Hidden? It’s not hidden. What does that even mean? I do remember that you have to explicitly use it in Java Only in some circumstances. A variable called name could be known inside the class and also be the name of a parameter in a method. Example: class Test { String name; public void test(String … Read more
You don’t need to use ref in your parameter declarations. For reference types like your class A, a parameter declared as just A other will cause C# to pass a reference to the object. A parameter declared as A other in C# is similar to A* other in C++. A parameter declared as ref A … Read more
Why can’t the context be gleaned by the j/s? This is not a question about can and cannot. The Javascript engine is designed to use certain concepts such as for example scope and execution context. It is difficult to give a full explanation of these concept in just a few lines. But here are the … Read more
The value of this changes depending upon how the function was invoked; Collection.prototype.onOpen(); // `this` refers to `Collection.prototype` // vs var c = new Collection(); c.onOpen(); // `this` refers to `c` // vs var o = {}; Collection.prototype.onOpen.call(o); // `this` refers to `o` // vs var foo = Collection.prototype.onOpen; foo(); // `this` could be `window` … Read more
First thing to get straight: a non-static member function is essentially just like any other function, but has an implicit parameter called this which is a pointer to the object that the member function was called on. That is, calling foo.bar() can be thought of as similar to calling bar(&foo), where the first parameter is … Read more
Use this code: @Override public void onClick(View view) { // TODO Auto-generated method stub //public void work (View view){ Intent intent = new Intent(PDFtester.this, copyAsset.class); startActivity(intent);} } Note :- Interfaces like OnClickListener,OnTouchListener etc don’t use this for getting Context try to use YourActivity.this or getApplicationContext() 2 solved calling a method from an onClick listener [duplicate]
The dilemma here is that “currently executing object” is a very abstract concept that is easy to intuit but hard to describe in writing (at least for me) If you have a ChildClass, it is also a BaseClass. Therefore, you have a single object in question. Its type is ChildClass, and it can be cast … Read more
Introduction This article will discuss the use of the keyword “this” in Javascript. We will look at when it is appropriate to use “this” and when it is not. We will also discuss the different ways in which “this” can be used and the implications of using it incorrectly. By the end of this article, … Read more
when it is needed/best practice to use the keyword this This is usually used when you want to access something in some. So for instance, if you have a custom object and want to use some property inside some method, you should use this. function Person(fname, lname){ this.fname = fname; this.lname = lname; this.fullName = … Read more
It is not possible to set this. You can however create a method which copies all values of the receivedclass object to this if the types are compatible. But i don’t know if this is what you want. 3 solved Is that possible to do this = variable in Java?
In Visual Studio C++, what are the memory allocation representations?: 0xCCCCCCCC : Used by Microsoft’s C++ debugging runtime library to mark uninitialised stack memory At the moment you do obj->, your obj is not initialized. The two lines of code in the question are not your real code, or there is something important taking place … Read more
Any JS problem relating to this is likely due to the way the function using this is called. Storing a reference to this in your that variable should let you reference it from within your nested functions, exactly the way you are doing it already – assuming that qwerty() is called in a way that … Read more
When is using the “this pointer” useful in a C++ program When you need a pointer to the current object. One of the most often usages of this that I have seen is to make self assignment a noop. Foo& Foo::operator=(Foo const& rhs) { if ( this != &rhs ) { // Assign only when … Read more
Here’s a possible solution: Use the same name, just at different scopes. #include <iostream> #define LOG(x) do { log() << (x) << ‘\n’; } while(false) std::ostream & log() { return std::clog; } struct Identifier { std::ostream & log() { return ::log() << id << “: “; } int id; explicit Identifier(int n) : id(n) {} … Read more
this keyword is used to reference current instance of given class, for example: class A { public: void setName(std::string name) { // if you would use name variable directly it // will refer to the function parameter, //hence to refer the field of the class you need to use this this->name = name; } private: … Read more