[Solved] CSS for text inside a ribbon/pennant type shape [closed]

[ad_1] There are multiple ways to do this. But you can split it in 2 separate shapes. Rectangular shape ( background of the text ) and a triangle using a pseudo element. See below Tweak around with the border values of the after element to achieve exactly the shape you want. span { position:relative; color: … Read more

[Solved] refactoring/making the code better in javascript [closed]

[ad_1] Yes, you should use switch statement here. Chaining so many else if’s is considered bad practice. You can read about switch statement here. https://www.w3schools.com/js/js_switch.asp Code would look something like: function likes(names) { if(names.length<0) { return `${names} likes this`; //return early if possible } let answer=””; switch (names.length) { case 0: answer = `no one … Read more

[Solved] Need to delete if block in file using python

[ad_1] The issue you are hitting here is that .readlines() reads line separated by a newline escape character (\n) and treats them as separate entries in an array – so your data contains: data == [‘if (aaaaa == b) {\n’, ‘qqqq\n’, ‘cccc\n’, ‘vvv\n’, ‘}’] If something isn’t working, run it through a debugger or print … Read more

[Solved] Get string line by line android programmatically

[ad_1] I think you can go for an approach like this. int clicks = 0; Button checkButton = (Button) findViewById(R.id.check_Button); checkButton.setOnClickListener(new View.OnClickListener() { public void onClick(View v) { EditText editBox = (EditText) findViewById(R.id.edit_Text); String items = editBox.getText().toString(); if (i == 0) { Toast.makeText(getApplicationContext(), items , Toast.LENGTH_LONG).show(); i++; editBox.setText(“”); } else if (i == 1) { … Read more

[Solved] how to check the range using only if statement

[ad_1] if you want to check the difference between two numbers, you need to subtract them. The result may be negative if the first number is smaller than the second, so you may want to use Math.abs() which will make it positive again. Then you have a positive number that you can check for being … Read more

[Solved] is there a way to have a “main” arraylist? [closed]

[ad_1] List<List<Citizen>> mainList= new ArrayList<>(); You can go with List of List. Also need to consider below points. I recommend using “List” instead of “ArrayList” on the left side when creating list objects. It’s better to pass around the interface “List” because then if later you need to change to using something like Vector (e.g. … Read more

[Solved] Event when onblur input jquery

[ad_1] The solution I’ve found : $(“#address”).on(‘blur focus’, function() { if (this.value==”) { $(‘#button_submit’).css(‘display’, ‘none’); } }); http://jsfiddle.net/np1wkh9p/17/ [ad_2] solved Event when onblur input jquery