Month: October 2022

[Solved] Convert an Array Object that is a String [duplicate]

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Your input is structured as JSON. You can thus simply use any JSON parsing method or library. For example JSON.parse(stringArray) (documentation). Here is a snippet which uses JSON.parse: var stringArray = “[[1,2,3,4],[5,6,7,8]]”; var parsedArray = JSON.parse(stringArray); $(‘#first’).html(parsedArray[0].toString()); $(‘#second’).html(parsedArray[1].toString()); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> First element: <span id=”first”></span><br> Second element: <span id=”second”></span> You can also use the eval function … Read more

[Solved] How to indicate the position in a class within an if statement? [closed]

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Change your onBindViewHolder method like this: ….. holder.itemView.setOnClickListener(new View.OnClickListener() { @Override public void onClick(View view) { // no neeed this condition //if (PizzaActivity.class != null){ if(position == 0){ Intent intent = new Intent(activity, Pizza1Activity.class); activity.startActivity(intent); } if(position == 1){ Intent intent = new Intent(activity, Pizza2Activity.class); activity.startActivity(intent); } if(position == 2){ Intent intent = new Intent(activity, … Read more

[Solved] Error :- String was not recognized as a valid DateTime

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Try this and tell me if it works and please change 06/31 to 06/30 june has only 30 days thanks this.Text=”30/06/2013″; DateTime date = DateTime.ParseExact(this.Text, “dd/MM/yyyy”,CultureInfo.InvariantCulture); 1 solved Error :- String was not recognized as a valid DateTime

[Solved] How to print a single backslash in python in a string? [duplicate]

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In IDLE (Python’s Integrated Development and Learning Environment), expression values have their representation echoed to stdout. As https://docs.python.org/3/library/idle.html explains: The repr function is used for interactive echo of expression values. It returns an altered version of the input string in which control codes, some BMP codepoints, and all non-BMP codepoints are replaced with escape codes. … Read more

[Solved] How to get index of array element in cell? [closed]

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Sorry if I’m understanding your English incorrectly, but I guess this is along the lines of what you want: You can get the indexPath of the row that was selected in a table by implementing tableView:didSelectRowAtIndexPath: in you tableView’s delegate (presumably your tableViewController). An indexPath has two properties you’ll be interested in; section and row. … Read more

[Solved] Python 3- assigns grades [duplicate]

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You defined your function to be getScore() but you’re calling getScores(), so as would be expected this throws an error because the function you’re calling doesn’t actually exist / hasn’t been defined. Addendum: Since you changed your question, after fixing the previous error. Likewise you’re calling grades, but grades is defined in your other function … Read more

[Solved] PHP reformatting array

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$currentKey = ”; $newArray = array(); foreach ($array as $val) { if (!is_array($val)) { $currentKey = $val; } else { if (isset($newArray[$currentKey]) && is_array($newArray[$currentKey])) { $newArray[$currentKey][] = $val; } else { $newArray[$currentKey] = array($val); } } } I hope you understand what is happening here? And of course it’ll work only with arrays like first … Read more

[Solved] Why does this Javascript script not give ant output?

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Avoid cascading of if’s var month = [“January”, “Feb”, “March”,….,”Dec”];//store array of months as string var suffix =[“st”,”nd”,”rd”,”th”]; var today = new Date(); var dd = today.getDate(); var mm = today.getMonth(); var yyyy = today.getFullYear(); var op=””; if(parseInt(dd) > 4) op+=dd+””+suffix[3]+”|”; else op+=dd+””+suffix[(parseInt(dd)%10)-1]+”|”; op+=month[parseInt(mm)]+”|”+yyyy; MAKE IT SIMPLE working fiddle FYI : just now saw the … Read more

[Solved] How do you put a User Name/Password in JSON format? [closed]

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You could try using the $.ajax method: $.ajax({ url: ‘/some_server_side_script’, type: ‘POST’, contentType: ‘application/json’, data: JSON.stringify({ username: $(‘#username’).val(), password: $(‘#password’).val(), }), success: function(result) { alert(‘success’); } }); In this example I have explicitly specified the Content-Type HTTP request header to application/json so that the server knows the exact content type being sent. I have also … Read more