Month: August 2022

[Solved] create an image view in android with arbitrary shape [duplicate]

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You can achieve the described background by below code. <?xml version=”1.0″ encoding=”utf-8″?> <layer-list xmlns:android=”http://schemas.android.com/apk/res/android”> <item android:drawable=”@color/colorPrimary”/> <item> <bitmap android:src=”https://stackoverflow.com/questions/49953217/@drawable/your-drawable” android:gravity=”center” android:alpha=”0.1″/> </item> <item android:top=”300dp” android:bottom=”-300dp” android:left=”0dp” android:right=”-300dp”> <rotate android:fromDegrees=”-10″ android:pivotX=”0%” android:pivotY=”100%”> <shape android:shape=”rectangle”> <solid android:color=”?android:colorBackground”/> </shape> </rotate> </item> </layer-list> 4 solved create an image view in android with arbitrary shape [duplicate]

[Solved] How to display specific JSON data using Javascript alert? [closed]

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You can try the following way: var myJSON = { “status”: “Succeeded”, “recognitionResult”: { “lines”: [ { “boundingBox”: [ 2, 52, 65, 46, 69, 89, 7, 95 ], “text”: “The quick brown fox jumps over the lazy”, } ] } } var text = myJSON.recognitionResult.lines[0].text; console.log(text) 2 solved How to display specific JSON data using … Read more

[Solved] Looking for regex solution [closed]

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Will be [0-9]{2}\.[0-9]{2}\.[0-9]{4} [0-9]stands for any integer in range 0 to 9, the number in curly brackets ({2} in this case) indicates how many times should the pattern be repeated. You need to escape the dots with a backslash because otherwise they will be interpreted as any character. 0 solved Looking for regex solution [closed]

[Solved] Error trying to swap Card Objects in a vector c++

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To pick out some key lines from you error In instantiation of ‘void std::swap(_Tp&, _Tp&) [with _Tp = Card]’: use of deleted function ‘Card& Card::operator=(Card&&)’ ‘Card& Card::operator=(Card&&)’ is implicitly deleted because the default definition would be ill-formed: non-static const member ‘const int Card::numFace’, can’t use default assignment operator You are trying to use std::swap with … Read more

[Solved] Apply get set for methods? [closed]

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The answer is: it depends. I’ll try to help you to reformulate your question: does it make any sense to return a function rather than computed result from another fuction? Then I would say: definitely yes (let me know if you’d like to know ehy, I’ll update this post). But the example you showed does … Read more

[Solved] How can i generate an excel file and save it into the local directory and send it with a mail as an attachment using phpmailer [closed]

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include ‘connection.php’; include ‘phpmailer/PHPMailerAutoload.php’; $name=$_POST[‘details’]; $location=$_POST[‘from’]; $city=$_POST[‘to’]; $state=$_POST[‘message’]; $branch=$_POST[‘client’]; $email=$_POST[’email’]; $date=date(‘Y-m-d’); $columnHeader=””; $columnHeader = “Details” . “\t” .”From Date” . “\t”. “To Date” . “\t”. “Message” . “\t”. “Hotel” . “\t” . “Email” . “\t” . “Date” ; $setData=””; $newarray = array(‘details’=>$name,’fromdate’=>$location,’todate’=>$city,’message’=>$state,’hotel’=>$branch,’email’=>$email,’date’=>$date); $rowData=””; foreach ($newarray as $value) { $value=””” . $value . ‘”‘ . “\t”; … Read more

[Solved] Sibling as Child

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In XSLT 2.0, you could have probably made use of xsl:for-each-group, using its group-starting-with attribute. In XSLT 1.0 though, this can be achieved by use of keys. You can define a key to look up the Loop-2000B elements by their first preceding Loop-2000A element <xsl:key name=”B” match=”ex:Loop-2000B” use=”generate-id(preceding-sibling::ex:Loop-2000A[1])” /> Similarlym you could do the same … Read more

[Solved] Why are there so many formatting flavours in Python?

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This is what evolution looks like. “We need string concatenation”. Sure. “hello” + ”’ ”’ + ‘world’ or, if you like, ‘ ‘.join([‘hello’, ‘world’]) “But “found ” + str(var) + ” matches” is kind of clumsy. I hear Lisp has princ…?” Oh okay, here: ‘found %i matches’ % var (… Time passes… ) “I hear … Read more

[Solved] Just input a number in cpp [closed]

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I think this is what you are looking for: #include <iostream> #include <string> #include <cctype> int main () { std::string input; bool valid; do { valid = true; std::cin >> input; for (char c : input) if (! std::isdigit( static_cast<unsigned char>(c) ) ) valid = false; } while (! valid); // Here the string is … Read more