[ad_1] Yes, with itertools product , map and set: >>> from itertools import product >>> A={1,2,3} >>> B={4,5,6} >>> list(map(set, product(A, B))) [{1, 4}, {1, 5}, {1, 6}, {2, 4}, {2, 5}, {2, 6}, {3, 4}, {3, 5}, {3, 6}] 1 [ad_2] solved How to get the cartesian product between sets in python without using … Read more
[ad_1] You might be interested in this project. https://github.com/redgeoff/mson MSON is a JSON language to describe forms and there is an example in React with Material UI. I have discovered it yesterday and didn’t test it yet. But it looks nice [ad_2] solved Build Dynamic form from JSON with Material UI
[ad_1] If you use the following code, response being your json: data = response[‘data’][‘students’] for student in data: print(‘{} {}:’.format(student[‘name’], student[‘lastname’])) for grade in student[‘grades’]: print(‘\t{} – {}’.format(grade[‘subject’], grade[‘score’])) This is what you’d get: Peter Henderson: math – A english – B Nick Simons: math – B english – C 0 [ad_2] solved how to … Read more
[ad_1] This question is quite unclear. But, I’m assuming you essentially just want to rotate an element around an arbitrary point on a HTML5 canvas. On a canvas, you can only draw one element at a time. You can’t really manipulate singular elements – for example, you can’t rotate an element by itself. Instead, you’d … Read more
[ad_1] You are not using the variables that you are defining(_index, _array are not being used anywhere in the code). So change it to this instead: allRejectedByPatient = survey.resultSent.every(function(element) { return (element.patientConfirmed === false); }); [ad_2] solved Disable JSHint warning for function: variable is defined but never used
[ad_1] If any more questions don’t doubt to contact me. Good luck. About createlist() Head should point to the first element of the list, but you are using head to instantiate the newest element added to the list. First and head conceptually are the same. I think you think head should be the last element … Read more
[ad_1] What it looks like right now is that you end up with just having 71008 in your first TextView because you loop through the keys but only ever access the first TextView. If you know that you’ll always have eight keys, in your case you can try adding them to your TextViews without the … Read more
[ad_1] I am trying to print numbers from 1 to 10 in sequential order with two different threads, but output is not always same [closed] [ad_2] solved I am trying to print numbers from 1 to 10 in sequential order with two different threads, but output is not always same [closed]
[ad_1] You can use Object.keys() to iterate over the keys of your first json object. Object.keys() returns a string array containing the key names. So we can call .forEach() on that result. In the foreach method we can use the key to access the child object in secondJsonObj. Object.keys(firstJsonObj).forEach(key => { if (secondJsonObj[key]) { secondJsonObj[key].value … Read more
[ad_1] Try something more like this: cout << “Please enter a number to search: “; cin >> n; out << endl; out << “Occasions during the year when there were three consecutive days where the temperature went above ” << n << ” are:” << endl; int firstday, numdays = 0; for (int x = … Read more
[ad_1] The correct answer I was searching for is: https://apidock.com/rails/ActionController/Base/url_for url_for(controller: ‘articles’, action: ‘show’, id: @article.id, protocol: :http) [ad_2] solved Convert url from https to http [closed]
[ad_1] You could use a regular expression: const addPort = (url, port) => url.replace(/^(https?:\/\/)?([^/]*)(\/.*)?$/, ‘$1’ + ‘$2:’ + port + ‘$3’); console.log(addPort(‘http://www.example.com/full/url/with/param’, ‘8080’)) 0 [ad_2] solved how to add substring into a string
[ad_1] Try this: var Items = string.Join(” , “, new[] {“1″,”2″,”3”}); ? 9 [ad_2] solved How can I get the AS3 array.toString behaviour in C#?
[ad_1] Asker Comment: 4 unique and 2 repetitive digits. But they should also have 3 unique and 3 repetitive digits, 2 unique and 4 repetitive digits in random number. Ok, I think I finally understand, so I have tweaked the algorithm to match every possible rule you’re expecting from 0 to 6 unique, though as … Read more
[ad_1] I modified the code to include the strings in single quotes. (R requires single or double quotes for strings. I used single quotes so as not to have to escape the double quotes.) Before <- ‘kzyFw4hw8EOC/655’ After <- ‘kzyFw4hw8EOC”https://stackoverflow.com/”655’ Using base R: gsub.method <- gsub(“https://stackoverflow.com/”, ‘”https://stackoverflow.com/”‘, Before) gsub.method == After # [1] TRUE or … Read more