Two things regarding the mapping: There’s an address field there that’s not found in your actual documents. Remove it. Your dates should be mapped correctly using the date datatype. A correct mapping would look like this: { “properties”:{ “end_date”:{ “type”:”date”, “format”:”yyyy-MM-dd” }, “start_date”:{ “type”:”date”, “format”:”yyyy-MM-dd” }, //…other properties } } Once you get the mapping … Read more
Based on your update on what bid_data contains: Do: int(bid_data[6].split(‘:’)[1].strip()) # returns an integer Explanation: The Python string method strip() removes excess whitespace from both ends of a string (without arguments) Original below: Below is based on using the input you gave, [‘Quantity Required’, ‘ 1’], to get the output of 1 If the input … Read more
If RESULTHAZARD is 2, RESULTHAZARD == 2 or 3 evaluates to True or 3 which evaluates to True. Otherwise, RESULTHAZARD == 2 or 3 evaluates to False or 3 which evaluates to 3, which is a truthy value. You need to explicitly compare both for equality. Either with RESULTHAZARD == 2 or RESULTHAZARD == 3, … Read more
The problem is your function searched() in the script-tag. If you have for example following name-instances: [ { ‘First’: ‘foo’, ‘Last’: ‘bar’, }, { ‘First’: ‘foobar’, ‘Last’: ‘barfoo’, } ] So your rendered if–else in the function would look like this: function searched(){ nameSearched = document.getElementById(‘name’).value; if (“foo” == nameSearched) { … } else { … Read more
You Can use pd.read_html for this. import pandas as pd Data = pd.read_html(r’https://www.boxofficemojo.com/chart/top_lifetime_gross/’) for data in Data: data.to_csv(‘Data.csv’, ‘,’) 2.Using Bs4 import pandas as pd from bs4 import BeautifulSoup import requests URL = r’https://www.boxofficemojo.com/chart/top_lifetime_gross/’ print(‘\n>> Exctracting Data using Beautiful Soup for :’+ URL) try: res = requests.get(URL) except Exception as e: print(repr(e)) print(‘\n<> URL present … Read more
originalString = ‘bpy.types.object.location.* std:label -1 editors/3dview/object/properties/transforms.html#bpy-types-object-location Transform Properties’ # this separates your string by spaces split = originalString.split(‘ ‘) # first element is ready to go! first_element = split[0] # ‘bpy.types.object.location.*’ # second element needs to be cut at “#” second_element = split[3] second_element = second_element[:second_element.find(‘#’)] # editors/3dview/object/properties/transforms.html # now you have your desired output … Read more
This is pretty straightforward: num = int(input(“Input a number: “)) 5 solved Asking user for input – prime number code [duplicate]
You check for the empty line after appending the splitted line to data. .split() on an empty line returns an empty list. x[0] on an empty list produces an IndexError. data +=[line.split()] # equal to data.append([]) if line ==”: ips=[ x[0] # Access to the first element of every list in data. for x in … Read more
It is not entirely clear what the conditions are. Based on your comments I think you look for the following regex: r”Профессиональная ГИС \”Панорама\” \(версия 12(\.\d+){2,}, для платформы \”x(32|64)\”\)” This will match any sequence of dots and numbers after the 12. (so for instance 12.4.51.3.002 is allowed), and furthermore both x64 and x32 are allowed … Read more
If you want to get the results of every iterations of a for loop into a list, you need a list to store the values at each iteration. import ipaddress user_input = input(“”) network = ipaddress.IPv4Network(user_input) ipaddresses = [] #initiate an empty list for i in network.hosts(): ipaddresses.append(i) print(ipaddresses) solved How to catch all the … Read more
The fact that the ids were the same implies that they are pointing on the same object. String in Python is immutable, you can’t assign to it’s indexes values. Immutability means that we can change the original object: # List is mutable l = [1, 2, 3] # That’s OK l[0] = 5 # String … Read more
One of the shortest way would be to prepare a list/set of all the keys from all the dictionaries and call that key on all the dictionary in the list. list_of_dict = [{‘a’: 1, ‘b’: 2, ‘c’: 3}, {‘a’: 3, ‘b’: 5}, {‘k’: 5, ‘j’: 5}, {‘a’: 3, ‘k’: 5, ‘d’: 4}, {‘a’: 3}] # … Read more
Your example input/output suggests that you are looking for a power set. You could generate a power set for a string using itertools module in Python: from itertools import chain, combinations def powerset(iterable): “powerset([1,2,3]) –> () (1,) (2,) (3,) (1,2) (1,3) (2,3) (1,2,3)” s = list(iterable) return chain.from_iterable(combinations(s, r) for r in range(len(s)+1)) print(list(map(”.join, powerset(‘abcd’)))) … Read more
I will suggest that you use nested/inner functions as shown below to solve you problem. This allows you to compute the result using integers, and then convert the result to a string, or any other type, before returning it. def binary(n): def inner(m): if m>0: return inner(m//2)*10 + (m%2) else: return 0 return str(inner(n)) Alternatively … Read more
You can try this way : list1=[[‘in’, ‘comparison’, ‘to’, ‘dogs’, ‘,’, ‘cats’, ‘have’, ‘not’, ‘undergone’, ‘major’, ‘changes’, ‘during’, ‘the’, ‘domestication’, ‘process’, ‘.’], [‘as’, ‘cat’, ‘simply’, ‘catenates’, ‘streams’, ‘of’, ‘bytes’, ‘,’, ‘it’, ‘can’, ‘be’, ‘also’, ‘used’, ‘to’, ‘concatenate’, ‘binary’, ‘files’, ‘,’, ‘where’, ‘it’, ‘will’, ‘just’, ‘concatenate’, ‘sequence’, ‘of’, ‘bytes’, ‘.’], [‘a’, ‘common’, ‘interactive’, ‘use’, ‘of’, ‘cat’, … Read more