A simple Google search for “DocuSign Dynamics CRM” gives you links about DocuSign for Microsoft Dynamics CRM 2013: http://www.docusign.com/partner/docusign-for-microsoft-dynamics-crm-2013 https://www.docusign.com/sites/default/files/Integrations/DynamicsCRM/DocuSign_for_Microsoft_Dynamics_CRM_2013.pdf https://www.docusign.com/sites/default/files/DocuSign%20for%20Dynamics%202013%20QS%20Guide.pdf solved docusign connector dynamics 2013
a = {:a => :b} b = {:b => :c} # Works on ruby >= 2.1 c = a.map{|k, v| [k, b[v]]}.to_h #=> {:a => :c} # Works on all versions of ruby c = Hash[a.map{|k, v| [k, b[v]]}] #=> {:a => :c} solved Ruby combine hashes? [closed]
GPA = Double.parseDouble(df.format (((double)qualityPoints) /(double)(sumOfHours))); int qualityPoints = 0; int sumOfHours = 0; double GPA = 0; DecimalFormat df = new DecimalFormat(“0.00”); GPA = Double.parseDouble(df.format (((double)qualityPoints) /(double)(sumOfHours))); No compilation error for this. 8 solved Converting String to Double in Java [closed]
Building on larsmans answer, a custom iterator can be built to do this: class my_large_num(object): def __init__(self): self.num_iterations = 0 def __iter__(self): return self def next(self): if self.num_iterations < 1: self.num_iterations += 1 return 10**200 else: raise StopIteration() You can then: import pickle pickled_repr = pickle.dumps(my_large_num()) restored_object = pickle.loads(pickled_repr) sum(restored_object) This works because underneath, iterable … Read more
The code behind this is very simple and designed for you to start on a blank sheet with Row 1 being your header row. It’s dynamic so essentially plug and play. Just call on the sub with whatever code you have for entering in the other data. Sub SerialCode() Dim ws As Worksheet Dim lastSerial, … Read more
If you want your own implementation you can filter your list of items and split it into subarrays based on how many items you want in one page. Below is an example code on how to achieve that. Example component’s contents: data() { return { currentPage: 1, itemsPerPage: 3, items: [{id: 1, title: ‘test1’},{id: 2, … Read more
You can do this using jquery: // get height of left summary and set right summary to the same on page load var summaryLeftHeight = $(“.summary-left”).height(); $(“.summary-right”).css(“height”, summaryLeftHeight + “px”); // add this to make sure they have the same height on page resize $(window).on(“resize”, function(){ var summaryLeftHeight = $(“.summary-left”).height(); $(“.summary-right”).css(“height”, summaryLeftHeight + “px”); }); … Read more
var elements = document.querySelectorAll(‘.currency, .excludeCurrency’); elements.forEach((item) => { new AutoNumeric(item, { allowDecimalPadding: “floats”, modifyValueOnWheel: false }); }); solved Conversion of jQuery code into Vanilla Javascript [closed]
Split method returns a string array, if you need both elements of this array, Try: string s = “FINAL PAYMENT $25”; string[] resArray = s.Split(‘$’); var FPayment = resArray[0]; var second25= resArray[1]; 5 solved How do I split a string with ‘$’ delimiter? [closed]
list1 is a list that contains 1 element that is an numpy.array that contains multiple floats64. list2 is list that contains 1 element that is a list that contains multiple strings (that happen to look a lot like floats). You can convert them like so: import numpy as np # list of list of strings … Read more
The expression “cake” || “Cake” evaluates to true, because both those strings are truthy. So when user’s input is compared with that value, for example “cake” == true, it evaluates to true because the user’s input (“cake”) is also truthy. To ignore the case of user’s input, you can simply convert it to lowercase (by … Read more
From your question name = input(“What is your name: “) age = int(input(“How old are you: “)) year = str((2014 – age)+100) print(name + ” will be 100 years old in the year ” + year) Your code is just fine, change your input to raw_input for name variable. NOTE: raw_input returns a string, input … Read more
The select statement chooses a case whose communication op would not block. If there are multiple cases whose comm. op would not block, one is chosen randomly. Since in the example all communication ops would block, and since a default is provided, that will be executed. To “trigger” another case, you have to make sure … Read more
As zipa pointed out, you never break your while loop in the else statement on line 146 unless you run out of tries. A one line “fix” is to simply put an exit() after line 98 within the traverse() function. 3 solved Udacity python code a quiz [closed]
You can separate each target section of the string into an array using split. Then iterate through the array and do your count. my $string = ‘AAAAaaa>1BBbbbbbbb>2CCCCCCCCccccc>3DDDDDDDDDddd>4FFFFfffffff>’; my @targets = split(/(?=\d+\w+>)/, $string); my $successes = 0; foreach my $target (@targets){ my $target_lc = $target =~ tr/a-z//; my $target_uc = $target =~ tr/A-Z//; if($target_lc > $target_uc){ … Read more