[Solved] How can i scroll the page with img tag [closed]

$(window).load(function () { (function ($) { jQuery.fn.extend({ slimScroll: function (o) { var ops = o; //do it for every element that matches selector this.each(function () { var isOverPanel, isOverBar, isDragg, queueHide, barHeight, divS = “<div></div>”, minBarHeight = 30, wheelStep = 30, o = ops || {}, cwidth = o.width || “auto”, cheight = o.height || … Read more

[Solved] Converting Pseudo Code To Python [closed]

You should try to code something before posing on Stack Overflow. This will work but won’t catch any error conditions. options = [ {‘vehicle’: ‘Car’, ‘destination’: ‘Ghana’, ‘coeff’: 0.3}, {‘vehicle’: ‘Van’, ‘destination’: ‘Nigeria’, ‘coeff’: 0.2}, {‘vehicle’: ‘Truck’, ‘destination’: ‘Togo’, ‘coeff’: 0.33}, {‘vehicle’: ‘Van’, ‘destination’: ‘Kenya’, ‘coeff’: 0.17}, {‘vehicle’: ‘Truck’, ‘destination’: ‘Somalia’, ‘coeff’: 0.31}, ] while … Read more

[Solved] Java If command

As the Answer by NFE, and Niks Tyagi has showed, you Should to write: if (f.equals(“bif”)) { System.out.println(“BIF FAN”); } else { System.out.println(“Doesn’t Seem like a FAN”); } But if you want to do the second part too with the if expression, you can write like following. if (f.equals(“bif”)) { System.out.println(“BIF FAN”); } if(!f.equals(“bif”)){ System.out.println(“Doesn’t … Read more

[Solved] Java Class Exception [closed]

Best practice is to make them separate classes in three different source code files. It is possible to have more than one class in a single source code file by using inner classes. However, I would advise against it in this case, because it would break best practice. And the compiler will still create separate … Read more

[Solved] c# finding different words in two texts [closed]

string text1 = “hello, world apple,pineapple,cabbage,apple”; string text2 = “hello, world,pineapple”; string pattern = @”\p{L}+”; var list1 = Regex.Matches(text1, pattern).Cast<Match>().Select(x => x.Value); var list2 = Regex.Matches(text2, pattern).Cast<Match>().Select(x => x.Value); var result = list1.Where(x => !list2.Contains(x)) .GroupBy(x => x) .Select(x =>new { Word = x.Key, Count= x.Count() }) .ToList(); This will return Word = apple, Count … Read more

[Solved] When to use blank parameters in Java? [closed]

You’d use them when you don’t need to give the constructor or method any data. In the case of your ArrayList it’s to make an empty array with a default capacity of 10 elements (OpenJDK implementation). As an abstract example, I can tell you to eat() but I don’t care what you eat, so I … Read more

[Solved] Make inventory that receives purchased items from the shop system

You can use events to make your scripts “communicate” independently. First you need the gameevents. Make sure you have the script on a gameobject in your scene: using System; using System.Collections; using System.Collections.Generic; using UnityEngine; public class GameEvents : MonoBehaviour { public static GameEvents gameEvents; private void Awake() { gameEvents = this; } public event … Read more

[Solved] Align item center and right [closed]

Basically, you’d need to use absolute positioning to take the buttons (I’ve wrapped them here for simplicity) out of the flow so the title can center. .parent { text-align: center; position: relative; border: 1px solid green; } h1 { display: inline-block; } button { display: inline-block; } .wrap { position: absolute; top: 50%; transform: translateY(-50%); … Read more

[Solved] C# Dynamic for-loop

It can be done without recursion. var s = “A,B,C|1,2|a|u,v,w”; var u = s.Split(‘|’).Select(v => v.Split(‘,’)).ToList(); var buffer = new List<string>(); buffer.Add(“COMMAND “); while (u.Count > 0) { var t = from a in buffer from b in u.First() select a + ‘ ‘ + b; buffer = t.ToList(); u.RemoveAt(0); } The buffer list will … Read more

[Solved] Meaning of += sign [closed]

+= is the concatenation equals operator. Often used to append and assign strings; var s=”Hello”; s += ‘ World’; console.log(s); // Hello World 1 solved Meaning of += sign [closed]

[Solved] I have around 1000 different activities in my Android App. How can I jump to a random activity?

Although this is terrible, I’ll still show a possible way to do this. But just remember, this is TERRIBLE. You can store all the activity classes in an ArrayList. ArrayList<Class<Activity>> activities = new ArrayList<> (); And then you add all the activities into the ArrayList. Yeah, I know, this part is tedious. For example, activities.add … Read more