[ad_1] As panta-rei correctly pointed out, it looks like you’re trying to contain a string of the form “string” + string form of (i) but you’re actually doing pointer arithmetic which is illogical in this case (you’re just passing a pointer incremented i from some location – who knows what’s in that memory?). In order … Read more
[ad_1] You can use itertools.groupby for this: >>> s = “aaaXXXbbbXXXcccXdddXXXXXeXf” >>> import itertools >>> sum(e == ‘X’ for e, g in itertools.groupby(s)) 5 This groups the elements in the iterable — if no key-function is given, it just groups equal elements. Then, you just use sum to count the elements where the key is … Read more
[ad_1] You could use a negated class like: [^A-Za-z0-9\s] Btw, you also can shorten it to: [^A-Za-z\d\s] And.. if you don’t mind to preserve underscores your could use: [^\w\s] The idea of the negated class is to not match the characters in it. For this regex: [^A-Za-z0-9\s] it means: ^ —> not match the following … Read more
[ad_1] You need regular expressions for this: import re s=”abc xyz.xyz(1, 2, 3) pqr” re.sub(r'[a-z]{3}\.{[a-z]{3}\([^)]*\)’, ‘NULL’, s) Explanation: [a-z]{3} stands for 3 small letters (lower case) \. escapes the dot, as it is special character [a-z]{3} again 3 small letters \( escapes the left parenthesis [^)]* any character but right parenthesis, 0 or more time … Read more
[ad_1] package stackoverflow.q_24933319; public class FindLength { public static void main(String[] args) { String[] arr = {“abc”,”bgfgh”,”gtddsffg”}; System.out.println(“Array size is: ” + arr.length); for(String s : arr) { System.out.println(“Value is ” + s + “, length is ” + s.length()); } } } //Output: //Array size is: 3 //Value is abc, length is 3 //Value … Read more
[ad_1] You can use the function split: String[] words = yourString.split(” “); int currency = Integer.parseInt(words[0]); String currencyFrom = words[1]; String currencyTo = words[2]; 1 [ad_2] solved How can I split a string by a delimiter in Java? [duplicate]
[ad_1] Here is a program with comments explaining how you can do what you want. Hopefully it will help you learn how to solve such problems. #include <stdio.h> #include <stdlib.h> #include <string.h> /* Use if strdup() is unavailable. Caller must free the memory returned. */ char *dup_str(const char *s) { size_t n = strlen(s) + … Read more
[ad_1] Sometimes (rarely) regexes are the response to the question, especially if the question is like this. bool ism1 = Regex.IsMatch(“AABAC”, @”(.)\1\1″); // false bool ism2 = Regex.IsMatch(“AAABC”, @”(.)\1\1″); // true Matches any character (.) followed by the first match (\1) twice. 0 [ad_2] solved C# how to check if a string contains 3 times … Read more
[ad_1] you can use this to separate text and number first then proceed further, preg_match_all(‘/[^\d]+/’, $string, $textMatch); preg_match(‘/\d+/’, $string, $numMatch); $text = $textMatch[0]; $num = $numMatch[0]; 2 [ad_2] solved To print sum of numbers from this string
[ad_1] public static void main(String[] args) { String str = “154.232”; str = str.replaceAll(“\\..*”, “”); System.out.println(str); } or str.substring(0, str.indexOf(“.”)); or // check for index of . is not -1, then do following. str.split(“.”)[0]; output 154 [ad_2] solved Split the number on a decimal
[ad_1] Your return type is void, not string. Change it to: private string SQLSelection() A void is a “returnless” action that is performed upon something and does not “return” back the values of the return statement. If you try to return a value, you get a compiler error as you are experiencing. In addition, you … Read more
[ad_1] Before you do sss+=str;,please add sss=str;. you forget to update your sss. public static void main(String[] args) { String s = “2a[2b[c]]]”; Stack s1 = new Stack(); for(int i=0;i<s.length();i++) { s1.push(s.charAt(i)); } String str=””; String sss=””; for(int j=0;j<s.length();j++) { char a = (char)s1.pop(); System.out.println(“a:”+a); // if(a == ”) if((int)a >=49 && (int)a<=58){ for(int i=0;i<(int)a-48;i++){ … Read more
[ad_1] i Resolved my issue by using stack overflow suggestions. and i am posting my answer it may helpful for others. extension Date { var startOfWeek: Date? { let gregorian = Calendar(identifier: .gregorian) guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil } return gregorian.date(byAdding: .day, value: 1, to: sunday) } … Read more
[ad_1] The most simple approach would be to just check for every element in src vector, if an duplicate exists in dest vector or not. If it exists just append Duplicate to it, else you can just push back the element as a new element in dest vector. The follow code would do the job … Read more
[ad_1] You can build a list of lines skipping the digit ones this way : lines = [line for line in data.splitlines() if not line.strip().isdigit()] assuming data is your text file content. 1 [ad_2] solved How to extract a line from text file that is digits-only? [closed]