[Solved] Why doesn’t control enter the repeat() function? [closed]
// Thanks for the help #include <stdio.h> int repeat(int num) { scanf(“%d”,&num) ; if(num!=42) { printf(“%d”,num) ; repeat(num) ; } else { return num ; } getch() ; } int main() { int num ; scanf(“%d”,&num) ; repeat(num) ; return 0; } solved Why doesn’t control enter the repeat() function? [closed]