Month: October 2022

[Solved] retrieve contents of div and make image src

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[ad_1] You can simply do it in jQuery by getting the text of the div and then setting the source of image like this: var source = $(“#flag-name”).text(); console.log(“before – ” + $(“#image”).attr(“src”)); $(“#image”).attr(“src”,source); console.log(“after – ” + $(“#image”).attr(“src”)); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <div id=”flag-name” style=”hidden”>en-flag.jpg</div> <img id=”image” src=”https://stackoverflow.com/questions/48871589/DIV CONTENTS HERE”> 1 [ad_2] solved retrieve contents of … Read more

[Solved] getActivity() From Fragment to Fragment returning null

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[ad_1] adapter.setOnItemClickListner(new DailyMenuFrag()); The new DailyMenuFrag() here is a new fragment and it is not attached to any activity and hence getActivity() returns null. Looks like you should use adapter.setOnItemClickListner(this); instead to use the current DailyMenuFrag instance as item click listener. [ad_2] solved getActivity() From Fragment to Fragment returning null

[Solved] tokenizing and parsing with python

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[ad_1] To retrieve the data from the file.txt: data = {} with open(‘file.txt’, ‘r’) as f: # opens the file for line in f: # reads line by line key, value = line.split(‘ : ‘) # retrieves the key and the value data[key.lower()] = value.rstrip() # key to lower case and removes end-of-line ‘\n’ Then, … Read more

[Solved] Construct a game so that two random numbers appear and the user has to choose which one is bigger

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[ad_1] The simplest thing you can do is ask for the value of the biggest number, and compare it to the biggest number: biggest = max(a1, a2) user_num = int(input(“What is the biggest number?”)) if user_num == biggest: print(‘Correct!’) else: print(‘Wrong! The biggest number is {}’.format(biggest)) Note the use of int() for converting the input … Read more

[Solved] Sort date using lambda expression [closed]

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[ad_1] What you’re ordering by here is the distance between the pivot (the birthdate) and each date. Something like this: var sorted = data.OrderBy(date => (birthdate – date).TotalDays); will sort by distance, but put all the after dates first, because the TotalDays will be negative, then the before dates. To avoid that, we need to … Read more

[Solved] Javascript Append Link on Copy

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[ad_1] Try this. Whenever the length of the selection is less than 20 , the function will return the selection. <script type=”text/javascript”> function addLink() { var body_element = document.getElementsByTagName(‘body’)[0]; var selection; selection = window.getSelection(); if(selection.toString().length<20) { return selection; } var pagelink = “<br /><br /> Read more at: <a href=””+document.location.href+””>”+document.location.href+”</a><br />”; // change this if … Read more

[Solved] Add new user to database

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[ad_1] Your issue is simply syntax; you had a period instead of a comma at textBox1.Text+”‘.'”+textBox3.Text The other issue is that you need to use parameterized queries. Here is your code updated to use parameterization… private void button2_Click(object sender, EventArgs e) { Byte[] IMAGES = null; FileStream STREAM = new FileStream(IMGLOCATION, FileMode.Open, FileAccess.Read); BinaryReader BSR … Read more

[Solved] Javascript ECMA6 basic , variable is not defined in ajax

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[ad_1] So for anyone else coming here this is the working code. class ep_List { constructor() { this.urlForAjax =”; this.dataList=[]; this.dataJson=”; this.dataParams={}; } getData(method,params,url) { this.urlForAjax = url; this.dataParams=params; if(method==’get’) this.callGetAjax(); else this.callPostAjax(); } callPostAjax() { $.post(this.urlForAjax,this.dataParams,this.setList.bind(this)); } callGetAjax() { $.get(this.urlForAjax,this.setList.bind(this)); } setList(res) { this.dataList =res; console.log({dataList:this.dataList}); } } class gasFilter extends ep_List { displayList() … Read more