If you want to get the average of the elements in a and b, you need to be summing those elements, not the elements of first. Also, you had an extra ; after if (avg1 > avg2), which was creating an empty body for that conditional, so return “first” was being executed unconditionally. function compare(a,b) … Read more
you need to convert the age to an integer use age = int(sys.stdin.readline()) that way the line you read from the input will be saved as an integer and will be of the right type to be compared to the integer 15 solved Comparison between str and int fails [duplicate]
Looks like I was talking rubbish when I said in a previous question: I had a quick look, and at first glance it doesn’t look easy enough that I can just write in a comment here. You can fix it simply by adding float: left to #logo. It’s yet another instance of IE7 dropping down … Read more
You may want to redesign how you define a card: enum Suit: String { case heart, diamond, club, spade } enum Rank: Int { case _1 = 1, _2 = 2, _3 = 3, _4 = 4, _5 = 5, _6 = 6, _7 = 7, _8 = 8, _9 = 9, _10 = 10 … Read more
The include method returns a boolean value. So your solution eliminates one of the steps, which is great. The old script didn’t work because you were trying to compare a boolean value to a string. You could take away your quotes on true and you would have come up with a working solution: if val … Read more
Not a code-writing service nor a tutorial. But for its simplicity’s sake, a possible solution could look like def count_down(n): return ‘, ‘.join(str(i) for i in range(n, 0, -1)) # return ‘, ‘.join(map(str, range(n, 0, -1))) >>> count_down(5) ‘5, 4, 3, 2, 1’ join, str, range are very fundamental functions/methods you should read up on … Read more
Make sure your <?xml tag is the first thing in the document (and that it doesn’t have anything before that, this includes whitespace). You can have <?xml only once per document, so if you have a large chunk of XML and you have this tag repeated somewhere down the lines your document won’t be valid. … Read more
This Bash script will: Set the source directory (SOURCE). Set the destination backup directory (BACKUP). Set the destination directory for latest full backup (LBACKUP). Get the current system date in Y-m-d-Time format (DATE). Sets the destination directory as BACKUP+/+DATE+-diff. Rsync/copy the files from the SOURCE to the DESTINATION folder by comparing the files from LBACKUP … Read more
You have to use event.stopPropagation() that stop the event propagation to the parent tree. Try the FIDDLE, As you have not provide the $get implementation, i have coded as a mock function like below function $get(idselector) { alert(‘$get’); return $(‘#’ + idselector); } function ABCDEF(event, object) { alert(‘ABCDEF’); event.stopPropagation(); // try commenting this will reproduce … Read more
main() is missing parentheses, and the statement is missing a semicolon. int main() { // ^^ cout << “*” << endl; // ^ } 2 solved Use Cout to create asterisk shapes (No Loops) [closed]
You could try the below code which uses word boundary \b. Word boundary is used to match between a word character and a non-word character. > library(stringr) > str_extract_all(x, perl(‘\\b(?:[35948]\\d{9}|TAM\\d{5}|E\\d{7}|A\\d{5})\\b’)) [[1]] [1] “3234567890” “5234567890” “9234567890” “4234567890” “8234567890” [6] “TAM12345” “E1234567” “A12345” solved Extract with Specific Prefix and control no. of digits in Regex- R
I’m quite sure this query will work; meaning that it won’t return an error but I’m not certain if it will return correct result as what you intended: SELECT s.Name, SUM(p.Note=5)/COUNT(*) as Anteil FROM Studenten s JOIN pruefen p ON p.MatrNr = s.MatrNr GROUP BY s.Name ORDER BY Anteil DESC, s.Name ASC; If this doesn’t … Read more
Running your code through the popular online c compiler here: http://www.tutorialspoint.com/compile_c_online.php Your code ran as expected. What happens when you type “.”? EDIT: (Solution) The problem was that when you input a negative number, a=”-” which has an integer value greater than zero, hence not triggering the negative case. The solution then, is to check … Read more
str converts the list into its string representation. Use map to convert each number in the list to str: lista = [1,2,3,4,9,5] print(“<“.join(map(str, sorted(lista)))) >>> 1<2<3<4<5<9 0 solved Can´t join a list the way I would like
Use this pattern instead (it looks for single digits): import re print(re.search(r’\b\d\b’, “I’m 30 years old.”)) Output: None This also works for Unicode characters in Python 3. To also account for punctuation, you can use \b\d(\b|\.|\?|\!) 3 solved regular expression to search only one-digit number