The below code will pick up the first sub-list viz. [(468000,)] And extract its 0th element which is a tuple (468000,) Applying further indexing to it, the 0th element of the tuple will be extracted. za, zb, zc = [element[0][0] for element in z] Each element of the list will then be assigned to za, … Read more
I can see what you’re after although there is a big omission: What happens when the status has reached ‘Z’ and it is time to update? More on that later. Your request has 2 components, actually getting a process to run and a rolling update procedure (script) for the status. Well, Postgres has no native … Read more
choice.index(p1) == (choice.index(p2) + 1) is true when the position of p2 in the list is one more than the position of p1 in the list, i.e. p2 is right after p1 in the list. choice.index(p1) == (choice.index(p2) + 1) % 3 is the same thing, but it considers the start of the list to … Read more
The Python tutorial should explain all you need. If you want more resources, have a look at this recent thread on the Python mailing list. solved Looking for a good introduction to object oriented programming with Python [closed]
Your code should work. To check what is wrong, you could use this: def checksite(): #blahblah while True: print(‘starting’) checksite() print(‘site checked’) time.sleep(10) print(‘sleep function complete’) Then maybe you will get an idea of what is wrong. 3 solved Function doesn’t work in another function with sleep [closed]
Not sure what you mean with “store the data of ‘li1’ into an index”. I’m assuming you want a list of lists? You could append the list. k = “/BTC” result_list = [] for i in range(l): if k in dat1[“Data”][i][‘Label’]: value = dat1[“Data”][i][‘Label’] value1 = dat1[“Data”][i][‘TradePairId’] value2 = dat1[“Data”][i][‘AskPrice’] value3 = dat1[“Data”][i][‘BidPrice’] result_list.append([value, value1, … Read more
Literally write it as you would say it! >>> [‘a’ if i % 2 else ‘b’ for i in range(10)] [‘b’, ‘a’, ‘b’, ‘a’, ‘b’, ‘a’, ‘b’, ‘a’, ‘b’, ‘a’] 2 solved Creating a list that gives a specific value at even indexes and another value at odd indexes
x = SimpleClass() creates the instance of class (something like an object of this type). If you run it outside the loop, you have exactly one object and try to change it. simplelist.append(x) in this case will append this unique object to list (and will change it each time) so you will have a list … Read more
Here, you can try this one: summation = 0 with open(“test.txt”, “r”) as infile: for line in infile: newLine = line.split(“, “) summation = summation + int(newLine[3]) print(summation) Output: 3784 The contents of test.txt file are structured like this: [52639 – 2017-12-08 11:56:58,680] INFO main.master 251 Finished pre-smap protein tag (‘4h02′, [], 35000, 665, ’67’) … Read more
a = int(input()) b = int(input()) if a > b: for number in range(a,b+1): print(number) else: for c in range(b,a+1): print(c) solved a = int(input()) b = int(input()) if a > b: for number in range(a,b+1): print(number) else: for c in range(b,a+1): print(c)
You can do something like as follows. import numpy as np A = np.eye(3, 3) B = np.eye(3, 3, k=-1) B[B>0]=-1 C = A + B C[0, 0] = 0 print(C) Output: [[ 0. 0. 0.] [-1. 1. 0.] [ 0. -1. 1.]] solved python, change value of matrix eye [closed]
This is mass conversion to the older Excel 97-2003: import glob from win32com.client import Dispatch for file in glob.glob(‘/home/adam/*.xlsx’): xl = Dispatch(‘Excel.Application’) wb = xl.Workbooks.Add(file) wb.SaveAs(file[:-1], FileFormat=56) xl.Quit() 2 solved how to convert xlsx files to simple xls for a given folder
Problem solved. It turned out that my version of libpng was looking for the older version of zlib. I reinstalled(updated) libpng and things are working correctly now. solved Issue with loading python matplotlib
for your specific question, you can just use .isdigit() s = “abc 123 def 456″ for ch in s: if ch.isdigit(): print(ch, end=”) print() 5 solved How to extract integers from a random string without using regex? [closed]
this is a problem with indentation. try this: while True: print(“YOUTUBE SIMULATOR”) print(“1. search a video”) print(“2. edit video”) choice = int(input()) if choice == 1: print(“Searching video…”) print(“Can’t find your video!”) elif choice == 2: print(“Editing video…”) print(“Can’t edit your video?”) solved python program not working beacuse of the “if” [closed]