[ad_1] Assuming you have a string of digits (e.g. “123”), you can use toCharArray() instead: for (char c : pesel.toCharArray()) { temp += 3 * (c – ‘0’); } This avoids Integer.parseInt() altogether. If you want to ensure that each character is a digit, you can use Character.isDigit(). Your error is because str.split(“”) contains a … Read more
[ad_1] You can use the function rand() : $str = str_replace(‘ ‘, rand(0, 10000), $str); Or did you mean a random value from your list? In this case: $list = array(“value1”, “value2”); $str = str_replace(‘ ‘, array_rand($list, 1), $str); 1 [ad_2] solved replace spaces with randam values [closed]
[ad_1] Here’s a recursive primality test function: int test_prime(unsigned n, unsigned d) { if (n < 2) { return 0; } if (d == 1) { return 1; } else { if (n % d == 0) { return 0; } else { return test_prime(n, d – 1); } } } Use it like: unsigned … Read more
[ad_1] If you use GCC for a compiler, you can use –save-temps which prevents the intermediate files (including the assembly output) from being deleted after it’s done. See http://gcc.gnu.org/onlinedocs/gcc/Debugging-Options.html [ad_2] solved assembler code of a fragment of C++ code [closed]
[ad_1] The docs are pretty clear Someone didn’t make any attempt at all. 1 [ad_2] solved bitbuckes and privacy [closed]
[ad_1] EDITED You must pass the instance of FrmA into the constructor of FrmMenu. In FrmA: private void Print() { FrmMenu ObjMain = new FrmMenu(this); ObjMain.Show(); } In FrmMenu: public FrmMenu(FrmA f2) { f2.CreateButtons(“NEW”); } 0 [ad_2] solved invoked function is not working in winforms [closed]
[ad_1] You could use GDI+ (and more specifically the Graphics class): // Load an existing image into a Graphics object using (var image = Image.FromFile(@”c:\work\input.png”)) using (var gfx = Graphics.FromImage(image)) { // Draw a line on this image from (0x0) to (50×50) gfx.DrawLine(new Pen(Color.Red), 0, 0, 50, 50); // save the resulting Graphics object to … Read more
[ad_1] You want to learn about character classes: [abc] matches a character that is either an a, a b or a c. [^abc] matches any character that is neither an a, a b nor a c. Together with quantifiers and start- and end-of-string anchors, you’re all set. ^[^X]*$ matches a string of any length that … Read more
[ad_1] JMeter uses Perl5-style regular expressions so the relevant regular expression would be: jobID\\”:(\d+) where: \ – escape character for the backslash () – grouping d – matches any digit + – non greedy match (don’t stop after first digit) See Regular Expressions chapter of JMeter User Manual for more information. You can test your … Read more
[ad_1] You’ll get a divide by zero error if u <= 0 in: vidmerginu = ms / m; because m is set to 0 and not incremented. And a divide by zero error if u >= 0 in: vidvaikinu = fabs(vs / v); because v is set to 0 and not incremented. [ad_2] solved C++ … Read more
[ad_1] If you want to write the results in a file, move FILE *f = fopen(“test”, “w”); into your main() function (also check return value since the function can fail), if you want the file format to be csv then you should add the extension .csv so that other people know it has that format … Read more
[ad_1] With a precision of two decimal places, determine the average number of guns for all battleships (including the ones in the Outcomes table) [ad_2] solved With a precision of two decimal places, determine the average number of guns for all battleships (including the ones in the Outcomes table)
[ad_1] It is named Exchange sort and is sometimes confused with bubble sort. While Bubble sort compares adjacent elements, Exchange sort compares the first element with all the following elements and swaps if needed. Then it does the same for the second element and so on. 0 [ad_2] solved What is this inefficient sorting algorithm … Read more
[ad_1] This code int∗ p = &a[2]; is equivalent to this: int∗ p = a + 2; so even mathematically you can see that p – a is equal to a + 2 – a so I think result should be obvious that it is equal to 2. Note name of array can decay to … Read more
[ad_1] ZoneId defaultZoneId = ZoneId.systemDefault(); String issueDate1=”01/01/2017″; Date issueDate2=new SimpleDateFormat(“dd/MM/yyyy”).parse(issueDate1); String dateTo1=”31/12/2018″; Date dateTo2=new SimpleDateFormat(“dd/MM/yyyy”).parse(dateTo1); here year month days can find easily.This giving ans of all question. Instant instant = issueDate2.toInstant(); LocalDate localDatestart = instant.atZone(defaultZoneId).toLocalDate(); Instant instant1 = dateTo2.toInstant(); LocalDate localDateend = instant1.atZone(defaultZoneId).toLocalDate().plusDays(1); Period diff = Period.between(localDatestart, localDateend); System.out.printf(“\nDifference is %d years, %d months and … Read more