Familiarize with the data that you have: The first key thing is to understand what data you have. Here in this case, you have four tables InsuranceCompanies Patient Doctors Visits Your goal: Find the list of all the patients who visited all orthopedists (specialty) associated with their Insurance Companies. Let’s take a step back and … Read more
In you sql code add this line CASE WHEN Approach = 0 THEN NULL END AS Approach so in your stored procedure when Approach will come as 0 then it will be replaced with NULL solved How to modify stored procedure to give null instead of 0
You have to create your service (which you can see by clicking right start menu bar and task manager). To create your service you have to open cmd as an adminstrator. Then write cd where/your/ sql/bin/. After that, write mysqld -install – you should see service succesfully installed. Go to services from task manager, find … Read more
select case when color=”Black” then ‘Green’ else case when color=”White” then ‘Red’ else color end end as [Color] from paint solved SQL statement to replace multiple values
open “config.inc.php” on your PMA folder. add this line to prompt the authentication before login $cfg[‘Servers’][$i][‘auth_type’] = ‘cookie’; /* $cfg[‘Servers’][$i][‘user’] = ‘root’; */ /* $cfg[‘Servers’][$i][‘password’] = ”; */ OR manually define your authentication by this line $cfg[‘Servers’][$i][‘auth_type’] = ‘config’; $cfg[‘Servers’][$i][‘user’] = ‘root’; $cfg[‘Servers’][$i][‘password’] = ‘yourpassword’; solved Access denied with localhost [closed]
select ID, — returns a sequence without gaps for consecutive years first_value(year) over (partition by ID order by year desc) – year +1 as x, — returns a sequence without gaps row_number() over (partition by ID order by year desc) as rn from Temp e.g. for ID=1: 1 2016 1 1 1 2015 2 2 … Read more
I see this in a comment: i need more than one value Okay. Let’s run this as a real query then: SELECT NombrePelicula, (SELECT SUM(pelicula.PrecioEntrada) FROM pelicula) / count(*) As Recaudacion FROM funcion GROUP BY NombrePelicula HAVING COUNT(*)>1 solved Subquery returned more than 1 value. This is not permitted when the subquery follows =, !=, … Read more
How do you represent the linkage of a person to a team. Do you use a teamID field in person? If so, what do you do when a person is not on a team? Keep it null? select * from person where teamID is null Set it to -1? select * from person where teamID … Read more
try this, public void updateQty(Integer qty,String bookId) { int originalQty = getQuantity(bookId); int updateQty = originalQty – qty; try{ SQLiteDatabase db = this.getWritableDatabase(); String rawQuery = “update ” + BOOKS_TABLE + ” set ” + KEY_QTY + ” = ” + updateQty + ” where ” + KEY_BOOK_ID + ” = ‘” + bookId + … Read more
With a UNION ALL you can get 1 combined resultset from 2 selects. Then you can group that and SUM the amounts per date. So you’re probably looking for something like this: select q.ID, q.Name, nullif(sum(case when q.Date=”2018-05-01″ then q.Amount end), 0) as “5/1/2018″, nullif(sum(case when q.Date=”2018-05-02” then q.Amount end), 0) as “5/2/2018” from ( … Read more
Given the code you’ve posted, here’s how I’d handle this. First, I’d create an associative lookup array whose keys are the column names and whose values are the corresponding point values; it would look something like this: $pointVals = array(’email1′ => 2, ’email2′ => 5, ’email3′ => 2, … ); You can generate this array … Read more
you can try this SELECT Department.DeptName, COUNT(Employee.FName) AS EmpCount FROM Employee INNER JOIN Department ON Employee.DeptId = Department.ID GROUP BY Department.DeptName order by EmpCount 2 solved SQL query to list department names in descending order of employee count
Posting as an answer, because I have a LOT of comments: The RIGHT JOIN is certainly wrong. This would imply that some stores do not need to exist, but of course, your sales facts are tied to stores with an INNER JOIN. It is effectively being turned into an INNER JOIN anyway, so is unlikely … Read more
Never try and prevent SQL injection solely by JavaScript. What happens if I turn JavaScript off? Your validation fails instantly. What happens if I modify your JS and remove the keywords you are preventing me from injecting? Always validate it against the server. solved Can we protect against SQL-injection by writing Javascript code correctly? how? … Read more
If you don’t want to create a dedicated function, you can use successive CROSS APPLYs: SELECT T.s, FirstSpace.i, SecondSpace.j, ThirdSpace.k, CASE When ThirdSpace.k > 0 THEN LEFT(T.s, Thirdspace.k – 1) ELSE T.S END AS Phrase FROM t CROSS APPLY (SELECT CHARINDEX(‘ ‘, T.s, 1)) AS FirstSpace(i) CROSS APPLY (SELECT CHARINDEX(‘ ‘, T.S, FirstSpace.i + 1)) … Read more