>>> from collections import OrderedDict >>> sorted_dict = OrderedDict() >>> dct = {1: 2, 3: 4, 4: 3, 2: 1, 0: 0} >>> dct.values().sort() >>> for x in sorted(dct.values(), reverse=True): … keys = [idx for idx in dct if dct[idx]==x] … for key in keys: … sorted_dict[key] = x … >>> >>> sorted_dict OrderedDict([(3, 4), … Read more
Read the file sequentially – thats the easiest route. Then randomly shuffle the collection. Actually, another question. Could you use math.random() to look at the lines of the text file and if, lets say, the line 5 comes up then you remove it from the parameters you set for math.random()? It would pick from 0-9 … Read more
This can be done using cellfun and strsplit as follows: NewValues = cellfun(@(x) strsplit(x, ‘, ‘), MyValues, ‘UniformOutput’,0); NewValues = [NewValues{:}].’ 7 solved Split a value of different data types cell array based upon a delimiter
include <time.h> include <stdio.h> int main(){ clock_t start = clock(); // Execuatable code clock_t stop = clock(); double elapsed = (double)(stop – start) * 1000.0 / CLOCKS_PER_SEC; printf(“Time elapsed in ms: %f”, elapsed); } 3 solved how to show time performance for merge sort? [closed]
You can use sortBy function of lodash. var users = [ { ‘user’: ‘fred’, ‘age’: 48 }, { ‘user’: ‘barney’, ‘age’: 36 }, { ‘user’: ‘fred’, ‘age’: 40 }, { ‘user’: ‘barney’, ‘age’: 34 } ]; _.sortBy(users, [function(o) { return o.user; }]); // => objects for [[‘barney’, 36], [‘barney’, 34], [‘fred’, 48], [‘fred’, 40]] solved … Read more
Your current method is … not quite right, for any kind of sort. Insertion sort would take an element and insert it at the correct index, then shift the already inserted items down appropriately. Something like void looper(int *p) { for (int i = 1;i < 25;i++) { int key = p[i]; int j = … Read more
public class Run { public static void main(String[] args) { String string = “I love stack overflow very much”; //replacing all newline and and then making tokens String[] words = string.replaceAll(“\\s”, “”).split(“(?<=\\G.{8})”); for (String st : words) { if (st.length() == 8) { // if length of the string is 8, just print the string … Read more
You could explode the string into an array by spaces, sort it and implode it back into a single string. Something like that: $string = “Lorem ipsum dolor sit amet consectetur adipiscing elit quisque facilisis tincidunt finibus aliquam id tempor elit ut in massa quis nisi dapibus tempus class aptent taciti sociosqu ad litora torquent … Read more
Using System.Linq, you can Take the first two items, then Concat that with the rest of the list after calling Reverse: var items = new[] {1, 2, 3, 4, 5}; var sorted = items.Take(2).Concat(items.Skip(2).Reverse()); Update: You can take this logic and create a more generic implementation, such as: private static int[] SortRangeReverse(int[] input, int startRange, … Read more
You can in-place sort scores if you want, using List.Sort(Comparison<T>): scores.Sort((a, b) => int.Parse(a.Punten).CompareTo(int.Parse(b.Punten))); Note that because Punten appears to be a string, you need to convert it to an int to compare properly. If you change your code to make Punten an int, the sorting code would simplify to: scores.Sort((a, b) => a.Punten.CompareTo(b.Punten)); What’s … Read more
Simple, type safe solution: enum Grade : Double { case A = 20.0 case B = 17.5 case C = 15.0 case D = 12.5 case E = 10.0 case F = 0.0 } extension Grade : Comparable { static func <(lhs: Grade, rhs: Grade) -> Bool { return lhs.rawValue < rhs.rawValue } } let … Read more
var goal = 4; array.sort(function(a, b) { if (a.Seats == goal) { return -1; } else if (b.Seats == goal) { return 1; } else { // If neither matches the goal, order them by Seats return a.Seats – b.Seats; } }); 0 solved Sort Array in Javascript [duplicate]
-r is to reverse the results -n specifies numerical ordering -k5 indicates it is comparing the entries in the 5th column solved Can anyone tell me what this expression denotes for bash sorting “sort -r -n -k5”
For a full explanation see this answer from a related question. In short you basically have to implement… – (NSComparisonResult)compare:(Contact *)otherContact; …in your Contact class (order of comparison: self, otherContact). NSComparisonResult has three possible values: NSOrderedAscending, NSOrderedSame and NSOrderedDescending. solved Sorting in Objective C [duplicate]
You could use sorted. The following solution works, provided the value of ‘id’ starts with a single character followed by numbers. sorted(b, key=lambda x: int(x[‘id’][1:])) 1 solved How to sort a list by dict values in Python? [closed]