At least this statement array->values = realloc(array->values, array->capacity); shall be rewritten like array->values = realloc(array->values, array->capacity * sizeof( Value ) ); Though it would be more safer to use an intermediate pointer like for example Value *tmp = realloc(array->values, array->capacity * sizeof( Value ) ); if ( tmp != NULL ) { array->values = tmp; … Read more
The function is not updating the caller’s value of client_details, you need one more level of pointer: void func(struct client_detail **client_details,int *size){ *client_details = realloc(*client_details, (*size + 1) * sizeof(**client_details)); *size = *size + 1; } int main() { struct group_detail *group_details = malloc(0 * sizeof(*group_details)); struct client_detail *client_details = malloc(1 * sizeof(*client_details)); int size … Read more
Introduction The malloc: *** error for object 0x147606ac0: pointer being realloc’d was not allocated is a common error encountered when attempting to reallocate memory in C programming. This error occurs when a pointer is passed to the realloc() function, but the pointer was not allocated with malloc() or calloc() beforehand. This error can be caused … Read more
TL;DR Your code provokes Undefined Behavior, as already mentioned in Morlacke’s Answer. Other than that, it seems that you’re having problems on understanding how pointers work. See references for tutorials. First, From your comments When you say that there’s memory allocated for ip in this case: int i = 10; int *ip; ip = &i; … Read more
Assuming you have the number of rows “r” and the number of columns “c”, you can do this: int **arr; arr = malloc(r*sizeof(int*)); for(int i=0; i < r; i++) { arr[i] = malloc(c*sizeof(int)); } this dynamically allocates an array of pointers to integers, and then allocates arrays of integers to each pointer. Don’t forget to … Read more
sizeof is giving you the size of char pointer which is 4 on your platform. 0 solved Dynamic Memory allocation to string, gives out incorrect size [duplicate]
I want to have a array of struct A, so I declared the array in function ‘mem_init’. this is not what you did because struct A *arr_A[n]; is an array of pointers tostruct A. An array of struct A can be struct A arr_A[n]; // variable length array or struct A * arr_A = malloc(n … Read more
There are multiple issues with your program. Let me list all of them one by one. As mentioned in one of the comments, You are immediately deallocating memory just after you allocated it. Definitely this will result in a segmentation fault or memory access violation when you access deallocated memory. When you allocate the memory … Read more
According to the C++ Standard (4.2 Array-to-pointer conversion) 1 An lvalue or rvalue of type “array of N T” or “array of unknown bound of T” can be converted to a prvalue of type “pointer to T”. The result is a pointer to the first element of the array. So for example if you have … Read more
You have extra stars. The function should be void assign_memory_for_board(int ROWS, int COLS, int *** board) { *board = new int*[ROWS]; for (int i = 0; i < ROWS; i++) { (*board)[i] = new int[COLS]; } } 3 solved Allocate memory 2d array in function C++
Remarks: You do not free allocated memory by using delete[]. That’s a very bad practice. You always should remember to free memory you allocated. It is very, very uncomfortable to choose jagged arrays (arrays of arrays) for long term use. A lot easier solution is to allocate a single array: double * phi = new … Read more
From the man page: The realloc() function changes the size of the memory block pointed to by ptr to size bytes. So instead of: int *newbuffer = (int*) realloc (stacky, size); you probably want int *newbuffer = (int*) realloc (stacky, size * sizeof(int)); BTW: No need for cast when using malloc and friends. See Do … Read more
Exception thrown at 0x0F640E09 (ucrtbased.dll) in ConsoleApplication5.exe: 0xC0000005: Access violation writing location 0x014C3000? solved Exception thrown at 0x0F640E09 (ucrtbased.dll) in ConsoleApplication5.exe: 0xC0000005: Access violation writing location 0x014C3000?
The stack is the memory set aside as scratch space for a thread of execution. When a function is called, a block is reserved on the top of the stack for local variables and some bookkeeping data. When that function returns, the block becomes unused and can be used the next time a function is … Read more