Here’s something: import turtle delay = 0.1 # For the mainloop count = 0 # To track when a second past score = 0 # The score count pen = turtle.Turtle(visible=False) # The turtle which will write the score pen.penup() pen.goto(0,200) pen.write(‘Score: {}’.format(score),align=’center’,font=(‘Arial’,10,’bold’)) while True: # Main game loop time.sleep(delay) # 1 frame per 0.1 … Read more
I think you are confusing lists with dicts. The keys of your items dict are ‘coke’, ‘mars’, ‘fanta’, etc. and that is how you access it like items[‘coke’]. To iterate the items, something like this is more usual: >>> def list_items(): … for k,v in items.items(): … print(“{}: {}”.format(k, v)) … >>> list_items() coke: 1.50 … Read more
As suggested in comments, you could use itertools.groupby to subdivide the tuple into “not a separator” and “separator” groups and then pick those groups that are not separators. This works for arbitrary numbers of segments, but can also be unpacked into two variables if you know to have exactly two groups. >>> a = (‘a’, … Read more
>>> from __future__ import division … … result = [] … text = “20 7/8 16 1/4” … for num in text.split(): … try: … numerator, denominator = (int(a) for a in num.split(“https://stackoverflow.com/”)) … result.append(numerator / denominator) … except ValueError: … result.append(int(num)) … >>> result [20, 0.875, 16, 0.25] 2 solved How to convert a … Read more
Your attempt was pretty close to correct. The problem is the + ‘\n’. You don’t want to write a newline after every single input character. Any newlines in the input will be read and written to the output; that’s probably what you want. import sys ch = sys.stdin.read(1) while (len(ch)>0): sys.stdout.write(ch) ch = sys.stdin.read(1) You … Read more
Let’s start from the middle of this expression. ‘3’ * 2 evaluates to ’33’. This is because multiplication of a str object by a int object results in concatenating string with itself n times (providing you are multiplying by n). int(’33’) is just 33 as an integer. When you feed int class a string it … Read more
after converting to datetime pd.to_datetime(df[‘date’]) you can create a separate column with the hour in it, e.g. df[‘Hour’] = df.date.dt.hour and then sort by it df.sort_values(‘Hour’) EDIT: As you want to sort by time you can instead of using hour, put the timestamp part into a ‘time’ column. In order to get times between 9 … Read more
A dictionary maps strings to values. An array maps integers to values. That is about it! So, seriously: in the end, both data structures map a “key set” to values. For dictionaries, the keys can of (almost) arbitrary type, without any constraint on them (besides being “hash able”). Whereas an array maps a consecutive range … Read more
First of all, this is neither a string nor a list, but a tuple, as indicated by the round brackets. split is a method of the str class, so it can’t be used here. To convert a tuple t into a list, simply do list_1 = list(t) 4 solved How do you explicitly convert a … Read more
You are leaving open the possibility that age >= 8 but grade < 3 in which you have no control flow to handle. You can correct this succinctly with an and statement age = float(raw_input(“Enter your age: “)) grade = int(raw_input(“Enter your grade: “)) if age >= 8 and grade >= 3: print “You can … Read more
You need to call the method: month.lower() == ‘march’ The method is an object too, and without calling it you are comparing that method with a string. They’ll never be equal: >>> month=”January” >>> month.lower <built-in method lower of str object at 0x100760c30> >>> month.lower == ‘January’ False >>> month.lower == ‘january’ False >>> month.lower() … Read more
You have to do the conversion of integer values to string, before using .join(…). list1[6] = str(counter) 0 solved Python join a list of strings
map does a delayed execution, so when you cast the result to a list, the map is executed, which amounts in computing sum(1), sum(2), sum(-3) and sum(4) Any of those will fail because sum takes something like a list (an iterable object) in input. You pass integers which are not iterable, hence the error message. … Read more
Try adding adding an if parameter to check if its the desired item that your looking for, then just record all of its information. import json with open(‘elements.json’) as f: data = json.load(f) choice = input(“Choose element: “) for element in data[‘Elements’]: if element[‘name’] == choice: for x, y in element.items(): print(x.title() + “-> ” … Read more
Input function receives string as argument. String needs to passed on double quotes. If you’re not using double quotes, it will be treated as variable. So use myName = input() or myName = input(“Enter your name”) While running system will ask for the input at that time you can enter your name 0 solved First … Read more