[ad_1] Change your code to this: String[][] content_split = new String[string_array.length][]; // create 2d array for (int i=0; i<string_array.length; i++){ content_split[i] = string_array[i].split(” : “); // store into array and split by different criteria } Which leaves you with a 2D array of your split content. [ad_2] solved Looping a string split from an array … Read more
[ad_1] You could do it like this: @Component({ selector: ‘my-app’, template: ` <div> <h2>Hello {{name}}</h2> <button (click)=”buttonClicked()”>{{ started ? ‘reset’ : ‘start’ }}</button> <br /> <span>{{ time.getHours() }}</span>: <span>{{ time.getMinutes() }}</span>: <span>{{ time.getSeconds() }}</span> </div> `, }) export class App { name:string; started = false; time = new Date(2000, 1, 1, 1, 0, 0); constructor() … Read more
[ad_1] Is this what you’re trying to say? If not, please specify how you mean further. This code should give you a number between 1-10 that hasn’t been already used. This code will only work 10 times. Random rnd = new Random(); List<int> usedNumbers = new List<int>(); public int RandomNum(){ int number; do { number … Read more
[ad_1] You need ClientID in javascript not the server id as asp.net will generate the new CliendID for server controls and the selector you have wont find element by that id. $(“#<%= RdbToday.ClientID %>”).change(function () { $(“#dateSelectorSpan”).hide(); }); $(“#<%= RdbDateRange.ClientID %>”).change(function () { $(“#dateSelectorSpan”).show(); }); Edit The code you have is working. Live Demo $(“#RdbToday”).change(function … Read more
[ad_1] The problem you’re experiencing is due to a misunderstanding of lists, list-references, and possibly the concept of mutability. In your case, you are binding the name user_data to a list object. In other words, user_data acts as a list-reference to the actual list object in memory. When you say user_list.append(user_data), all you’re doing is … Read more
[ad_1] Split on “,”. String st = “Tokyo, New York, Amsterdam” String[] arr = st.split(“,”); If st has ‘{‘ and ‘}’. You might want to do something along the lines of… st = st.replace(“{“,””).replace(“}”,””); to get rid of the ‘{‘ and ‘}’. 1 [ad_2] solved How to convert String into String Array in Java? [duplicate]
[ad_1] This happens because gather requires a name and value argument (supplied as strings, hence the error message. I imagine that supplying this would solve your problem. However, I strong encourage you to change from gather to the pivot arguments as gather has been retired. I think your code would work fine with pivot. Please … Read more
[ad_1] The C programming language is essentially a single-scan language – a compiler doesn’t need to reread the code but it can assemble it line by line, retaining information only on how identifiers were declared. The C89 standard had the concept of implicit declaration. In absence of a declaration, the function p1 is declared implicitly … Read more
[ad_1] Do you mean this? import math n = int(input(“Enter n: “)) i = 1 s = 0 while i <= n: s += 1/math.sin(sum(range(1,i+1))) i += 1 print(s) If you want to see each item during iterations import math n = int(input(“n = “)) i = 1 s = 0 while i <= n: … Read more
[ad_1] Using loops you could do something like this: public double Pow(double num, int pow) { double result = 1; if (pow > 0) { for (int i = 1; i <= pow; ++i) { result *= num; } } else if (pow < 0) { for (int i = -1; i >= pow; –i) … Read more
[ad_1] The only difference between println and print method is that println throws the cursor to the next line after printing the desired result whereas print method keeps the cursor on the same line. More information 4 [ad_2] solved System.out.print vs. System.out.println (Last sentence)
[ad_1] You can then apply a transformation to the result. df[‘mean’] = df[‘mean’].apply(lambda x: round(x)) or, if you want to truncate: df[‘mean’] = df[‘mean’].apply(lambda x: int(x)) 0 [ad_2] solved Can I change the dtype of mean function in Pandas? I want to change it to int type [closed]
[ad_1] Here is one way to solve the problem. It doesn’t hardcode any of the child node names (TI, MO, AU, etc.) so you could potentially use it on similar documents. I’ve put comments in the code so please read them and ask if you don’t understand what the code is doing. $txt=”your XML string … Read more
[ad_1] im trying to display the full name like the output did , but whenever i hit enter the program just print out 1 word rather than 2 word [ad_2] solved im trying to display the full name like the output did , but whenever i hit enter the program just print out 1 word … Read more
[ad_1] You get the Cross-thread error when you try to update a UI element from any thread it was not created on. Controls in Windows Forms are bound to a specific thread and are not thread safe. Therefore, if you are calling a control’s method from a different thread, you must use one of the … Read more