You may use explode() to get it. $word= “who’s’who”; $results= array(); $parts = explode (“‘”, $word); foreach ($parts as $part) $results[$part]++; You then may output like: foreach ($results as $word => $count) echo $word . ” = ” . $count. “<br>”; The output should be: who = 2 s = 1 3 solved How to … Read more
There is NO such number that is less than 1900 and greater than 2020. Assuming instead you meant a number in the range 1900 <= x <= 2020, you can use the following regex: ^(19[0-9][0-9]|20[01][0-9]|2020)$ Demo solved Regex for a number in the range 1900 and 2020 [closed]
Are you looking for s/x([0-9a-fA-F]{1,5})/ chr hex $1 /eg 3 solved Regex , regular expression [closed]
Shouldn’t the a* match with the a in the string? No, because * means a can match zero or more times, so the ” empty string also matches that expression. That leaves ‘ad’ after the initial empty string to match for the remainder of the expression. A regex will consider both options here (both ”, … Read more
Simple: /^(?=.{8,32}$)(?=.*[a-z]).*\d/i (assuming you meant “letter” not “character”.) solved regex to check password consist of Character and Number [duplicate]
This should work 🙂 String num1 = mEtfirst.getText().toString(); char[] temp = num1.toCharArray(); int i=0; num1=””; while(Character.isDigit(temp[i])) num1=num1+Character.toString(temp[i++]); This converts the string to a character array, checks the array character by character, and stores it in num1 until a non-digit character is encountered. Edit: Also, if you want to convert num1 to an integer, use: num1=Integer.parseInt(num1); … Read more
Try with preg_replace_callback function in php. $ptn = “/_[a-z]?/”; $str = “kp_o_zmq_k”; $result = preg_replace_callback($ptn,”callbackhandler”,$str); // print the result echo $result; function callbackhandler($matches) { return strtoupper(ltrim($matches[0], “_”)); } 0 solved Converting all underscore connected letters to uppercase in php [closed]
If it is about the longest possible matching (sub)string, thus the most specific one, the task actually can be solved pretty easy. sort the array descending by each of its string-item’s length property. Iterate the array … for each string item, try whether it is included within the given text. Stop iterating with the first … Read more
If you are trying to parse single or double quoted strings, it should be done in two steps. Validation, then parse for values. You could probably do both in a single regex with the use of a \G anchor, validating with \A\G and parsing with just the \G. If you are sure its valid, you … Read more
This is hard to do with perl’s extended regular expressions, which are considerably more powerful than anything in C++. I suggest a different tack: First get rid of the things that don’t look like functions such as data (look for the D designator). Stuff like virtual thunk to this, virtual table for that, etc., will … Read more