In this code on each for iteration doing like below: temp = last last = now now = max(temp + i, now) so this code in c++ actually looks like: last = 0; now = 0; for (int i = 0; i < num.length; i++) { temp = last; last = now; now = max(temp … Read more
Supposing you want to be able to match *.swiss.ch domains and addresses: import re preg = re.compile(r'([^\.]+)\.swiss\.ch’) 5 solved Convert perl regex to python [closed]
Your indentation is all over the place – indentation should be in 4 white space blocks, and if and else statements should line up. A guide to python styling – http://legacy.python.org/dev/peps/pep-0008/#code-lay-out if os.path.isfile(‘number.txt’): print(‘ESISTE’) f = open(‘number.txt’, ‘r’) data = f.read() f.close() listOfNumber = data[0:12] if jid[0:12] in listOfNumber: print(“PRESENTE”) else: print(“DA INSERIRE”) numberAndMessage = … Read more
You can try something like this without importing any module : s1=’appleandgold’ s2=’appleblue’ track=[] for k in range(len(s1)): if k!=0: for ka in range(0,len(s1),k): if s1[ka:ka+k] in s2: track.append((len(s1[ka:ka+k]),s1[ka:ka+k])) print(max(track)[1]) output: apple solved String intersection in Python
As simple as that: word = input(“Enter a word: “) print(“***”) for letter in word: print(letter) print(“***”) 0 solved How to print out the letters of a word, one on each line, with three asterisks before and after the word
dictionaries are unordered (well pre 3.6 at least), instead sort the items d = {3: ‘__init__’, 5: ‘other’, 7: ‘hey ‘, 11: ‘hey’} print(sorted(d.items(),key=lambda item:(item[0].strip(),item[1]))) # output => [(3, ‘__init__’), (7, ‘hey ‘), (11, ‘hey’), (5, ‘other’)] if you really want it as a dict (for reasons i cant fathom) and you are using 3.6+ … Read more
What you receive when you load json data, is native Python Dict, or List. When you’re iterating over a list of dictionaries as you do here, data is a dict. To extract a value from a dict, you need to look up the key by its name, in your instance: ‘minecraft.net’, ‘session.minecraft.net’, ‘account.mojang.com’, … Python … Read more
list = [1,2,3,4,5,6] for x in range(len(list)): if list[x] % 3 == 0: list[x] = list[x]**2 print(list) solved How to divide specific elements in a list and then square the values? [closed]
This can be done by simply parsing the file line by line and checking if the current asset is the same as the previous one. First, let us store the assets and tags in a list inside transformed_data, to access tags easily, like so: [ [ asset1, tag1 ], [ asset2, tag2 ], … ] … Read more
As Scott said, result is defined inside the flip function. I haven’t really used async before, but probably this will work for you. Take out the return statement Tab the following lines. elif message.content.startswith(config.prefix + ‘coinflip’): result = random.randint(0, 1) if result == 1: print(‘Heads!’) await client.send_message(message.channel, content=”Heads!”) else: print(‘Tails!’) await client.send_message(message.channel, content=”Tails!”) 1 solved … Read more
I think this is what you mean. a = [1, 1, 2, 2, 3, 3, 4, 4, 5, 5] b = [1, 2, 3, 4, 5] for x in a: for y in b: if a[x] == b[y]: #Do stuff here print “found a match ” + str(a[x]) elif y == len(b) – 1: break … Read more
MySQLdb (the native driver for MySQL) is not compatible with Python3 yet; but the driver from Oracle for MySQL, called MySQL Connector/Python is compatible with Python 3. You should use the Oracle driver. django works with both. Once you have the driver installed, follow the connection section in the documentation. 1 solved Django 1.6.1 + … Read more
When you iterate through a list in Python, any modifications to the list you are iterating through will have an effect on the for loop. For example, take this code: my_list = list() my_list.append(“hello”) for element in my_list: my_list.append(“hello”) This code will run forever, because my_list keeps growing in size. With your code, you have … Read more
I forgot almost everything about bash scripting. but I think you can do something like this. files=(file1 file2 file3 file4) for i in `seq 4` do j=$(($i-1)) f[$j]=`cat ./temp/${files[$i]} | awk ‘{print $2}’ ` done for i in `seq 0 1799` do sum=0 rowValue=0 for j in `seq 0 3` do fileContent=(${f[$j]}) rowValue=`echo ${fileContent[$i]} ` … Read more
Firstly, you can simply write while True: Instead of a = True while a: Secondly, you don’t use total or t anywhere. You can delete them. Thirdly, if x has to belong to [a, b], you can write if a <= x <= b: Fourthly, you can use else statement instead of negation of if. … Read more