Did you ever initialize numberOfTries? Try changing this: for (numberOfTries=0; numberOfTries = 4; numberOfTries++){ To: for (int numberOfTries=0; numberOfTries <= 4; numberOfTries++){ 2 solved required: boolean found: int 1 error
You will have to use POST/GET to send a JS variable to PHP, because PHP is processed by the server and JS is processed by the client. I know this isn’t what you want to hear. solved Passing jQuery variable to PHP on the same page?
Type of conditional expression cannot be determined because there is no implicit conversion between ‘Entities.KRAParameterInfo’ and ‘string’ solved Type of conditional expression cannot be determined because there is no implicit conversion between ‘Entities.KRAParameterInfo’ and ‘string’
You may want to reconsider how the app is structured. If you are checking for usernames before being authenticated that means the node is exposed and anyone can grab a copy of all the usernames. Obviously that in itself may not be a huge issue but if your users decide to use an email, whoever … Read more
Try transaction[‘amount’] For example a = {“amount”=>”-50.01″, “currency”=>”CAD”} Then a[‘amount’] returns ‘-50.01’ 2 solved Negative string value in hash ruby [closed]
Whilst we can’t say for sure without the XML that’s being parsed, the usual reason for ‘getting blanks’ from childNodes[0] (firstChild) is that there is a whitespace Text node between the parent’s start-tag and the node you are looking for: <data> <![CDATA[ foo ]]> </data> On an XML parser that retains CDATA sections, that’ll give … Read more
Create a UIButton. Set the cornerRadius to (button height / 2). Style it for each state you would like. You could even use an image as a background and just edit the image for pressed and not pressed. Use Interface Builder and set the background image as applicable. solved How to create a circular button … Read more
How can I find specific variables have the same names for all countries in original dataset and select them for another new dataset? solved How can I find specific variables have the same names for all countries in original dataset and select them for another new dataset?
Add in Manifest.xml: <uses-permission android:name=”android.permission.READ_EXTERNAL_STORAGE” /> <uses-permission android:name=”android.permission.WRITE_EXTERNAL_STORAGE” /> For android versions higher than M you have to ask for permissions, I’m referring to this question: Link solved webview app permission for capturing images using camera and uploading images from gallery
You could try something like this in data.table data <- data.table(yourdataframe) bar <- data[,.N,by=y] foo <- data[x==1 & z==1,list(mean.t=mean(t,na.rm=T),median.t=median(t,na.rm=T)),by=y] merge(bar[,list(y)],foo,by=”y”,all.x=T) y mean.t median.t 1: 1 12.5 12.5 2: 2 NA NA 3: 3 NA NA 4: 4 NA NA You probably could do the same in aggregate, but I am not sure you can do … Read more
In your MainActivity.java: public void onClicknews(View v) { String titel1 = “Trumps brutales Kalkül”; EditText article = (EditText) findViewById(R.id.articlename); String s = article.getText().toString(); Intent intent = new Intent(getApplicationContext(), NewsActivity.class); intent.putExtra(“articalName”,s); startActivity(intent); } In your NewsActivity.java: EditText news = (EditText) findViewById(R.id.news); String newsName = getIntent().getStringExtra(“articalName”); news.setText(newsName ); 0 solved Change EditText with Button click
If its a valid JSON you can use $.each() $.each() or jQuery.each() is used for iterating over javascript objects and arrays. Example : In the example below intArray is a JavaScript array. So to loop thru the elements in the array we are using $.each() function. Notice this function has 2 parameters The JavaScript object or … Read more
IDs must be unique, so use instead: (and close all UL tags) <ul> <li> <a class=”left-menu”>Test</a> <ul style=”display: none” class=”submenu”> <li>test</li> <li>test</li> </ul> </li> <li> <a class=”left-menu active”>Test 2 </a> <ul style=”display: none” class=”submenu”> <li>test</li> <li>test</li> </ul> </li> </ul> And then: jQuery(document).ready(function($) { $(“.left-menu.active”).next(‘.submenu’).show(); }); BTW, you could use: $(“.left-menu.active”).next(‘.submenu’).show(); SEE DEMO 3 solved query … Read more
if (document.getElementById(‘name’).value != “” && document.getElementById(‘company’).value != “” && document.getElementById(’email’).value != “”){ document.getElementById(‘hiddenpdf’).style.display = ‘block’; }else{ document.getElementById(‘hiddenpdf’).style.display = ‘none’; } Hope this helps. You have a syntax error in your code. Above solution checks with “and” logic and will only execute ‘block’ statement if all three conditions are met otherwise it will move over to … Read more
First you put one Div element for whole content set width as 100% and indise div for img tag 50% and Button 50% .It should work CSS: #needdiv { width:100%; display:block; } #needdiv img { float:left; } #needdiv input { float:right; } solved how to show button and images in one line using css