Running your code, put aside the code logic first, just to show the BMP image, you did not add the correct image path. You can try to add the absolute path of the picture. Like this: DrawBitmap(“C:\\Users\\strives\\source\\C.bmp”,x,y); //This is my picture path. Please enter your picture path correctly. Updated: I retested the code with MinGW, … Read more
Introduction This question is about a C++ code that is unable to display a bitmap. The code is from a textbook and is not working as expected. In this introduction, we will discuss the possible reasons why the code is not displaying the bitmap correctly. We will also discuss some possible solutions to the problem. … Read more
If you mean that you want to determine if a contiguous sequence of at least n (bytes of) characters match in two strings, you could do it like this (sliding window Google query): function haveSameNCharacters (length, str1, str2) { const [shorter, longer] = [str1, str2].sort(({length: a}, {length: b}) => a – b); if (length > … Read more
Try this: private bool ContainsOnlyOneLetter(string String) { if(String.Length == 0) { return true; } for(int i = 0; i < String.Length;i++) { if(String.Substring(i,1) != String.Substring(0,1)) { return false; } } return true; } And you can use the function like this: bool containsOneLetter = ContainsOnlyOneLetter(“…”); if (containsOneLetter == true) { //Put code here when the … Read more
You can use range() instead. l = list(range(1,100)) print(l) k = [] for i in l: if i%10==8: k.append(i) print(k) solved I have an error and due to lack of knowledge i dont no how fix this: “Traceback (most recent call last): File ““, line 8, in [closed]
Introduction If you are having trouble with an error and don’t know how to fix it, you are not alone. Many people have encountered similar issues and have found solutions. This introduction will provide an overview of how to troubleshoot and resolve the error you are experiencing. We will discuss the importance of understanding the … Read more
session_start() should be at the very top of your document and header() should only be executed before any output has taken place on the website. 1 solved PHP session variables wont work
<input type=”text” maxlength=”5″> 6 solved Is it posiible to stop user to enter value in textbox more than length of 5 at runtime in HTML? [closed]
Dump the database in windows Copy the files to linux Restore the database See https://docs.mongodb.com/database-tools/mongodump/ solved I want to move whole mongo databse to linux [closed]
The initializer of a static variable must be known at compilation time. That’s why the declaration of bin is rejected. Instead you need to declare bin as a pointer to an integer and allocate memory dynamically, that is at run-time: int *bin = malloc(size * sizeof *bin); As pointed out by rioV8, you should also … Read more
The answer to the question in the subject line: How do store sensitive files in my repo without tracking it? is: you don’t. The reason is simple: Git builds new commits from whatever is in Git’s index. The index, a.k.a. the staging area, holds the copies of files that will go into your next commit. … Read more
Something like this should do the trick: let getEnumDescription value = let fi = value.GetType().GetField(value.ToString()) let attributes = fi.GetCustomAttributes(typedefof<DescriptionAttribute>, false) |> Array.map (fun x -> x :?> DescriptionAttribute) if attributes.Length > 0 then attributes.[0].Description else value.ToString() Then you can call it like so: let red = Color.Red |> getEnumDescription let blue = Color.Blue |> getEnumDescription … Read more
Streams might not be the right tool for this task. Why not just add all elments from original list to new list and calculate how many new entries to add after finding the largest id? Something like: List<Fruit> newFruits = new ArrayList<>(); newFruits.addAll(fruits); int N = 10; int toAdd = N – fruits.size(); int maxId … Read more
You can use reduce to create the result and operator in to check if the key exists: const obj = {“John”:44,”Sarah”:23,”Bob”:43,”Kate”:65,”Bill”:18}; const keys = [‘John’, ‘Bob’, ‘Kate’, ‘Bill’, ‘Fred’]; const result = keys.reduce((acc, el) => { if (el in obj) acc[el] = obj[el]; return acc; }, {}); console.log(result); Another approach is to convert the object … Read more
You can generally turn a nested for loop that builds a list into a list comprehension by using the same exact for … in statements in the same order: list3 = [k for l in lst1 for k in lst2 if l == k[0]] list4 = [k for l in lst1 for k in lst2 … Read more