This solution below should do the trick (at least it does for the simplified version you put above. fi = fopen(‘myFile.txt’,’r’); fileCount = 1; fo = fopen([‘output’,num2str(fileCount),’.txt’],’w’); header = fgets(fi); fprintf(fo,header); tline = header; first = true; mark_index = 8; while ischar(tline) if (~first) values = cell2mat(textscan(tline,’%f ‘)); if values(mark_index) == 1 fclose(fo); fileCount = … Read more
You can use String‘s methods replaceAll and split together here. String one = “show ip interface brief | include 1234**\n Gi1/23.1234 xxx.225.xxx.106 YES manual up up”; String[] tokens = one.replaceAll(“[^\\n]+\\n\\s*”, “”).split(“\\s+”); System.out.println(Arrays.toString(tokens)); Output [Gi1/23.1234, xxx.225.xxx.106, YES, manual, up, up] solved How to split a string if any chracter is found in java
If you want to split it by space try, val = val.split(“\\s”)[0]; Here the String is split by whitespace (\n, \r, \t, \f, and ” “) 0 solved Java String.split not work [closed]
Use split() string name= “LUKE CARROLL”; string[] tmp = name.Split(‘ ‘); string FirstName = tmp [0]; string LastName = tmp [1]; 1 solved Split string into two separate strings [duplicate]
If you have dynamic separators like this, String.Split is not suitable. Use Regex.Split instead. You can give a pattern to Regex.Split and it will treat every substring that matches the pattern as a separator. In this case, you need a pattern like this: \d+\. |1|2|3|4 | are or operators. \d matches any digit character. + … Read more
sentence = “Get a sentence from the user and display it back with one word per line.” for character in range(len(sentence)): if sentence[character] == ‘ ‘ or sentence[character] == ‘.’ or sentence[character] == ‘,’: print(“”) else: print(sentence[character], end=”) OUTPUT: Get a sentence from the user and display it back with one word per line solved … Read more
You could take the remainfer of the index with three and address the dame group for every third element. If necessary take destructuring assignment, like [array0, array1, array2] = result; const array = [{ id: 0 }, { id: 1 }, { id: 2 }, { id: 3 }, { id: 4 }, { id: … Read more
Use a regular expression. import re result = re.sub(r'[dust]’, ”, string) The regexp [dust] matches any of those characters, and all the matches are replaced with an empty string. If you want to remove only the whole word dust, with possible repetitions of the letters, the regexp would be r’d+u+s+t+’. If only u can be … Read more
Introduction This article will discuss how to remove all occurrences of any characters in the word ‘dust’ from a given string. We will look at various methods of doing this, including using regular expressions, looping through the string, and using the replace() method. We will also discuss the advantages and disadvantages of each approach. Finally, … Read more
First, let’s elaborate rules: One part “John” -> “John” (do nothing) Two parts “John Smith” -> “Smith, John” (last, first) Three+ parts “John Peter Jack Smith” -> “Smith, John P. J.” (last, first, other in order as single letters) Having these rules we can implement a simple reordering: private static String ReOrderNamesParts(string name) { if … Read more
The following result, which isn’t an exact match to your request, but it may get you started. It doesn’t attempt to list all the starting times, but does count the number of entries per pd per date so any that are not equal to 2 can be detected easily. | ID | PD | MIN_TIME … Read more
Is Regex required? Here’s linq. edit: added a regex option as well since that was requested. ([a-z])([A-Z])”, “$1 $2”) matches lowercase letter and then uppercase letter and returns the matches as $1 and $2 respectively w/ a space in between. Note: this won’t work if you have accented characters like É, is that needed in … Read more
var cnt = (thestring.Count(x => x == ‘,’) + 1) / 4; 7 solved Split on every fourth comma in a string and count
Use string_to_array to split the string into multiple elements that can be accessed individually: select rules[1] as rule_1, rules[2] as rule_2, rules[3] as rule_3, rules[4] as rule_4, rules[5] as rule_5, rules[6] as rule_6 from ( select string_to_array(rules, ‘|’) as rules from rulebook ) t 1 solved PostgreSQL query to split based on Strings & Concatenate … Read more
With simple logic ‘4111111111111111’.match(/.{1,4}/g) Other way var str=”4111111111111111″; var parts = []; for (var i = 0; i < str.length; i += 4) { parts.push(str.substring(i, i + 4)); } console.log(parts); solved Jquery – Split a string(credit card number) in 4 groups [duplicate]