[ad_1] Create a set with the numbers that you need to delete and keep updating it while you read new lines. If the new line starts by one element in the set skip it and do not write it to the output file. to_delete = set() with open(‘input_file’, ‘r’) as input_file, open(‘output_file’, ‘w’) as output_file: … Read more
[ad_1] Try using ast.literal_eval: import ast s=”{(76034,0),(91316,0),(221981,768),(459889,0),(646088,0)}” print(dict(ast.literal_eval(‘[‘ + s.strip(‘{}’) + ‘]’))) Output: {76034: 0, 91316: 0, 221981: 768, 459889: 0, 646088: 0} [ad_2] solved Convert a string representation of a set of tuples to a dictionary [duplicate]
[ad_1] Ah I see your problem. this is really what i want to do. i want to add tt1 in another list but the thing is this just happen [0, [102, 0.5, 0.591, 0.529, 10, 42, 26, 6, 8, 17, 24], 1, 27, 109, 0.41100000000000003, 0.308, 0.818, 16, 48, 26, 13, 9, 9, 22 When … Read more
[ad_1] You are looking for the enumerate function: https://docs.python.org/2/library/functions.html#enumerate For instance: with open(“newfile.txt”, “w”) as output: for index, line in enumerate(open(“myfile.txt”)): output.write(“%d %s” % (index + 1, value)) 1 [ad_2] solved How can I use python to add index numbers for the data saved in the text file [duplicate]
[ad_1] At very simple i make this program for you as per your requirement that user must enter 10 numbers and program finds either it is prime or not. try this: for i in range(0, 10): num = int(input(‘Enter Number:’)) if num > 1: # check for factors for i in range(2, num): if (num … Read more
[ad_1] Surfaces doesn’t have an object for retrieving the file name, but maybe you could use another variable to hold the file name? #load images bg_filename = “start.png” background = pygame.image.load(bg_filename) #keep looping through while 1: #clear the screen before drawing it again screen.fill(0) #draw the screen elements screen.blit(background, (0,0)) #update the screen pygame.display.flip() #loop … Read more
[ad_1] Assuming that the count result applies to the whole file you can use a collections.Counter: from collections import Counter with open(‘input.tsv’) as infile: counts = Counter(infile.read()) for c in ‘SF’: print ‘{}: {}’.format(c, counts.get(c)) This has the advantage of allowing you to obtain counts of any character (not just “S” and “F”) with one … Read more
[ad_1] Maybe do some Exploratory data analysis first to see if you can figure out a pattern between your target variable and features? It would also be good to extract some features from your date/time variables rather than using them as integers (like weekday_or_not, seasons etc.) You can also try transforming your features (log, sqrt) … Read more
[ad_1] Use regex a=”HOW TO COOK RICE – Chapter 1: 1 rinse water once 2 add one and a half cup of water for every cup of rice 3 cover the pot and simmer” idx=[i.start() for i in re.finditer(‘(\d{1,} \w{1,})’, a)] if idx: print(a[:idx[0]]) else: print(a) for i,index in enumerate(idx): if not i==len(idx)-1: print(a[index:idx[i+1]]) else: … Read more
[ad_1] This is using glob rather than listdir, but this might be a possible method. No regular expressions involved here either though. import glob folder_path = “C:\Temp” file_pattern = “\*.txt” search_string = “hello” match_list = [] folder_contents = glob.glob(folder_path + file_pattern) for file in folder_contents: print(“Checking”, file) read_file = open(file, ‘rt’).read() if search_string in read_file: … Read more
[ad_1] GtkAda is also object-oriented, and so is any other high-level GUI toolkit I’ve seen so far, so I don’t think you can avoid object-oriented programming for the GUI, unless you use a more low-level approach. Two more low-level approaches are: An HTTP/HTML based interface. Using the X protocol to talk directly with an X … Read more
[ad_1] It took some effort, but here goes: from tkinter import * from tkinter.ttk import * def left_side(): “””Left “”” global left_entry, right_entry, answer_label, integer_combo left_entry.get() def right_side(): “””Right””” global left_entry, right_entry, answer_label, integer_combo right_entry.get() def combo_calc(): “””Combobox basic Calculator””” global left_entry, right_entry, answer_label, integer_combo if integer_combo.get() == “+”: answer_label[‘text’] = str(int(left_entry.get()) + int(right_entry.get())) elif … Read more
[ad_1] >>> import numpy as np >>> x = np.arange(-1,1,0.1) >>> print(x) [ -1.00000000e+00 -9.00000000e-01 -8.00000000e-01 -7.00000000e-01 -6.00000000e-01 -5.00000000e-01 -4.00000000e-01 -3.00000000e-01 -2.00000000e-01 -1.00000000e-01 -2.22044605e-16 1.00000000e-01 2.00000000e-01 3.00000000e-01 4.00000000e-01 5.00000000e-01 6.00000000e-01 7.00000000e-01 8.00000000e-01 9.00000000e-01] >>> type(x[0]) <type ‘numpy.float64’> >>> print(x.tolist()) [-1.0, -0.9, -0.8, -0.7000000000000001, -0.6000000000000001, -0.5000000000000001, -0.40000000000000013, -0.30000000000000016, -0.20000000000000018, -0.1000000000000002, -2.220446049250313e-16, 0.09999999999999964, 0.19999999999999973, 0.2999999999999998, 0.3999999999999997, 0.49999999999999956, … Read more
[ad_1] The simplest way, assuming you do not wish to go further down in the tree is: import os filepaths = [] iterdir = os.scandir(path_of_target_dir) for entry in iterdir: filepaths.append(entry.path) Update: A list comprehension makes is faster and more compact: (Strongly Recommended) import os iterdir = os.scandir(path_of_target_dir) filepaths = [entry.path for entry in iterdir] If … Read more
[ad_1] list_sum_recursive doesn’t return a list; it returns the sum of the values in its argument: list_sum_recursive([]) == 0 list_sum_rescursive([1]) == 1 + list_sum_recursive([]) == 1 + 0 == 1 list_sum_rescursive([1, 2]) == 1 + list_sum_recursive([2]) == 1 + (2 + list_sum_recursive([])) == 1 + (2 + 0) == 1 + 2 == 3 If … Read more