Using vanilla JavaScript (no libraries): //We attach a click handler on the nearest common parent. //This allows us to have only one event handler, which is better //For performance! document.getElementById(“parent”).onclick = function(e) { //We only want events on the spans, so let’s check that! if (e.target.tagName.toLowerCase() == “span”) { this.style.backgroundColor = “#BADA55”; //This is for … Read more
Here is a very basic Slideshow-from-PHP application. It can easily be modified or built upon. Image names (file_name) are pulled from the database, then pushed into a JavaScript array of image src values. Make sure you also specify the images directory (where the images are actually stored) to match your own. A simple image preloader … Read more
We can group by ‘A’, ‘B’ and select the first non-NA element across other columns library(dplyr) df1 %>% group_by(A, B) %>% summarise(across(everything(), ~ .[order(is.na(.))][1]), .groups=”drop”) -output # A tibble: 1 x 8 # A B C D E F G H # <chr> <chr> <int> <int> <int> <int> <int> <lgl> #1 time place 1 2 … Read more
You can use itertools to do this: from itertools import permutations strings = [‘a’,’b’,’c’,’d’,’ab’,’cd’,’abc’] all_combin = [s for i in range(2,len(strings)+1) for s in permutations(strings,i)] # List of all possible combinations of letters from the list num = [] for n in all_combin: if ”.join(n) == ‘abcd’: a=”” for l in n: a += str(strings.index(l)+1) … Read more
You could pipe into jq -s .: for …. ; do … ; done | jq -s . solved How do I merge all the outputs from for loop into single json using jq
This looks like target membership issue. I suggest that look at the target membership of Player.swift and make sure that the check mark next to your project name is there. How to verify target membership Click on the file Open the Utility Pane (The right pane on Xcode) (option + command + 0) Navigate to … Read more
Make a bash script. LOGIC: Use netstat -natp (filter it through awk/sed to get the ports, then grep it) Then use a simple test to see if the result was empty. Run curl if it was. Put this in a cron job. Simple stuff, really. EDIT: netstat is a utility which will show you all … Read more
My instinct was to do something similar to Karthick’s answer, however I first took a look at the output of Import-Csv. Surprisingly it puts the line break in the individual property where it was found like: Import-Csv C:\temp\Broken.csv | fl EmpId : 1 EmpName : Jack EmpLocation : Austin EmpId : 2 EmpName : Pet … Read more
column += 1 can not be used in the way you are using it because it is a statement rather than an expression. What you are writing is equivalent to self.test1 = input[column = column + 1] which doesn’t much sense. Instead you would need to do: column += 1 self.test1 = input[column] or self.test1 … Read more
You just need to change the return type to 2-D array: func test() -> [[Any]] { 0 solved How to display Any items? [closed]
It depends on the type that employee.getdate_of_birth() returns. If its a LocalDate, you can do employee.getdate_of_birth().plusYears(maxage). There are similar methods for days, months and seconds. 7 solved How to add 25 years(integer variable) to a date field in java [duplicate]
When the interpreter runs the line .innerHTML=”LIVES: ” + removeLives();, removeLives will be called, resulting in lives being decremented and the new content there being lower. Put that line inside the click handler instead, and initially populate the lives div via the HTML. Also, either use an inline handler in the HTML or .onclick in … Read more
Yes, you can have multiple: namespace A {}; namespace B {}; And nested: // Pre C++17 namespace A { namespace B {}; }; // C++ 17+ namespace A::B {}; solved Can we have more than one namespace in a library (in c++)
To do this, you can use slice on the array (assuming it’s an array — using {} is for objects, which isn’t valid for this). args = [“!say”, “pineapples”, “are”, “cool!”] // As an array console.log(args.slice(1)); // To string console.log(args.slice(1).join(” “)); solved args and up? javasript
To find the average in the given array and find the number which is closest to the average, public static void main(String[] args) { int array[] = new int[] { 1, 2, 3, 4, 5, 6, 7, 8 }; int sum=0; double avg; for (int i = 0; i < array.length; i++) { sum += … Read more