[ad_1] Did you ever initialize numberOfTries? Try changing this: for (numberOfTries=0; numberOfTries = 4; numberOfTries++){ To: for (int numberOfTries=0; numberOfTries <= 4; numberOfTries++){ 2 [ad_2] solved required: boolean found: int 1 error
[ad_1] You will have to use POST/GET to send a JS variable to PHP, because PHP is processed by the server and JS is processed by the client. I know this isn’t what you want to hear. [ad_2] solved Passing jQuery variable to PHP on the same page?
[ad_1] Type of conditional expression cannot be determined because there is no implicit conversion between ‘Entities.KRAParameterInfo’ and ‘string’ [ad_2] solved Type of conditional expression cannot be determined because there is no implicit conversion between ‘Entities.KRAParameterInfo’ and ‘string’
[ad_1] You may want to reconsider how the app is structured. If you are checking for usernames before being authenticated that means the node is exposed and anyone can grab a copy of all the usernames. Obviously that in itself may not be a huge issue but if your users decide to use an email, … Read more
[ad_1] Try transaction[‘amount’] For example a = {“amount”=>”-50.01″, “currency”=>”CAD”} Then a[‘amount’] returns ‘-50.01’ 2 [ad_2] solved Negative string value in hash ruby [closed]
[ad_1] Whilst we can’t say for sure without the XML that’s being parsed, the usual reason for ‘getting blanks’ from childNodes[0] (firstChild) is that there is a whitespace Text node between the parent’s start-tag and the node you are looking for: <data> <![CDATA[ foo ]]> </data> On an XML parser that retains CDATA sections, that’ll … Read more
[ad_1] Create a UIButton. Set the cornerRadius to (button height / 2). Style it for each state you would like. You could even use an image as a background and just edit the image for pressed and not pressed. Use Interface Builder and set the background image as applicable. [ad_2] solved How to create a … Read more
[ad_1] How can I find specific variables have the same names for all countries in original dataset and select them for another new dataset? [ad_2] solved How can I find specific variables have the same names for all countries in original dataset and select them for another new dataset?
[ad_1] Add in Manifest.xml: <uses-permission android:name=”android.permission.READ_EXTERNAL_STORAGE” /> <uses-permission android:name=”android.permission.WRITE_EXTERNAL_STORAGE” /> For android versions higher than M you have to ask for permissions, I’m referring to this question: Link [ad_2] solved webview app permission for capturing images using camera and uploading images from gallery
[ad_1] You could try something like this in data.table data <- data.table(yourdataframe) bar <- data[,.N,by=y] foo <- data[x==1 & z==1,list(mean.t=mean(t,na.rm=T),median.t=median(t,na.rm=T)),by=y] merge(bar[,list(y)],foo,by=”y”,all.x=T) y mean.t median.t 1: 1 12.5 12.5 2: 2 NA NA 3: 3 NA NA 4: 4 NA NA You probably could do the same in aggregate, but I am not sure you can … Read more
[ad_1] In your MainActivity.java: public void onClicknews(View v) { String titel1 = “Trumps brutales Kalkül”; EditText article = (EditText) findViewById(R.id.articlename); String s = article.getText().toString(); Intent intent = new Intent(getApplicationContext(), NewsActivity.class); intent.putExtra(“articalName”,s); startActivity(intent); } In your NewsActivity.java: EditText news = (EditText) findViewById(R.id.news); String newsName = getIntent().getStringExtra(“articalName”); news.setText(newsName ); 0 [ad_2] solved Change EditText with Button click
[ad_1] If its a valid JSON you can use $.each() $.each() or jQuery.each() is used for iterating over javascript objects and arrays. Example : In the example below intArray is a JavaScript array. So to loop thru the elements in the array we are using $.each() function. Notice this function has 2 parameters The JavaScript object … Read more
[ad_1] IDs must be unique, so use instead: (and close all UL tags) <ul> <li> <a class=”left-menu”>Test</a> <ul style=”display: none” class=”submenu”> <li>test</li> <li>test</li> </ul> </li> <li> <a class=”left-menu active”>Test 2 </a> <ul style=”display: none” class=”submenu”> <li>test</li> <li>test</li> </ul> </li> </ul> And then: jQuery(document).ready(function($) { $(“.left-menu.active”).next(‘.submenu’).show(); }); BTW, you could use: $(“.left-menu.active”).next(‘.submenu’).show(); SEE DEMO 3 [ad_2] … Read more
[ad_1] if (document.getElementById(‘name’).value != “” && document.getElementById(‘company’).value != “” && document.getElementById(’email’).value != “”){ document.getElementById(‘hiddenpdf’).style.display = ‘block’; }else{ document.getElementById(‘hiddenpdf’).style.display = ‘none’; } Hope this helps. You have a syntax error in your code. Above solution checks with “and” logic and will only execute ‘block’ statement if all three conditions are met otherwise it will move over … Read more
[ad_1] First you put one Div element for whole content set width as 100% and indise div for img tag 50% and Button 50% .It should work CSS: #needdiv { width:100%; display:block; } #needdiv img { float:left; } #needdiv input { float:right; } [ad_2] solved how to show button and images in one line using … Read more