score : 300″ android:textSize=”18sp” /> We have only android:paddingLeft=”50dp” in android not something like android:paddingleft=”10dp” remove this it will compile then. [ad_2] solved Solve Compile error in Android Studio?
[ad_1] Your onCreate() has SQL syntax errors: String DATABASE_CREATE_FIRST =”CREATE TABLE IF NOT EXISTS”+ NAME_TABLE +”(” + KEY_NAME +TEXT_TYPE+ COMMA_SEP + KEY_HR+TEXT_TYPE+ COMMA_SEP + KEY_IBI +TEXT_TYPE+ COMMA_SEP+ KEY_HMIN+TEXT_TYPE+ COMMA_SEP+ KEY_HMAX+TEXT_TYPE+ COMMA_SEP+ KEY_IMIN+TEXT_TYPE+ COMMA_SEP+ KEY_IMAX+TEXT_TYPE+ COMMA_SEP+ KEY_BMIN+TEXT_TYPE+ COMMA_SEP+ KEY_BMAX+TEXT_TYPE+ COMMA_SEP+ “)”; No space between EXISTS and table name. Extra comma after last column specification. So: String … Read more
[ad_1] Problem is with if block in both method try: if(p[i]<min){ min=p[i]; custnum=i; } and if(p[i]>max){ max=p[i]; custnum=i; } store customer number who have min or max value.. 1 [ad_2] solved Cannot find the highest and lowest
[ad_1] After painstaking efforts and google search I found a solution to my problem. A page from Stackoverflow helped very much. First I changed the get method of my form to post like this <form action=”Upload” method=”post” enctype=”multipart/form-data”> Image<input type=”file” name=”image” id=”image” accept=”image/jpg”> <input type=”submit” value=”submit”> </form> Then I wrote the following servlet code. We … Read more
[ad_1] After splitting the string, you end up with an array of song names. That array has an undefined number of items inside so you cannot just reference abcd[0] and abcd[1] and expect to see all songs. You need another loop that will iterate through all your song names in variable abcd. Maybe I did … Read more
[ad_1] Didn’t tryed this, and I’m just guessing what you want to acomplish, but here it is: int[] arrayRow; int[] arrayCol; int[,] myArray = new int[Math.Max(arrayRow.Length, arrayCol.Length), 2]; for (int i = 0; i < arrayRow.Length; i++) myArray[i, 0] = arrayRow[i]; for (int i = 0; i < arrayCol.Length; i++) myArray[i, 1] = arrayCol[i]; [ad_2] … Read more
[ad_1] Yes, You can upload any image or file using AngularJs follow the below steps. Note here I am uploading the file to store in a folder and not to the database because it’s a bad idea to upload the file into the database instead of that store the file into folder and name of … Read more
[ad_1] You should use split(String) method of String class. Following is working code: public static void main (String[] args) { String val = “1123456@lopoa”; String[] vals = val.split(“@”); System.out.println(vals[0]); } Output: 1123456 See it working here [ad_2] solved “filed value” is coming like ‘1123456@lopoa’ format
[ad_1] Sure, there are many ways. Simplest: def func(alist): return zip(alist, alist[1:]) This spends a lot of memory in Python 2, since zip makes an actual list and so does the slicing. There are several alternatives focused on generators that offer memory savings, such as a very simple: def func(alist): it = iter(alist) old = … Read more
[ad_1] One slightly unrelated suggestion I have for your a==0 error check is to use a do while statement instead of having your program close. It would look like this: do { cout << “Enter a number for a: “; cin >> a; if (a==0) { cout << “Can’t use 0 for a.”; } } … Read more
[ad_1] Use instead ‘where’, ‘where in’ – where in allows You to serach in array. for example : Select id from member where parent_id IN (here array ($y) ) 0 [ad_2] solved make a query, get results make query again
[ad_1] c++ Making a code that displays equations and keep getting the “expression must have integral or unscoped enum type” error [ad_2] solved c++ Making a code that displays equations and keep getting the “expression must have integral or unscoped enum type” error
[ad_1] this.tooltip = this.renderer.createElement(‘div’); this.tooltipTitle.split(‘,’).forEach((text) => { this.renderer.appendChild(this.tooltip, this.renderer.createText(text)); this.renderer.appendChild(this.tooltip, this.renderer.createElement(‘br’)); var img2 = document.createElement(‘img’); // Use DOM HTMLImageElement img2.src=”https://stackoverflow.com/questions/54232501/image2.jpg”; img2.alt=”alt text”; this.renderer.appendChild(this.tooltip,img2); this.renderer.appendChild(this.tooltip, this.renderer.createElement(‘br’)); this.renderer.appendChild(document.body, this.tooltip); }); Another layout 5 [ad_2] solved Angular 4 adding an image before each new line using renderer
[ad_1] @kayal if you are still learning then this is good but sometime you should read the documentation here is the method that you can do this easily For Example Assuming Table name test +————+ | id | data | +————+ | 1 | {…} | +————+ suppose you have Model Test.php Then add a … Read more
[ad_1] There’s some confusion here regarding the term garbage characters. What it refers to is any byte that resides in a variable that wasn’t assigned in some well-defined way. The character A can be a garbage character if it happens to appear in (for example) a block of memory returned by malloc or an uninitialized … Read more