[ad_1] How can I extract a string from a text field that matches with a “value” in my Dictionary and return the dict’s key into a new column in the Output? [closed] [ad_2] solved How can I extract a string from a text field that matches with a “value” in my Dictionary and return the … Read more
[ad_1] If input is contained in a std::string you can find the length as stated by Ravi. If it’s a C string you find the length with int len = strlen(INPUT); In C/C++ upper case is normally used for constants so it’s better to name the string input, not INPUT. 0 [ad_2] solved How to … Read more
[ad_1] Are you using str[n]cpy? You can’t! Base64 encoded data can contain null characters, which C string processing functions interpret as end-of-string. Use memcpy instead of str[n]cpy, memcmp instead of strcmp, etc. These functions require you to know your data size, but I believe that you do know it. Also if you’re not very confident … Read more
[ad_1] Since you are sure the string will contain digits, subtract each character from ‘0’ to get their numeric value. int sum = 0; fgets(str, sizeof str, stdin); char *s = &str; while(*s != ‘\0’) { sum += *(s++) – ‘0’; } printf(“the sum of the digits is: %d”, sum); [ad_2] solved Splitting a string … Read more
[ad_1] #example of the list being used conundrum = [‘black pen’, ‘lift pen’, [‘go to’, -98, 132], [‘draw dot’, 10], ‘lift pen’, [‘go to’, -120, 137], [‘draw dot’, 10], ‘lift pen’, ‘thick lines’, [‘go to’, -55, 80], ‘lower pen’] #Import everything from the turtle library from turtle import * #Define the draw function def draw(test): … Read more
[ad_1] You are using an uninitialized string, so assigning a to s[0] does nothing or does undefined behavior. To do this, you have to give s a size, as the options below: Option 1: Resize #include <bits/stdc++.h> using namespace std; int main() { string s; s.resize(10); s[0] = ‘a’; cout << s << endl; return … Read more
[ad_1] example by use strtok, strchr, sprintf #include <stdio.h> #include <stdlib.h> #include <string.h> int main(){ const char *data = “date=2013-12-09 time=07:31:10 d_id=device1 logid=01 user=user1 lip=1.1.1.1 mac=00:11:22:33:44:55 cip=2.2.2.2 dip=3.3.3.3 proto=AA sport=22 dport=11 in_1=eth1 out_1=”; char *work = strdup(data);//make copy for work char *output = strdup(data);//allocate for output char *assignment; //tokenize to aaa=vvv size_t o_count = 0;//output … Read more
[ad_1] try this: public String getTestGauge(){ return String.valueOf(<yourdouble>); } –> this is prettier return (new Double(<yourdouble>).toString()); [ad_2] solved Converting double to string with a return
[ad_1] The problem is near break statement, Your break statement is being executed without executing a++;. Here is the correct code. #include<stdio.h> #include<string.h> void main() { int a=0, copy[10]={0},len,i; char string[10]; clrscr(); puts(“enter a number string”); gets(string); len=strlen(string); while(a<len) { for(i=48;i<=57;i++) { if(string[a]==i) { copy[a]=i-48; a++; break; } } } for(i=0;i<len;i++) printf(“%d”,copy[i]); getch(); } [ad_2] … Read more
[ad_1] One of the option is just to split before the first English character and take the 1st and 2nd group inputstring = ‘小西 – 杏花 Siu Sai – Heng Fa’ a = re.split(r'([a-zA-Z].*)’, inputstring) >>>[‘小西 – 杏花 ‘, ‘Siu Sai – Heng Fa’, ”] Another way to do this without an empty string is … Read more
[ad_1] No, there’s no difference, unless someone’s done something silly to the JavaScript environment. “andrei” is a string primitive, thus typeof “andrei” is “string”. If you do “andrei”.valueOf(), you’re coercing a string primitive into a String object (in theory*) because you’re accessing a property on it (valueOf), and then asking that object for its primitive … Read more
[ad_1] You will want to do the following: char *gg = “hello”; printf( “%c\n”, gg[3] ); This will print the fourth character (zero based array = 0, 1, 2, 3 so 0=’h’, 1=’e’, etc). Change the 3 to which ever character you want, but make sure to not go past the end of the string. … Read more
[ad_1] there is no custom operator overloading in java. [so you cannot overload it to call equals()] the equals() ensures you check if 2 Objects are identical,while == checks if this is the exact same object. [so no, using == does not invoke equals()]. 2 [ad_2] solved Comparing java Strings with == [duplicate]
[ad_1] In your first example, you MUST pass a char pointer for the “%s” modifier so it is actually the way it has to be, you would of course know that if you read the appropriate documentation, like e.g. The C Standard. The second one, is wrong. Because it would invoke undefined behavior. To print … Read more
[ad_1] Split the string by space and rename the last word. Then using the StringBuilder concatenate them together back to your original String. String str = “hello I am a example example” String[] parts = str.split(” “); parts[parts.length-1] = “moon”; System.out.println(parts[parts.length-1]); StringBuilder sb = new StringBuilder(); for (int i=0; i<parts.length; i++) { sb.append(parts[i]); sb.append(” “); … Read more