[Solved] How can i scroll the page with img tag [closed]

[ad_1] $(window).load(function () { (function ($) { jQuery.fn.extend({ slimScroll: function (o) { var ops = o; //do it for every element that matches selector this.each(function () { var isOverPanel, isOverBar, isDragg, queueHide, barHeight, divS = “<div></div>”, minBarHeight = 30, wheelStep = 30, o = ops || {}, cwidth = o.width || “auto”, cheight = o.height … Read more

[Solved] Converting Pseudo Code To Python [closed]

[ad_1] You should try to code something before posing on Stack Overflow. This will work but won’t catch any error conditions. options = [ {‘vehicle’: ‘Car’, ‘destination’: ‘Ghana’, ‘coeff’: 0.3}, {‘vehicle’: ‘Van’, ‘destination’: ‘Nigeria’, ‘coeff’: 0.2}, {‘vehicle’: ‘Truck’, ‘destination’: ‘Togo’, ‘coeff’: 0.33}, {‘vehicle’: ‘Van’, ‘destination’: ‘Kenya’, ‘coeff’: 0.17}, {‘vehicle’: ‘Truck’, ‘destination’: ‘Somalia’, ‘coeff’: 0.31}, ] … Read more

[Solved] Java If command

[ad_1] As the Answer by NFE, and Niks Tyagi has showed, you Should to write: if (f.equals(“bif”)) { System.out.println(“BIF FAN”); } else { System.out.println(“Doesn’t Seem like a FAN”); } But if you want to do the second part too with the if expression, you can write like following. if (f.equals(“bif”)) { System.out.println(“BIF FAN”); } if(!f.equals(“bif”)){ … Read more

[Solved] Java Class Exception [closed]

[ad_1] Best practice is to make them separate classes in three different source code files. It is possible to have more than one class in a single source code file by using inner classes. However, I would advise against it in this case, because it would break best practice. And the compiler will still create … Read more

[Solved] c# finding different words in two texts [closed]

[ad_1] string text1 = “hello, world apple,pineapple,cabbage,apple”; string text2 = “hello, world,pineapple”; string pattern = @”\p{L}+”; var list1 = Regex.Matches(text1, pattern).Cast<Match>().Select(x => x.Value); var list2 = Regex.Matches(text2, pattern).Cast<Match>().Select(x => x.Value); var result = list1.Where(x => !list2.Contains(x)) .GroupBy(x => x) .Select(x =>new { Word = x.Key, Count= x.Count() }) .ToList(); This will return Word = apple, … Read more

[Solved] When to use blank parameters in Java? [closed]

[ad_1] You’d use them when you don’t need to give the constructor or method any data. In the case of your ArrayList it’s to make an empty array with a default capacity of 10 elements (OpenJDK implementation). As an abstract example, I can tell you to eat() but I don’t care what you eat, so … Read more

[Solved] Make inventory that receives purchased items from the shop system

[ad_1] You can use events to make your scripts “communicate” independently. First you need the gameevents. Make sure you have the script on a gameobject in your scene: using System; using System.Collections; using System.Collections.Generic; using UnityEngine; public class GameEvents : MonoBehaviour { public static GameEvents gameEvents; private void Awake() { gameEvents = this; } public … Read more

[Solved] Align item center and right [closed]

[ad_1] Basically, you’d need to use absolute positioning to take the buttons (I’ve wrapped them here for simplicity) out of the flow so the title can center. .parent { text-align: center; position: relative; border: 1px solid green; } h1 { display: inline-block; } button { display: inline-block; } .wrap { position: absolute; top: 50%; transform: … Read more

[Solved] C# Dynamic for-loop

[ad_1] It can be done without recursion. var s = “A,B,C|1,2|a|u,v,w”; var u = s.Split(‘|’).Select(v => v.Split(‘,’)).ToList(); var buffer = new List<string>(); buffer.Add(“COMMAND “); while (u.Count > 0) { var t = from a in buffer from b in u.First() select a + ‘ ‘ + b; buffer = t.ToList(); u.RemoveAt(0); } The buffer list … Read more

[Solved] Meaning of += sign [closed]

[ad_1] += is the concatenation equals operator. Often used to append and assign strings; var s=”Hello”; s += ‘ World’; console.log(s); // Hello World 1 [ad_2] solved Meaning of += sign [closed]

[Solved] I have around 1000 different activities in my Android App. How can I jump to a random activity?

[ad_1] Although this is terrible, I’ll still show a possible way to do this. But just remember, this is TERRIBLE. You can store all the activity classes in an ArrayList. ArrayList<Class<Activity>> activities = new ArrayList<> (); And then you add all the activities into the ArrayList. Yeah, I know, this part is tedious. For example, … Read more