First change the method signature to return a value: public static boolean checkUSPASS(String a,String b) Then return a value from within the method: return true; or: return false; Note that all code paths must return some value. So you have this in your try block: if (rs.next()) { return true; } else { return false; … Read more
just add a test : String firstWords = “”; if(splitVideoTitle.length>1){ firstWords = splitVideoTitle[0] + ” ” + splitVideoTitle[1]; } else firstWords=splitVideoTitle[0]; 0 solved Splitting a string caused ArrayIndexOutOfBoundsException [duplicate]
Let’s consider two ways to solve it that are two slow, and then merge them into one solution, that will be guaranteed to finish in milliseconds. Approach 1 (slow) Allocate an array v of size 2^16. Every time you add an element, do the following: void add(int s) { for (int i = 0; i … Read more
claim is not an array, but another object. If you want it to be an array, it should be something like this: “claim”: [ “date”: “2015-08-06”, “comments”: “Some comments” ] (notice the [ ] instead of { }) If it’s meant to be an object, then the code should read: JSONObject claims = c.getJSONObject(TAG_CLAIM); 4 … Read more
Not Possible Two problems: Where does the array end? In C, arrays are simply blocks of memory and do not have a length property. It is possible to read unpredictable numbers off the end of the array, from other portions of memory. In the posted code, sizeof(*arr) apparently is being used to get the length … Read more
Change your code from $query = “SELECT COUNT( id ) FROM scores WHERE id = $id;”; $result = mysql_query($query) or die(‘Query failed: ‘ . mysql_error()); to $query = “SELECT COUNT( id ) as `total_ids` FROM scores WHERE id = $id”; $result = mysql_query($query) or die(‘Query failed: ‘ . mysql_error()); after that you need $count = … Read more
You can use a function based on this formula: The basic formula for the frequencies of the notes of the equal tempered scale is given by fn = f0 * (a)n where f0 = the frequency of one fixed note which must be defined. A common choice is setting the A above middle C (A4) … Read more
I could not post it to comment section. Please see below: List<Integer> integers = Arrays.asList(1, 2, 3, 4); int i = 0; StringBuilder sb = new StringBuilder(“[“); for (int value : integers) { sb.append((i == 0) ? “” : (i % 2 == 0 ? “,” : “:”)).append(value); i++; } sb.append(“]”); System.out.println(sb.toString()); Output is: [1:2,3:4] … Read more
I would go by a string.split(” “).lastOption. But keep in mind that other blank chars may be used instead of space solved Scala. How get last word in String [closed]
Type is an instance of the String object, it has the method String#equals(…) and that method returns a boolean… “!” this is the negation opeator and inverts any boolean value… so !type.equals(“auto”) is a boolean condition as result from comparing whether the String var with the name type has the value “auto” . solved What … Read more
Is there another solution for this situation without using braces? That is the wrong question. The real question is: is there ever a reason to NOT use braces? NO. Just use braces. Your colleagues, and future-you, will thank you later. 1 solved Is this the most elegant/safe/recommended solution for this situation?
The solution you look for is rand() % 7 + 4 which will give you results from range [4, 10]. More general, for given min and max to obtain random value from [min, max] you go for rand() % (max – min + 1) + min 1 solved Error in using rand function [closed]
The proper syntax for this kind of for loop is for(String name : family) Instead of what you have for(String name = family) 1 solved (Java) How to loop through the content of an array? [closed]
Well, for one continuously querying for the same DOM objects is not only repetitive, but costly. You should always capture your query results with a variable. Doing this alone, will clean up your code: var $tlb = jQuery(‘#top-link-block’); NOTE: I suggest prefixing your JQuery result variable with a $ to remind you that it is … Read more
Let’s suppose we have a function like this: int change_char( char *str, const char a, const char b) { int n = 0; if ( str ) { while ( *str ) { if ( *str == a ) { *str = b; // Can I modify the value pointed by the pointer? ++n; } … Read more