[ad_1] since you just want code it sounds like from operator import itemgetter sorted(map(itemgetter(1,-1),lists),key=itemgetter(-1)) heres some code that should do what you want … a teacher may want an explanation however… just fair warning [ad_2] solved Python: Sorting and printing lists within lists [closed]
[ad_1] Now as you can see in the comment in your question that you really need to be specific about where you are actually stuck in to ask a question in SO. However, after looking at your other questions in SO it looks like you are completely new in programming world and need serious helping … Read more
[ad_1] It’s optimization on level 3, basically a shortcut for several other options related to speed optimization etc. (see link below). I can’t find any documentation on it. … it is one of the best known options: https://gcc.gnu.org/onlinedocs/gcc/Optimize-Options.html http://docs.nvidia.com/cuda/cuda-compiler-driver-nvcc/#options-for-altering-compiler-linker-behavior [ad_2] solved What is option -O3 for g++ and nvcc?
[ad_1] As panta-rei correctly pointed out, it looks like you’re trying to contain a string of the form “string” + string form of (i) but you’re actually doing pointer arithmetic which is illogical in this case (you’re just passing a pointer incremented i from some location – who knows what’s in that memory?). In order … Read more
[ad_1] You need to convert the int to String using pointsAvailable.setText(“C”+String.valueOf(pointsAmount)); And to save the points, you need to store them in the SharedPreferences in onRewarded: saveCoins.edit().putInt(“C”,pointsAmount).commit() [ad_2] solved How to save and update points in a share preferences
[ad_1] create a string variable and append the html to it and do document.write for that variable. var output = “”; for (var i = 0; i < 11; i++) { output += “<tr><td>” + i + “</td>”; output += “<td>” + Classmates[i] + “,” + Emails[i] + “</td></tr>”; } document.write(output); 0 [ad_2] solved I … Read more
[ad_1] You can use itertools.groupby for this: >>> s = “aaaXXXbbbXXXcccXdddXXXXXeXf” >>> import itertools >>> sum(e == ‘X’ for e, g in itertools.groupby(s)) 5 This groups the elements in the iterable — if no key-function is given, it just groups equal elements. Then, you just use sum to count the elements where the key is … Read more
[ad_1] After the preprocessor runs, you’re left with: int main() { int girlsAge = (“14” / 2) + 7; printf(“%s can date girls who are %d or older.\n”, “Hunter Shutt”, girlsAge); return 0; } As you can see, “14” is a string, not a number. #define AGE 14 would fix it, but you’re better using … Read more
[ad_1] In your first program, you do i++ twice, and m++ once. So at the end of the first iteration, the values of i and m are equal (which is 2) – so in the next iteration i < m condition fails, and the loop exits. In the second case, you set the value of … Read more
[ad_1] You want to call a method, so you would have to add the parenthesis: myclass obj = new myclass(); obj.b = true; while (obj.notEnough()) { //Methods are always called by using the parenthesis () Thread.Sleep(5); } 6 [ad_2] solved How to use class method to stop loop? [closed]
[ad_1] You’re missing a closing brace to close this else block… else { _gaq.push([‘_trackEvent’, ‘Modals’, ‘skipped’, $(this).attr(‘name’)]); }); This is how it should be… else { _gaq.push([‘_trackEvent’, ‘Modals’, ‘skipped’, $(this).attr(‘name’)]); } }); [ad_2] solved Javascript error message ‘Uncaught SyntaxError: Unexpected token (‘ [closed]
[ad_1] You could add a simple splash activity to show the interstitial. After you are done with the interstitial, or after a delay you can navigate to your main activity. 2 [ad_2] solved displaying interstitial before app starts
[ad_1] Well, I found the problem, XCODE create the files here: /Users/[name]/Library/Developer/Xcode/DerivedData/[projectname]/Build/Product/Debug [ad_2] solved Write file with C++ [closed]
[ad_1] binaryNum = binaryNum & ~ (1u << 7) here binaryNum is your binary representation of number. 7(7 because it starts from 0) is the ith position where you wants to change. [ad_2] solved How to change 8th position no to 0 in a 32 bit integer
[ad_1] Try this: ([a-zA-Z0-9.-]+(?:@| AT | \(AT\) |_AT_)[a-zA-Z0-9.-]+.[a-zA-Z0-9._-]+) 10 [ad_2] solved Regular Expressions for JavaScript not normal emails [closed]