Java possesses the function Math.random() which returns a number that varies between 0 and 1. Therefore, if you want a random number to vary between 0.5 and 1 only, you need to scale this number by half so that it only varies between 0 and 0.5, and then add this to the minimum value in … Read more
I’m assuming you meant “ten non-negative integers less than 60”. With possibility of repeats: my @rands = map { int(rand(60)) } 1..10; For example, $ perl -E’say join “,”, map { int(rand(60)) } 1..10;’ 0,28,6,49,26,19,56,32,56,16 <– 56 is repeated $ perl -E’say join “,”, map { int(rand(60)) } 1..10;’ 15,57,50,16,51,58,46,7,17,53 $ perl -E’say join “,”, … Read more
You can use random.choice() and do something like this: import random for i in range(4): # add 4 entries from l2 and l3 l.append(random.choice(l2)) l.append(random.choice(l3)) Hope this helps. 0 solved Adding and deleting random entries from a list inside another list in Python?
Create an array containing all your quotes Create a random number based on the current date, which goes from 0 to n (n being the amount of quotes in your array – 1) Show the item of the array which has the index of the random number created in step 2 Try to write code … Read more
You just need to use an if..else statement: function RandomID() { var value; var rnd = Math.floor(Math.random() * 11); if (rnd === 7) value = “Wassup”; else if (rnd <= 5) value = “Hello”; else value = rnd; document.getElementById(‘id’).value = value; } <button class=”button” onclick=”RandomID();” style=”font-family: sans-serif;”>RUN</button> <input class=”input” type=”text” id=”id” name=”id” size=”3″ readonly /> … Read more
You need to create a function and then return the output of the addition. A function which takes two arguments. def addition(number1, number2): return number1 + number2 number1 and number2 are the 2 arguments. Since you already have 2 numbers in your list you can pass them like this. print(addition(*randomlist)) The * unpacks the items … Read more
Java JDK sources are publicly available. If you want an exact equivalent of Java’s random number generator in C, go grab the sources and write/port it yourself. 3 solved Exact C equivalent of Java Random.nextInt(int bound) method
Using php and javascript I created 2 files. call.php – Retrieves a sentence from a database and prints one of them (Random) index.html – A page with a button that runs a function which retrieves a sentence from call.php call.php: <?php $db_host = “localhost”; //Host address (most likely localhost) $db_name = “DATABASE_NAME”; //Name of Database … Read more
you should move the srand function to the begin of main. if you call this function twice in the same second you will get the same numbers from random() also you should change RandNum = 2 + (rand() % 2); to RandNum = 1 + (rand() % 2); rand() % 2 will result in 0 … Read more
You must initialize finished to false if you want to enter the while, and after, when job is done set finished to true to exit the loop boolean finished = false; while (!finished) { // ↑ ↑ ↑ ↑ ↑ →→→→→→ this means loop while finished == false randomNumber1 = random.nextInt(size); randomNumber2 = random.nextInt(size); if … Read more
In the method h(), the while forms an infinite loop if the atk!=10. so you need to specify an exit condition there to break the loop; you can use like this: public void h() { while (Atk != 10) { this.Atk = random.Next(11); } Console.WriteLine(Atk); } Now you will get a random number between 0 … Read more
Generate a random integer between 0 and (the array size – 1), both inclusive. Access your array with an index equal to this random number. We can’t give you ready-to-use code unless you show some efforts in terms of your own code. 2 solved How would I print a random array element? [closed]
Why are you creating new instance of JButton in roll? You just need to change the icon of the buttons which are already displayed on the screen This… public void roll() { value = nextValue() ; if (value==1){ Icon i=new ImageIcon(getClass().getResource(“1.png”)); c= new JButton(i); add(c); } else if(value==2){ Icon im=new ImageIcon(getClass().getResource(“2.png”)); c= new JButton(im); add(c); … Read more
You are not using bubble sort. this is a selection sort algorithm and your code is not correct. I have updated the code for the bubble sort algorithm. #include <stdio.h> #include <stdlib.h> #include <time.h> int main() { int ctr, inner, outer, didSwap, temp; int nums[10]; time_t t; srand(time(&t)); for (ctr = 0; ctr < 10; … Read more
You can make an array of your string value and pick the random value from array. // String array like in below format. string [] stringArray = new [] {“A”, “B”, “C”, “D”, “E”, “F”}; // Make it accordingly int ramdomNum = random.Next(0, stringArray.Length); Console.Write(stringArray[ramdomNum]); Hope this will help you. solved How can I randomly … Read more