for sub in range(2,int(sqrt(num))+1) : if num % sub ==0 : flag = False break print num , # <<– this is inside the for loop and will be printed every iteration 1 solved What’s going wrong with this prime-number output?
Just split upon space(s) and take the 4th column: >>> s = “neighbor 10.1.1.1 route-map wred900_NWK out” >>> re.split(r”\s+”, s)[3] ‘wred900_NWK’ 1 solved Find and replace with Regex in Python [closed]
from pathlib import Path def count(filename: str, word = “hello”): file = Path(filename) text = file.read_text() lines_excluding_first = text.split(“\n”)[1:] counts = sum([sum(list(map(lambda y: 1 if word == y else 0, x.split(” “)))) for x in lines_excluding_first]) return counts Example: say you have a txt file like: sample.txt ———- this is the first line so this … Read more
Well, I got result that was need for me. I found him in another question from Stack Overflow: How to show graph in Visual Studio Code itself? Use #%% for creating cells in that you will run independent fragments of code. It seems like Python Shell(this is Jupyter Notebook that I love). Result that I … Read more
for i in range(0, len(A)): if A[i] > 30: print(“Value” + str(A[i]) + ” Index ” + str(i) + ” Table B Value ” + str(B[i]) ) 4 solved how to compare the list of numbers to a predefined value and output the index of that value
Before getting into any of this: As chepner pointed out in a comment, this input looks like, and therefore is probably intended to be, JSON. Which means you shouldn’t be parsing it with regular expressions; just parse it as JSON: >>> s=””‘ {“text”: “Love this series!\ufeff”, “time”: “Hace 11 horas”, “author”: “HasRah”, “cid”: “UgyvXmvSiMjuDrOQn-l4AaABAg”}”’ >>> … Read more
For what you are trying to do, a better method would be: import os def print_file_contents(file_path): assert os.path.exists(file_path), “File does not exist: {}”.format(file_path) with open(file_path) as f: print (f.read()) user_input = raw_input(“Enter a file path: “) # just input(…) in Python 3+ print_file_contents(user_input) solved Read and print a user selected file’s contents [closed]
The default recursion limit is 1000. >>> sys.getrecursionlimit() 1000 A program with a single recursive function will reach 999: start = 0 try: def recursion(): global start start += 1 recursion() recursion() except RecursionError: print(‘recursion :’, start, ‘times’) prints out recursion : 999 times Your program is creating a stack that has recursion(), then repeat(), … Read more
So there are two things: The assignment of s should be either with escaped back-slashes or as a raw string. I prefer the latter: s = r”C:\x\xxx\temp\downloads\test_dir\sql\my-ee.sql” you should use the search method instead of match to be content with a partial match. Then, you can use \\\\ in the regular expression, or – as … Read more
You’re returning early in the loop, you need to build up a string and return that. Either just return a joint string or build it up “”.join(chr(ord(s)+4) for s in pas) def cip(pas): ret_val = “” for i in pas: asci = ord(i) encryption = asci + 4 ret_val += chr(encryption) return ret_val solved It … Read more
To learn more about text processing in Python3 I recommend training on codingame.com. def removeDuplicates(inp): output =”” lastCharacter=”” for character in inp: output+=character*(character!=lastCharacter) lastCharacter=character return output inpTest =”AAABBCCDDAA” print(removeDuplicates(inpTest)) ABCDA 0 solved HOW TO REMOVE DUPLICATES IN A ROW IN PYTHON [closed]
When I enter a variable that is storing an object, it keeps returning the instance of that object rather than the list that I want it to solved When I enter a variable that is storing an object, it keeps returning the instance of that object rather than the list that I want it to
Yes, with itertools product , map and set: >>> from itertools import product >>> A={1,2,3} >>> B={4,5,6} >>> list(map(set, product(A, B))) [{1, 4}, {1, 5}, {1, 6}, {2, 4}, {2, 5}, {2, 6}, {3, 4}, {3, 5}, {3, 6}] 1 solved How to get the cartesian product between sets in python without using loops?
If you use the following code, response being your json: data = response[‘data’][‘students’] for student in data: print(‘{} {}:’.format(student[‘name’], student[‘lastname’])) for grade in student[‘grades’]: print(‘\t{} – {}’.format(grade[‘subject’], grade[‘score’])) This is what you’d get: Peter Henderson: math – A english – B Nick Simons: math – B english – C 0 solved how to read multiple … Read more
def f(x): if x == 1: return [] return [f(x-1)] print(f(5)) Output: [[[[[[]]]]]] 1 solved Python. List comprehension. List in the list and so on [closed]