First, $email = filter_input(INPUT_GET, ’email’); does nothing it’s the same as $email = filter_input(INPUT_GET, ’email’, FILTER_DEFAULT);, and FILTER_DEFAULT is documented as “do nothing”. Second, PDO’s Query function does appear to support multiple statements (albeit in a rather annoying to use manner, and I can’t say I’ve personally played with it). PHP PDO multiple select query … Read more
It won’t be k-means anymore. K-means is variance minimization, and it seems your objective is to produce paritions of a predefined size, not of minimum variance. However, here is a tutorial that shows how to modify k-means to produce clusters of the same size. You can easily extend this to produce clusters of the desired … Read more
This is a math question and has nothing to do with ES. primary * (1 + replica) = primary + (primary * replica) 4 solved Elasticsearch what are the formulas to calculate total shards
The issue is that you need to assign self.title the correct date value. The line: self.title = NSDate() is assigning self.title to a new instance of NSDate(), while you want to assign it to the formatted date that you have above, convertedDate, which is also aString`. Additionally, NSDate() is of type NSDate and not of … Read more
in short, you have 3 main options: open a thread per client, that spawns after you accept(), and the run a loop in this context, that does read() => …. => write() run a main loop that uses select() on clients after accept() for each, and handle dispatching yourself. best option – use an async … Read more
You can declare multiple variables with one var statement but you have to close every command with an ; ! Its possible to leave it but i wouldnt (there are good examples out there: //not good but should work: var a,b function c(){} //the best solution: var a,b; function c(){}; //what you did var a,b,function … Read more
Add DisplayType = cmdType.SelectedIndex to the AddEntry Tried using a String Builder? StringBuilder sb = new StringBuilder(mainWindow.ChangeTextBox); foreach (AddEntry list in addedEntry) { sb.AppendLine(list.Type); if (list.DisplayType == 1) sb.AppendLine(“URL: ” + list.URL); if (list.DisplayType == 0 || list.DisplayType == 1) { sb.AppendLine(“User Name: ” + list.UserName); sb.AppendLine(“Password: ” + list.Password); } if (list.DisplayType == 2) … Read more
A function object is an instance of a class that defines the parenthesis operator as a member function. When a function object is used as a function, the parenthesis operator is invoked whenever the function is called. Consider the following class definition: class biggerThanThree { public: bool operator () (int val) { return val > … Read more
I want to skip index 0. How do I do that? Further I want to replace index 0 with something else. Just start the loop from 1 instead of 0 sportsArr[0] = “Something else”; // set the first element to something else for(var i = 1; i < sportsArr.length; i++){ // do something } solved … Read more
Here’s my best crystal ball guess at what you want. The keys of your dictionary are only a and b, which aren’t any characters in HelloWorld, but if you actually had characters from your string as keys like the following, this is how I’d do the replacement, assuming you want to rotate through the four … Read more
After newVector.insert(iter, 5), iter is not valid. That’s why insert returns an iterator. Your code should be iter = newVector.insert(iter, 5); 1 solved “Vector erase iterator outside range” error
How to capitalize a C string. #include <stdio.h> #include <ctype.h> int main() { int i = 0; char str[] = “foobar”; while(str[i]) { putchar (toupper(str[i])); i++; } return(0); } Test it online. solved Capitalizing a string in C
what is your folder structure?? if you calling css inside a folder “css” you must point out the correct path to custom fonts like this “../” src: url(‘../type/mercearia_new/21319b_0_0-mercearia.eot’); 3 solved Why Can I Not Implement @font-face?
The first step (reading in the csv) is pretty simple: data = read.table(“filename.csv”, sep = “,”, quote = “”, header=TRUE) The ‘sep’ part makes it clear that the separator is a comma, and ‘header’ keeps those column headings separate from the rest of the data. Does that work for you? -Y solved Using R – … Read more
without knowing what the code does: The statement will evaluate the first part (match(s1, s2 + 1)), and if and only if it is zero, evaluate the second part (match(s1 + 1, s2)). If the first part is not zero, it returns true (or 1) 0 solved return (a || b) utility?