[ad_1] Edit: This only addresses the second portion of the question. To disable a control try setting enabled to false. btnCheckAnswer.Enabled = false; 3 [ad_2] solved c# If else if statement event triggers before else if does
[ad_1] [*] Use a negative lookahead assertion: r’\b[a-z][*]{2}1(?!\d)’ The (?!…) part is the lookahead; it states that it cannot match at any location where a digit (\d) follows. Regex101 demo; note how only the second line is matched (blue). Python demo: >>> import re >>> pattern = re.compile(r’\b[a-z][*]{2}1(?!\d)’) >>> pattern.search(‘x**1’) <_sre.SRE_Match object at 0x10869f1d0> >>> … Read more
[ad_1] Try removing any stripslahes(). Stripslashes removes any backslashes and forward slashes. For example, line breaks are being sent as \n or \r and the stripslashes() takes away the backslashes in those, so that’s why it says ‘rn’. I had this very problem, and this solution helped me. Good luck! 1 [ad_2] solved Line break … Read more
[ad_1] Just check where you are in your loop to know if you need to print the comma. public static void Test() { for (int i = 49; i >= 1; i–) { Console.WriteLine(i + (i != 1 ? “,” : “”)); } Console.ReadLine(); } [ad_2] solved Loop to write a cimma separated list of … Read more
[ad_1] Remove hash from <li id=’#myElement’>. Correct syntax is : <li id=’myElement’> $(‘#myElement’).on(“click”, function() {… Then $(‘#myElement’).off(“click”) // or $(‘#myElement’).css(‘pointer-events’, ‘none’); will both work (but not ‘pointer-evenet’)… Demonstration : $(‘#myElement’).on(“click”, function() { alert(‘Hello world’); }); $(‘#myElement’).css(‘pointer-events’, ‘none’); // or : // $(‘#myElement’).off(“click”); <script src=”https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js”></script> <li id=’myElement’> <a href=”#”>Click here</a> (nothing should happen) </li> [ad_2] solved … Read more
[ad_1] Change getDetails() method by this // $this->session->userdata[‘id’] to this code $this->session->userdata(‘id’) public function getDetails() { $st = $this->db->SELECT(‘cursadas.date as date, cursadas.grade as grade, usuarios.username as user, materias.name as subject’)->from(‘cursadas’) ->join(‘usuarios’,’usuarios.id=cursadas.user_id’) ->join(‘materias’,’materias.id=cursadas.subject_id’) ->WHERE(‘cursadas.user_id=’,$this->session->userdata(‘id’)) ->get()->result_array(); return $st; } see the link for more info https://www.codeigniter.com/user_guide/libraries/sessions.html#retrieving-session-data 3 [ad_2] solved Error after loggin out
[ad_1] Node.js is a platform for the JavaScript language that is centered around asynchronous network programming. It contains a set of libraries to help you develop server-side applications with JavaScript Under the hood, Node.js is running on V8, a JavaScript engine developed by Google. Hope this helps. 1 [ad_2] solved What is the node.js and … Read more
[ad_1] From the man page: The realloc() function changes the size of the memory block pointed to by ptr to size bytes. So instead of: int *newbuffer = (int*) realloc (stacky, size); you probably want int *newbuffer = (int*) realloc (stacky, size * sizeof(int)); BTW: No need for cast when using malloc and friends. See … Read more
[ad_1] One popular convention for ids and class names is to use hyphens, like this: id=”cust-name”. This stems from the fact that CSS selectors are case-insensitive. 1 [ad_2] solved Do you name classes and ids as headless camel case?
[ad_1] The operating system stops running the thread receiving the signal and runs the signal handler. When it returns the original thread restarts where it was. If the signal handler is already running when another signal comes in, the action is configurable in the sigaction call. [ad_2] solved How are signals handled in Unix?
[ad_1] You want to traverse the dictionary, building the current key and accumulating the flat dictionary. For example: def flatten(current, key, result): if isinstance(current, dict): for k in current: new_key = “{0}.{1}”.format(key, k) if len(key) > 0 else k flatten(current[k], new_key, result) else: result[key] = current return result result = flatten(my_dict, ”, {}) Using it: … Read more
[ad_1] When i is 1, you print it with the printf statement. Then i gets incremented (via the ++ operator in your printf statement). Then i /= 2 is performed, which results to i = 2 / 2 which results to 1. This satisfies your condition i >= 1, making it an infinite loop. [ad_2] … Read more
[ad_1] InputStream is parent class of all input streams and readers. Classes that have Stream keyword will work with bytes whereas classes which have Reader keyword will work with characters. Buffer is wrapper around these streams to decrease the system calls and increase performance and speed of reading. Non buffered streams return single byte each … Read more
[ad_1] The first one is much cleaner and easier to read. C# coders will be used to seeing it done that way. [ad_2] solved best approach check string null and empty C# [closed]
[ad_1] A statement such as points.add(new Point(2,3)); must be inside some method/constructor. [ad_2] solved I get an error when i try to add a new point into my ArrayList