[ad_1] To summarize: The function prints out the first N numbers in the Fibonacci sequence. This is a sequence starting with 1, 1 and each following term is the sum of the two previous terms. a, b = b, a + b Here, you have 2 variables. a is always the current term and b … Read more
[ad_1] Yes it still exists Python 3.7.2 (tags/v3.7.2:9a3ffc0492, Dec 23 2018, 23:09:28) [MSC v.1916 64 bit (AMD64)] on win32 Type “help”, “copyright”, “credits” or “license()” for more information. >>> help(isinstance) Help on built-in function isinstance in module builtins: isinstance(obj, class_or_tuple, /) Return whether an object is an instance of a class or of a subclass … Read more
[ad_1] So from the sound of your question you are attempting to get a binary search working for your example. First, it is useful to know that a binary search only works reliably on sorted data. This is quite different than a standard linear search that will always find the value, regardless of order. As … Read more
[ad_1] From the question, it seems that you want to compute \sum_{i=1}^{n} 1/i If the input is 0, then returns 0. Remember that in a recursive function, you need to define a base case and an inductive clause. In your question, the inductive clause is: 1.0 / i + sum_of_reciprocals(i-1) while the base case can … Read more
[ad_1] Here is my answer to your assignment. I hope you get full marks. # This is a program that displays dimensions of a letter-size # sheet of paper in millimeters. WIDTH = 8.5 HEIGHT = 11 MILLIMETERS_IN_INCHES = 25.4 print(“The dimentions of a letter-size sheet of paper in millimeters is : {} x {}”, … Read more
[ad_1] There are cases when both isalpha and isdigit returns False, but isalnum returns True. So isalnum is not just a combination of the other two. >>> ‘a1’.isalpha(), ‘a1’.isdigit(), ‘a1’.isalnum() (False, False, True) [ad_2] solved Python: is isalnum() the same as isalpha with isdigit?
[ad_1] Option 1 You can nest numpy.where statements: org[‘LT’] = np.where(org[‘ID’].isin(ltlist_set), 1, np.where(org[‘ID2’].isin(ltlist_set), 2, 0)) Option 2 Alternatively, you can use pd.DataFrame.loc sequentially: org[‘LT’] = 0 # default value org.loc[org[‘ID2’].isin(ltlist_set), ‘LT’] = 2 org.loc[org[‘ID’].isin(ltlist_set), ‘LT’] = 1 Option 3 A third option is to use numpy.select: conditions = [org[‘ID’].isin(ltlist_set), org[‘ID2’].isin(ltlist_set)] values = [1, 2] org[‘LT’] … Read more
[ad_1] You can use the dict constructor d = dict(key1=val1, key2=val2) or __setitem__ method d = {} d[‘key1’] = val1 d[‘key2’] = val2 There are other, even more flexible ways, but those are the basics. [ad_2] solved Generate Dictionary in Python at run time [closed]
[ad_1] A correct version of you code – the problem was that you were having a bytes object instead of the str you probably expected. I added a .decode(‘utf-8’) to the content read from the website, and now the html is an str object. You recieved the error because you were working on a bytes … Read more
[ad_1] The issue is that your indentation is incorrect. By indentation I mean Leading whitespace (spaces and tabs) at the beginning of a logical line is used to compute the indentation level of the line, which in turn is used to determine the grouping of statements This link is helpful for you to see why … Read more
[ad_1] You could use a simple list comprehension here : S = [x[0] for x in content_E.most_common(3)] or, if you need to generate from E, then: S = [x[0] for x in E] 0 [ad_2] solved get most common keys from list
[ad_1] Using calendar built-in library, you can handle it like this: import calendar s_day = raw_input() days = list(calendar.day_name) # days.index(‘Saturday’) will print 5 print days.index(s_day) Like this, the raw input must be in the correct format. Such as ‘Monday’ not ‘MOnday’ [ad_2] solved Python – How to determine number of day of week given … Read more
[ad_1] You can use .isin() directly in pandas filtering – recent_indicators_filtered = recent_indicators[recent_indicators[‘CountryCode’].isin(developed_countries)] Also, you can come up with a boolean column that says True if developed – recent_indicators[‘Developed’] = recent_indicators[‘CountryCode’].isin(developed_countries) [ad_2] solved How to check whether data of a row is in list, inside of np.where()?
[ad_1] Just a small improvement based on your code to find limit primes instead of limit numbers. limit = 1000 def is_prime(n): for i in range(2, n): if n%i == 0: return False return True sum = 0 num = 2 for i in xrange(limit): while not is_prime(num): num += 1 sum += num num … Read more
[ad_1] Short answer is db.create_all(). Here is a piece of this answer app = Flask(__name__) app.config[‘SQLALCHEMY_DATABASE_URI’] = ‘postgresql+psycopg2://login:pass@localhost/flask_app’ db = SQLAlchemy(app) db.create_all() db.session.commit() [ad_2] solved sqlalchemy create tables [closed]