Here’s a fiddle with the solution: http://jsfiddle.net/h7Wda/7/ You basically check if number/1/phone is located in the href of the element: $(this).attr(‘href’).indexOf(‘number/1/phone’) Same for the number/3/phone case. Any other value will return false. 1 solved Search in text in link [closed]
1) Apple prefers that downloaded data be stored in the app’s Caches directory since the data can be replaced if it is deleted. 2) Yes, if a user deletes an app, all data stored in the app’s sandbox will be deleted. What would you expect to happen? 3) Use NSCachesDirectory. 4) /Users is not a … Read more
This is very bad practice, but because you asked for it: $str=”BCT34385Z0000N07518Z”; preg_match(‘/^(.{6})(.*?)$/’, $str, $result); echo $result[1]; // ‘BCT343′ echo $result[2]; // ’85Z0000N07518Z’ or if you want an if statement: $str = …; if (preg_match(‘/^BCT343/’, $str)) { // yes! } 2 solved Custom Regular Expressions [closed]
I can understand what a big difference developing on iOS is to Android so here’s the basics: In Android, you have activities, which is just a fancy way of saying pages or views. You have an XML layout file and a Java file which performs functionality tasks. In order to switch between activities you need … Read more
as you can see here, is working: http://jsfiddle.net/hCGu8/ CODE function a(){ var testMe = b(“hello”); alert(testMe); } function b(theVar){ var returnVar = theVar + ” returned”; return returnVar; } a(); 11 solved Return from on function to another javascript [closed]
You do not need to do anything in the XML file. This can all be done in a class. for(int i=0; i < x; i++) // where x is the size of the list containing your alphabet. { Button button = new Button(this); button.setId(i); yourView.add(button); } 1 solved ANDROID: How can I set up buttons … Read more
First you need to sibling your element with element, id or class: HTML : <div class=”rounded”></div> CSS : .rounded{ -webkit-border-radius:10px; -moz-border-radius:10px; border-radius:10px; } DEMO : http://jsfiddle.net/sq5Lmwrs/ You can also use border-radius left, right, top and bottom : https://developer.mozilla.org/en-US/docs/Web/CSS/border-radius Also you can use this link for generate what you want http://border-radius.com 1 solved how can i … Read more
select a.name as name,b.name as represon from table1 a inner join table1 b on a.code=b.rperson 0 solved How can I quickly solve this query? [closed]
Iteration 1 val is -10 if ((-10 < 0) && (+10 >= 40)) is false so it doesn’t break out of the loop * is printed loop condition: (-10 < 100) is true so the loop continues val is then updated: val = -val * 2 val = +10*2 = 20 Iteration 2 val is … Read more
It looks a bit bulky, I’d recommend you to rewrite it in the following way: SELECT User1.NAME,User1.PORT,User1.IP,File1.SIZE, FROM [User_File],[User1],[File1] WHERE [User_File].UID= User1.UID AND [User_File].FID=File1.FID and [User_File].FID = {0} and check if it runs without errors from your SQL Management Studio. solved What’s the problems on this sql command code? [closed]
Introduction This question is about a SQL command code and the problems associated with it. SQL is a powerful language used to query and manipulate data in databases. It is important to understand the syntax and structure of SQL commands in order to ensure that the code is written correctly and that the desired results … Read more
Files act like a long tape in a casette; you can read the file but by the time you are done you have passed the tape all the way to the end. Reading again won’t give you the data again. As such your second function tried to read data from a file that is already … Read more
Queues are most commonly used for scheduling and request handling applications. For example, anything where you have one process creating requests and another process handling the requests you would use a queue to hold the requests. Normally a queue is in FIFO order – requests are processed in the order they are received, but they … Read more
As Mark Baker pointed out, you’ll need to use something like Dijkstra’s algorithm to traverse a weighted graph (which is what you’ll have when you include distances). Here’s a simple distance function I found here: <?php /*::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::::*/ /*:: :*/ /*:: This routine calculates the distance between two points (given the :*/ /*:: latitude/longitude of those … Read more
It is hard to tell, but it looks like Python 3 is in use, and I suspect the book is requiring Python 2. If you can re-run the program with Python 2, you may find you have far fewer errors (if any). If you do have a new error, you can then ask a new … Read more