Try this one: counter = 0 while Amzn > 1000: counter+=1 print(“Watch”) Amzn = Amzn – (Amzn*.0103) else: print(“buy”) print(counter) 1 solved How can I count the outputs of a while loop in python? [duplicate]
Just make it so that it appends “s” unless the word ends with “y” or some other exception: def plural(word): wordlist = [] for char in word: wordlist.append(char) if word[len(word)-1] == “y”: wordlist[len(word)-1] = “ies” else: wordlist.append(“s”) word = “” for i in wordlist: word+=i return word print(plural(“STRING”)) solved Need a Python program Singular to … Read more
Assuming that you have a string with multiple instances of the same delimiter and you want to split at the nth delimiter, ignoring the others. Here’s a solution using just split and join, without complicated regular expressions. This might be a bit easier to adapt to other delimiters and particularly other values of n. def … Read more
You can just add, while computer1 in GuessList: computer1 = randint(0, 5) After your computer1 = randint(0, 5). You might have to remove your GuessList = [ ] because that will reset your GuessList each time. Instead, you should have that at the very start of your code and leave the append statement. Or you … Read more
You don’t show much effort to let us help you solving this. But since I’m learning bash scripting, I took your question as practicing. So… here is a bash script to rename duplicated files. /!\ The renamed files will be in the folder of first argument. So, in your case, you’ll have to launch it … Read more
EDIT: to drop the end of the string starting from the character before the underscore, but preserving the extension you can use a regex: import re s = “ABC_Y6N02.20.0025D_BF3DAC.tgz.bin” print( re.sub(r”^(.*)[^_]_[^\.]*(\.tgz\.bin)$”, r”\1\2″,s ).lower()) returns abc_y6n02.20.0025.tgz.bin 1 solved Removing a substring from a string in python
Here is a function that works fine for all cases and return the list of all first candidates encountered if no choice can be made to separate them. def find_best(list_of_lists): i = 0 while len(list_of_lists[i]) == 0: i+=1 list_containing_candidates = list_of_lists[i][:] if len(list_containing_candidates) == 1 : return list_containing_candidates[0] else: if i+1 < len(list_of_lists): for next_list … Read more
Using no external modules and only the count, although there would be some redundancy using dict comprehension: d = {itm:L.count(itm) for itm in set(L)} If you are allowed to use external modules and do not need to implement everything on your own, you could use Python’s defaultdict which is delivered through the collections module: #!/usr/bin/env … Read more
I believe this does what you want… arr = [[2,6,8],[1,4,7],[3,3,4],[2,4,9],[3,3,7]] foo = lambda arr, evenOdd, noDoubles: [ i for i in arr if not (evenOdd and (all(k % 2 == 1 for k in i) or all(k%2 == 0 for k in i))) and not (noDoubles and (len(i) != len(set(i))))] print(foo(arr, False, False)) print(foo(arr, True, … Read more
The way I see it, your code would be O(n) if it wasn’t for the a.pop(0) part. Since lists are implemented as arrays in memory, removing an element at the top means that all elements in the array need to moved as well. So removing from a list is O(n). You do that in a … Read more
A C struct can be packed into flat binary data, which is what Python 2 calls a string. The struct module lets you take a string that represents one of these C structs, and “unpack” it into a Python data structure. To do so you call struct.unpack. You need to specify a format string (as … Read more
You could do something like this: fragen = [‘List all the planets in our solar system!’, ‘List all countries in the European Union!’, ‘List all DAX companies!’] antwortsätze = [{‘Merkur’, ‘Venus’, ‘Erde’, ‘Mars’}, {‘Belgien’, ‘Bulgarien’, ‘Deutschland’, ‘Frankreich’}, {‘Adidas’, ‘Airbus’, ‘Allianz’, ‘BASF’}] for frage, antworten in zip(fragen, antwortsätze): antwortenx = set() richtige = 0 versuche = … Read more
You can split the string , then convert each elements to int – >>> s=”12 14 17″ >>> list(map(int,s.split())) [12, 14, 17] >>> solved How to convert a string filled with numbers to seperate integers in a list? [duplicate]
https://opendata.cityofnewyork.us/data/ Publicly available datasets are available, in xlsx format, that detail current zoning, events, shops, registrations, etc. for the city in the link above. import pandas as pd df = pd.read_excel (r’Path where the Excel file is stored\File name.xlsx’, sheet_name=”your Excel sheet name”) Utilize Pandas as an alternative for importing your data into Python. solved … Read more
for key,value in data.items(): if key == “members”: for key1,value1 in value[0].items(): print(value1) solved Read array inside json in python [closed]