An easy implementation would be to do something like: if len(set(input)) == 1: print(‘not present’) else: sorted(set(input))[-2] Take a look at Get the second largest number in a list in linear time for other implementations. 6 solved Need to find second maximum number in the list. All the details pasted below in the body. Please … Read more
You can simply use foreach instead like as foreach($your_arr as &$v){ $v = [$v[“period”] => $v[“way”]]; } print_r($your_arr); Or using array_map $your_arr = array_map(function($v){ return [$v[“period”] => $v[“way”]]; },$your_arr); print_r($your_arr); solved PHP Use array map to reOrder an array
You can do it by using a loop and from what I understand, a seperate method, which we’ll call addSum. In addSum, we will create a for loop with the starting limits and the ending limit. public static void addSum(int start, int end) { int addMe = 0; for(; start <= end; start++) { addMe … Read more
Is this answer correct? It is a declaration of a function that returns reference to an array of 10 int. gdb tells me it returns a int * variable. No it doesn’t. It tells you that the variable t that you created is an int * variable. 0 solved C++ Return the reference of an … Read more
You’re passing values that aren’t even of the right data type. Read up on TimeZoneInfo so you know how to use it properly. Also read: Why you shouldn’t use DateTime.Now The timezone tag wiki DST and Time Zone Best Practices Also understand that somewhere here you actually have to know the user’s time zone. Just … Read more
You are assigning a function to a function. Functions do not have a static value as you are trying to assign, and therefore you cannot simply assign another function to it. Maybe you want to assign each to a variable like this: my_var1 = predict_func(x, y, w, h) my_var2 = cv2.boundingRect(cnts[i]) Or maybe you want … Read more
you could do: function find_word_pos($string, $word) { //case in-sensitive $string = strtolower($string); //make the string lowercase $word = strtolower($word);//make the search string lowercase $exp = explode(” “, $string); if (in_array($word, $exp)) { return array_search($word, $exp) + 1; } return -1; //return -1 if not found } $str = “This is a string”; echo find_word_pos($str, “string”); … Read more
When you try to deploy a version of your APP to Google App Engine using a pipeline on Azure DevOps, if the deployment step itself is failed, normally the new version may not be deployed to App Engine. You just need to retry the pipeline. However, if the deployment step has completed successfully, but one … Read more
Use below code to your goal. startB = (Button) this.findViewById(R.id.button1); startB.setOnClickListener((OnClickListener) this); text = (TextView) findViewById(R.id.textView1); @Override public void onClick(View v) { new CountDownTimer(30000, 1000) { // adjust the milli seconds here public void onTick(long millisUntilFinished) { text.setText(“”+String.format(“%d min, %d sec”, TimeUnit.MILLISECONDS.toMinutes( millisUntilFinished), TimeUnit.MILLISECONDS.toSeconds(millisUntilFinished) – TimeUnit.MINUTES.toSeconds(TimeUnit.MILLISECONDS.toMinutes(millisUntilFinished)))); } public void onFinish() { text.setText(“done!”); } }.start(); } … Read more
You must use when writting python the TAB. Try using VSCode for writing Python and install de Python extension. If you dont have it, use this to check if your sintax is correct: Checker-Python. From the first view I saw you dindt use correct tabulation on the while loop. solved username and password python I … Read more
You can do as var ph = [String]() var newjson = [[String:String]]() for dict in json { if ph.contains(dict[“Phone”]!) { print(“duplicate phone \(dict[“Phone”]!)”) } else { ph.append(dict[“Phone”]!) newjson.append(dict) } } print(newjson) Hare newjson is the new array of dictionary that do not have duplicate phone solved How to parse JSON data and eliminate duplicates in … Read more
Replace num1 and num2 with num3 and num4. class fraction: def __init__(self,num1,num2,num3,num4): self.num1=num1 self.num2=num2 self.num3=num3 self.num4=num4 def addition(self): print(self.num1+self.num2) return self.num1+self.num2 def sub(self): print(self.num1+self.num2) return self.num1+self.num2 def div(self): print(self.num1/self.num2) return self.num1/self.num2 def mul(self): print(self.num1*self.num2) return self.num1*self.num2 def reminder(self): print(self.num1%self.num2) return self.num1%self.num2 if __name__ ==”__main__”: object=fraction(1,2,3,4) object.addition() object.reminder() 0 solved Creating a class in python with … Read more
Use integer type long long. It is good for at least the range -9223372036854775807 <= x <= +9223372036854775807. #include <stdio.h> int main(int argc, char *argv[]) { long long big = 600851475143; printf(“%lld\n”, big); // prints 600851475143 return 0; } Alternatively, one could use int64_t or uint64_t – 64-bit types. The range mentioned above is the … Read more
after you will build the fundamental function for this list you can use “for each” function to do your task: int SlistForeach(node_t from, node_t to , action_func_t action_func, void *param) { int stat = 1; node_t index = from; assert(NULL != to); assert(NULL != from); while(index != to) { stat = action_func(&(index->data), param); if(0 == … Read more
You should look into a collection called Set. There is a pretty handy function Set.contains that will return true or false depending if a number is already in the Set or not. Something like this would do the trick: Scanner scanner = new Scanner(System.in); int maxNum = 8; Set<Integer> numbers = new HashSet<>(); int digCounter … Read more