[ad_1] As mentioned in the tutorial you shared: The reason we can use this shorter, simpler form_for declaration to stand in for either of the other forms is that @article is a resource corresponding to a full set of RESTful routes, and Rails is able to infer which URI and method to use. Also, from the reference given there: For … Read more
[ad_1] Can I invent my own HTTP Status Code for when an entity is updated and the server returns a representation of the updated entity? [ad_2] solved Can I invent my own HTTP Status Code for when an entity is updated and the server returns a representation of the updated entity?
[ad_1] you can sent json through Http post in cakephp <?php $data = array(‘Users’=>array(‘id’=>’1′,’username’=>’xyz’,’password’=>’pass’,’email’=>’[email protected]’,’age’=>’28’,’gender’=>’male’)); $url = “http://localhost/appname/Controllername/functionname”; $content = json_encode($data); $curl = curl_init($url); curl_setopt($curl, CURLOPT_RETURNTRANSFER, true); curl_setopt($curl, CURLOPT_POST, true); curl_setopt($curl, CURLOPT_POSTFIELDS, ‘data=”.$content); $json_response = curl_exec($curl); echo $json_response;?> 2 [ad_2] solved How to write REST web service in cakephp using Post ..? [closed]
[ad_1] It’s not possible to get variables from the URL as POST, you need to use GET. This is how they built it. POST variables are not accessible from the URL, its more secure, and are used for sending Usernames, Passwords. Refer this for more info. [ad_2] solved How to get variables using POST in … Read more
[ad_1] Spring Rest support is based on MVC and its not actual implementation of JAX-RS.If your application is already on spring and you don’t have any constraint to use Jersey,Spring Rest will make sense. JAX-RS is just specification and you can replace jersey with apache cxf or RestEasy. refer : Spring MVC and JAX-RS compliant … Read more
[ad_1] How can i create the correct JSON data in an Android app required for a Java Jax RS REST POST Api accepting a List of JSON Objects [ad_2] solved How can i create the correct JSON data in an Android app required for a Java Jax RS REST POST Api accepting a List of … Read more
[ad_1] The quotes in your query param seem to be causing the error at the server. Try something like this apiURL := “http://localhost:8080/api/history/resources/count” req, err := http.NewRequest(“GET”, apiURL, nil) if err != nil { log.Fatal(err) } apiParams := req.URL.Query() apiParams.Add(“startedAfter”, “2021-03-06T15:27:13.894415787+0200”) req.URL.RawQuery = apiParams.Encode() res, err := http.DefaultClient.Do(req) try that and revert. [ad_2] solved Getting … Read more
[ad_1] I think it is better store it in a database’s table. If you store it in a enum, when you add, change or delete a fruit you have to compile your code again. In case of change, you will have to update all places (tables columns) where this fruit’s name is store. In the … Read more
[ad_1] All frameworks are by definition slower than no-code as there’s more going on. i.e. <?php echo ‘metro’; is going to be much faster than a Slim application with this code: use \Slim\App; $config = include ‘Config/Container.php’; $app = new App($config); $app->get(‘/metro’, function($request, $response){ return $response->write(“metro”); }); $app->run(); This is because the Slim application is … Read more
[ad_1] The top level object in your JSON file is an array so: class letsRead { public static void main(String [] args) { String inline = “”; try { URL url = new URL(“https://gist.githubusercontent.com/anubhavshrimal/75f6183458db8c453306f93521e93d37/raw/f77e7598a8503f1f70528ae1cbf9f66755698a16/CountryCodes.json”); HttpURLConnection conn = (HttpURLConnection)url.openConnection(); conn.setRequestMethod(“GET”); conn.connect(); int responsecode = conn.getResponseCode(); System.out.println(“Response code is: ” +responsecode); if(responsecode != 200) throw new RuntimeException(“HttpResponseCode: … Read more
[ad_1] REST doesn’t care what spellings you use for your resource identifiers. See REST: I Don’t Think it Means What You Think it Does, by Stefan Tilkov (2014). The key idea: in REST, the client follows links provided by the server, rather than constructing links described in documentation. [ad_2] solved Is this path RESTful?
[ad_1] Solution is very simple – need to add: Database=myDataBase; to CONN_STR = ‘DRIVER=SQL Server Native Client 10.0;UID=user;PWD=pass;server=server;’ + ‘Trusted_Connection=No;MARS_Connection=yes’;Database=myDataBase; Thanks Arnaud for great framework!!! [ad_2] solved Delphi: What’s wrong with REST API based on mORMot?
[ad_1] You have created a WCF service, but this is not (necessarily) the same as a REST service. With your current configuration, your service is a SOAP service, which you are supposed to send messages to using a special XML format. The easiest way to communicate with it is to generate a service proxy, by … Read more
[ad_1] Need help on to design architecture\model for Message send\receive using RESTFul Webservice + JMSTemplates + MQSeries [ad_2] solved Need help on to design architecture\model for Message send\receive using RESTFul Webservice + JMSTemplates + MQSeries
[ad_1] This is how your Meta class should look like. public class Meta { private String uc; private String pip; private String lot; public String getUc() { return uc; } @XmlAttribute public void setUc(String uc) { this.uc = uc; } public String getPip() { return pip; } @XmlAttribute public void setPip(String pip) { this.pip = … Read more