[ad_1] <?php$url = $_SERVER[‘REQUEST_URI’];$url_splitter = explode(“https://stackoverflow.com/”, $url);echo ‘<pre>’;print_r($url_splitter);?> Now you can access the variables by taking $url_splitter[0], $url_splitter[1],…. 1 [ad_2] solved Variables as www.example.com/var1/var2/ [duplicate]
[ad_1] I’d say you’d probably be looking at setting up a proxy on your local network, pointing the machines you want parental control on to that proxy, and filtering the “allowed” traffic by either: Checking website address against a predefined blocklist, and/or Reading through the HTML looking for naughty words or phrases. How to create … Read more
[ad_1] I can’t visualize the website cause I dont have Java x86 installed in this machine. “So I’m trying to make a growing navbar, where the menu fades in and is dropdown menu in landscape” Maybe another alternative to Javascript is using CSS3 Animation. Read following links: http://www.w3schools.com/cssref/css3_pr_animation-keyframes.asp http://www.w3schools.com/cssref/css3_pr_animation.asp Stopping a CSS3 Animation on last … Read more
[ad_1] You syntax is wrong. This is more what you need. for (int i=0;i<3;i++){ UIImageView *image=[[UIImageView alloc] initWithFrame:CGRectMake(i*50, 50, 250, 250)]; [self.view addSubView:image]; } However, this is not much use to you as your images are not referenced from anywhere so you can not populate or adjust them easily. 3 [ad_2] solved XCODE Obj-C add … Read more
[ad_1] I think you’re over complicating this. Just start at 0 and do powers of 10^((n-1)-i). Like so… int n = 4; // the number of elements in the arr. int sum = 0; for(int i = 0; i < n; i++) sum += (arr[i] * pow(10, (n-1)-i)); // here (n-1) = 3 std::cout << … Read more
[ad_1] Hi, im new to Java and im having trouble trying to figure out the problem with “case SCISSORS:” at the bottom can somebody help me:) [ad_2] solved Hi, im new to Java and im having trouble trying to figure out the problem with “case SCISSORS:” at the bottom can somebody help me:)
[ad_1] Get the Reference of this link. Go to format setting, where you find the following code the first argument is the number of character space you want, and the second is the output you want to print. System.out.format(“%4d”, i); System.out.format(“%3d”, j); System.out.format(“%3d”, k); System.out.println(); [ad_2] solved Values of for loops are not printing in … Read more
[ad_1] Load xml, traverse it (eg recursively), return tags with non-empty text. Here as generator: import xml.etree.ElementTree as ET def getNonemptyTagsGenerator(xml): for elem in xml: yield from getNonemptyTagsGenerator(elem) if len(xml) == 0: if xml.text and xml.text.strip(): yield xml xml = ET.parse(file_path).getroot() print([elem for elem in getNonemptyTagsGenerator(xml)]) Result: [<Element ‘field’ at 0x7fb2c967fea8>, <Element ‘text’ at 0x7fb2c9679048>] … Read more
[ad_1] Simple way is iterate and compare it. like below, I hope it may solve your problem int[] a = {1,2,2,3,4,3,5,5,7}; String b = “”; int count=0; for(int i = 0; i<a.length;i++){ for(int j=0; j<a.length;j++){ if(a[i]==a[j]){ count++; } } if(count>1){ count=0; b = String.valueOf(a[i]); }else{ count = 0; } } System.out.println(“last duplicate value : ” … Read more
[ad_1] To set a default value in a function you should do like in the code bellow and you don’t have to use str to convert x to a string, just send the string. def multiply(x,mult_int=10): return x*mult_int print(multiply(“I hope that’s not your homework.\n”, 2)) print(multiply(“Bye.”)) 1 [ad_2] solved The function should return the string … Read more
[ad_1] What you can do, is keep a list of usernames on the clients and server (give to new clients connecting), and then check if that username is in that list, if so then highlight the ping. The code I got was: function highlight(message){ if(message == “”) { return message } let mentions = message.match(/@\b([A-Za-z0-9]+)\b/g) … Read more
[ad_1] Try this: (df.join(pd.DataFrame( df[‘number’] .map(lambda x: range(1,x+1)).tolist()) .rename(lambda x: ‘C{}’.format(x+1),axis=1))) Output: number C1 C2 C3 C4 C5 C6 0 1 1 NaN NaN NaN NaN NaN 1 2 1 2.0 NaN NaN NaN NaN 2 3 1 2.0 3.0 NaN NaN NaN 3 4 1 2.0 3.0 4.0 NaN NaN 4 6 1 2.0 … Read more
[ad_1] Try using “$ django-admin startproject myproject”, the myproject should be the folder that contains your project. If that doesn’t work try checking this website: https://www.tutorialspoint.com/django/django_creating_project.htm And follow the steps. 1 [ad_2] solved How to create django project [closed]
[ad_1] Converting an object to a string will always implicitly call the ToString method, you cannot choose a different method. Implement your ToString method to return “true” or “false”: class YourClass { public override string ToString() { return “true”; // or return “false”; depending on your needs. } } You can call another method explicitly … Read more
[ad_1] This is an approach using Array.reduce() https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/reduce First I determine for each unique value in the array how many times it does occur, by returning an object like {“1”: 3, “2”: 3, “3”: 1} Then I determine which are the values occurred most of the times in the array, by returning an object like … Read more