A simple while loop works, just make sure you divide the number by 2, otherwise you’ll get the NEXT power of 2. def function(number): x = 1 while x <= number: x *= 2 return x / 2 solved Defining function with an argument, employs while loop and returns largest power of 2 that is … Read more
If you can get it to print out one row of random numbers, you are almost there. The piece that you are missing is this: as you are running the loop that prints out the numbers, keep track of a counter (starting from 1). After each time a number is printed, check counter % 6. … Read more
You can make count global: count = 0 def intro(start): if start == “yes” or start == “y”: print(“Lets begin.”) else: print(“Thanks for checking it out! Bye Bye!”) def question1(): global count count += 1 return count def question2(): global count count += 1 return count def main(): print(“Hello There! Welcome to an all new … Read more
Something doesn’t add up (no pun intended) here: full_cost = sum([int(product[‘product_cost’]) for product in cart_products ]) TypeError: string indices must be integers When the product_cart in your question is supplied as the input to this it should work. However if you had a string as a member of the product_cart list, instead of a dictionary … Read more
d = [{‘A’: [3, 45, 34, 4, 2, 5, 94, 2139, 230345, 283047, 230847]}, {‘B’: [92374, 324, 345, 345, 45879, 34857987, 3457938457]}, {‘C’: [23874923874987, 2347]}] [{x.keys()[0]:sum(x.values()[0])} for x in d] solved I have a very big list of dictionaries and I want to sum the insides
I’m not sure I completely understand what you’re trying to do, but I’ll give it a shot since you seem to have asked this question many times already (which usually isn’t a good idea). I believe that there’s a lack of clarity in your question – it would help a lot if you could clarify … Read more
UUID is not a number but you can generate a new UUID simple import uuid from django.db import models # Create your models here. def get_next(): return uuid.uuid4() class Users(models.Model): id = models.UUIDField(primary_key=True, default=get_next, editable=False) sex = models.CharField(max_length=100, null=True, default=None) age = models.CharField(max_length=100, null=True, default=None) By default Django will store Integer Primary keys. In order … Read more
The format of the input file depends on the extension that you use, a .txt file will be a Tab Separated Values (tsv) file while a .csv file will be a Comma Separated Values (csv) file (please note that this is not a general convention, it is something that was decided by that colleague of … Read more
A sample code to copy text from one file to another. Maybe it will help you: inputFile = open(“Input.txt”,”r”) text = inputFile.read() inputFile.close() outputFile = open(“Output.txt”,”w”) outputFile.write(text) outputFile.close() solved How do I get Python to read and extract words from a text file? [duplicate]
try this def reverse_besides_number(l): # convert number in list to a dict # record the index d = {k: v for k, v in enumerate(l) if v.isdigit()} # record the character in list c = [i for i in l if not i.isdigit()] c.reverse() # insert for key, value in d.items(): c.insert(key, value) return c … Read more
Wanted solution using regex, here you are: >>> import re >>> s = “StringText someText Wwwwww SomeOtherText OtherText SOMETextMore etc etc etc” >>> def replacement(match): … return match.group(1).lower() >>> re.sub(r'([sS]\w+)’, replacement, s) ‘stringtext sometext Wwwwww someothertext OtherText sometextmore etc etc etc’ 10 solved Python re: how to lowercase some words [closed]
You can use urllib2 and socket module for the task. import socket from urllib2 import urlopen, URLError, HTTPError socket.setdefaulttimeout( 23 ) # timeout in seconds url=”http://google.com/” try : response = urlopen( url ) except HTTPError, e: print ‘The server couldn\’t fulfill the request. Reason:’, str(e.code) except URLError, e: print ‘We failed to reach a server. … Read more
Solution is simple: i = 0 total = 0 while i < len(my_list): total += my_list[i] average = total / len(my_list) i += 1 solved Using a while loop instead of a for loop in Python [closed]
If the key argument is in switcher, the .get() method returns the value for the key. If the key is not in the dictionary, the method returns the optional “nothing”. def numbers_to_strings(argument): switcher = {0: “zero”, 1: “one”, 2: “two”} return switcher.get(argument, “nothing”) Calling the above function with a key that is in the dictionary: … Read more
Something like this? string = “AABBCCCASSDSFGDFGHDGHRTFBFIDHFDUFGHSIFUGEGFGNODN” for n in range(len(string)-15): print(string[n:n+16]) You have to iterate over every character up to the last character that has 16 characters after it (so the length of the string, minus 15 (because indexing starts at 0) : len(string)-15), and then print the string sliced at that starting index up … Read more