Your immediate problem is this: LDates[‘%s’ % (‘string%s'[‘Id’] % i)] I believe that you mean to access the variable you created earlier. That would require you to use: LDates[(globals()[‘string%s’ % i])[‘Id’]] But this whole thing is ill-advised. Why don’t you create a variable where you can access all the data by just passing in the … Read more
public static String[] SplitCsv(String value) { if (Object.ReferenceEquals(null, value)) return null; const Char quotation = ‘\”‘; const Char separator=”,”; List<String> result = new List<String>(); Boolean inQuotation = false; Boolean isStarted = false; StringBuilder Sb = new StringBuilder(); foreach (Char Ch in value) { if (inQuotation) { Sb.Append(Ch); inQuotation = Ch != quotation; continue; } if … Read more
package main import ( “fmt” “strings” ) func main() { for i := 1; i <= 6; i++ { fmt.Printf(“%6s\n”, strings.Repeat(“#”, i)) } } Try it on the Go playground 1 solved How to print the star pattern aligned to right hand side in GO lang
“%” is actually the modulus operator but it can also be used to format strings. Learn more about it here: link 0 solved How to use % symbol correctly
You should certainly read more on regex. A first hint is that when you want to capture a pattern you need to enclose it in parentheses. e.g. (\d+). For this example though, the code you need is: match = re.match(r’C(\d+)([F|G])(\d+)\.PNG’, s) first_id = match.group(1) fg_class = match.group(2) second_id = match.group(3) 1 solved How to extract … Read more
The date class defines the __format__() magic method, which is called by str.format() to produce a “formatted” string representation of an object. To quote the documentation for date.__format__(): Same as date.strftime(). This makes it possible to specify a format string for a date object in formatted string literals and when using str.format(). For a complete … Read more
This should work as you specified in your question. DateFormat dateFormat = new SimpleDateFormat(“yy-MMM-dd HH:mm:ss a”); System.out.println(dateFormat.format(new Date())); The date format you have in your question is something like: DateFormat dateFormat = new SimpleDateFormat(“yyyyMMddHmmss”); 2 solved Convert String to Date object [duplicate]
The “0” custom format specifier serves as a zero-placeholder symbol. If the value that is being formatted has a digit in the position where the zero appears in the format string, that digit is copied to the result string; otherwise, a zero appears in the result string. The position of the leftmost zero before the … Read more
Use string formatting: In [48]: def solve(a,b): a,b=str(a),str(b) spaces=len(a.split())-1 return “{0} {1} {2}”.format(a,”.”*(68-len(a)-len(b)-spaces),b) ….: In [49]: print solve(a,b);print solve(p,q) Hello …………………………………………………. False Python rocks …………………………………………… True 5 solved Python text formatting
You can do it programmatically using this function val text = “This is my first text view this is my second textview this is my third textview” textView.text = proxyWifi.textFormation(text) copy/paste this code do your project 🙂 public String textFormation(String text){ String result = “”; String[] sentenceWords = text.split(” “); List<String> newSentenceWords = new ArrayList<>(); … Read more
This is one way to achieve what you are looking to do: number = “12345678910” print( ‘number id {0}.{1}.{2}-{3}’.format( *[number[i:i+3] for i in range(0,len(number), 3)] ) ) #number id 123.456.789-10. There are a few problems with your code. First the first number in the “{0…}” refers to the positional argument in the format() function. In … Read more
This is what evolution looks like. “We need string concatenation”. Sure. “hello” + ”’ ”’ + ‘world’ or, if you like, ‘ ‘.join([‘hello’, ‘world’]) “But “found ” + str(var) + ” matches” is kind of clumsy. I hear Lisp has princ…?” Oh okay, here: ‘found %i matches’ % var (… Time passes… ) “I hear … Read more